x square 8x 9 0 with method .

Updated on number 2024-05-12
10 answers
  1. Anonymous users2024-02-10

    a) x 2 + 2x + k + 1 = 0

    x+1)^2=-k

    Because (x+1) 2 is greater than or equal to 0

    However, this problem has two real roots, so it cannot be equal to 0

    So -k is greater than 0

    then k is less than 0 two).

    According to the relevant links.

    a=1 b=2 c=k+1

    then x1+x2=-(2 1)=-2

    x1*x2=(k+1)/1=k+1

    Bring in inequalities.

    2-(k+1) is less than -1

    k+3 is greater than 1

    k is greater than -2

    Criss-cross method.

    All unary quadratic equations can be converted into this equation representation.

    a*b)x^2+cx+(d*f)=0

    Criss-cross. a d

    a*f+b*d=c (note: each item must be preceded by a plus sign) b f the original equation can be changed.

    ax-d)*(bx-f)=0

    For example, example questions. x 2 + 8x - 9 = 0.

    a*b=1*1

    c=8d*f= -9=-1*9

    1*(-1)+1*9=c c is exactly equal to 8 (note: each item must be preceded by a plus sign) The original equation becomes.

    1x+(-1))*1x+9)=0

    x-1)*(x+9)=0

    x=1 or x=-9.

  2. Anonymous users2024-02-09

    The square of 2x - 8x=0 is solved as x=0 or x=4.

    Matching method: 2x 8x=0

    x ² 4x=0

    x ²-4x+4=4

    x-2) ²=4

    x-2=±2

    x=0 or x=4

    Properties: In elementary algebra, a collocation method is a method used to reduce a quadratic polynomial to the sum of the squares of a primary polynomial and a constant. This method is to polynomialize the following forms to the coefficients a, b, c, d, and e in the above expression, which can also be expressions themselves and can contain variables other than x.

    The colocation method is usually used to derive the root finding formula for a quadratic equation: the purpose is to square the left side of the equation perfectly. Since the perfect square in the problem has the form of (x + y)2 = x2 + 2xy + y2, 2xy = (b a)x can be deduced, so y = b 2a.

    Add y2 = (b 2a)2 to both sides of the equation.

  3. Anonymous users2024-02-08

    2x²-8x=0

    Solution: 2x(x-4)=0

    x=0 or x-4=0

    x=0 or x=4

    This problem does not need a matching method, and it can be solved by directly extracting the common factor.

  4. Anonymous users2024-02-07

    Divide both sides of the equation by 2 at the same time, that is, x -4x=0, and add 4 to both sides to get x -4x+4=4, that is, (x-2) = 4, and open at the same time, so x-2 = 2, and the solution is x=4 or x=0.

  5. Anonymous users2024-02-06

    x" + 10x + 9 = 0 x" + 10x + 25 - 16 = 0 ( x + 5 )" - 4"= 0 ( x + 5 - 4 )(x + 5 + 4 ) = 0 ( x + 1 )(x + 9 ) = 0 Solve the equation to get x1 = -1 x2 = -9 if x"+ 10x = 9, which is x"+ 10x - 9 = 0 same x" + 10x + 25 - 34 = 0 ( x + 5 )" - 34 )"= 0 ( x + 5 + 34 )(x + 5 - 34 ) = 0 Solve the equation to get x1 = -5 - 34 x2 = -5 + 34

  6. Anonymous users2024-02-05

    x Lingmo +10x+9=0

    x��+10x+25-25+9=0

    x+5) Potato finger =25-9

    x+5) ruler hand bucket =16

    x+5=±4

    x=-1 or x=-9

    Give a five-star review!

  7. Anonymous users2024-02-04

    Matching method. x^2-9x+8=0

    x-9 pei 2) 2 =81 nano zhongyan 4 -8x-9 2) 2 = 49 4

    x-9 Cave 2 = 7 2 or -7 2x=8 or 1

  8. Anonymous users2024-02-03

    x's square acre is -12x-9=0

    x^2-12x+36=45

    x-6)^2=45

    x-6=±3√5

    x=6±3√5

  9. Anonymous users2024-02-02

    4x square - x-9 = 0 (2x-1 socks 4) squared = 9 + 1 answer: 16 (2x-1 4) = 145 under the positive and negative root number 42x = 145 under the positive and negative root number 4+1 4x = (145 + 1 under the positive and negative root number) 8

  10. Anonymous users2024-02-01

    Summary. 8x square + 12x + 4 = 0 matching method.

    I've figured out how to match, and that's what he ended up with. 8( x+1/2)( x+1)=0

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