What is the mass ratio of the sulfur element in sulfur dioxide and sulfur trioxide of the same mass

set, the same mass of sulfur dioxide.

and sulfur trioxide for 100g

The S content of 100g of sulfur dioxide is: 100g*32 (32+16*2)*100%=50g

The S content of 100g of sulfur trioxide is: 100g*32 (32+16*3)*100%=40g

For the same mass of sulfur dioxide and sulfur trioxide, the mass ratio of sulfur elements is 50:40=5:4

Let the mass of SO2 and SO3 be m

SO2 relative molecular mass = 64, SO3 relative molecular mass bridge resistance = 80, so the S mass in SO2 = M 64*32 = S mass in SO3 = M 80*32 = So in sulfur dioxide and sulfur trioxide with the same mass, the elemental mass ratio of sulfur is = 5:4

The same Exciting Fiber Ming imitation quality is set into a shooting studio 1g

Mass of aerobic elements in SO2 1x32 64=

SO3 has 1x48 80=

So it's 5:6

Let the mass w, w g of sulfur dioxide amount = w 64;w g of sulfur trioxide amount of substance = w 80

The number of molecules = the amount of matter * Avogadotrondro's constant, so the ratio of the number of molecules is the ratio of the amount of matter.

The ratio of the number of molecules of sulfur dioxide to sulfur trioxide = w 64:w 80 = 5:4

Summary. The answer is 1:2, both sulfur trioxide and sulfur dioxide contain one sulfur atom, so if the ratio of sulfur element is 2:

5, then there are two sulfur trioxide and five sulfur dioxide, so the mass ratio is (2 80) :(5 64) 160:320 1:

2. If the ratio of the mass of sulfur elements contained in sulfur trioxide and sulfur dioxide is 2 5, the mass of sulfur trioxide and sulfur dioxide is 2.

The answer is 1:2, both sulfur trioxide and sulfur dioxide contain one sulfur atom, so if the ratio of sulfur elements is 2:5, then there are two sulfur trioxide and 5 sulfur dioxide, so the mass ratio is (2 80):

Rotten Jane 5 64) 160:320 Randolph 1:2

Extension] If the mass ratio of the same element in two compounds is known, the mass ratio of the two compounds can be found by the following steps: Suppose the two compounds are compound A and compound B, respectively, and the mass ratio of the same element is a:b.

Since the total amount of the same element in the compound is equal, assuming that the mass of the same element in compound A is A1 and the mass of the same element in compound B is B1, there is the following relationship: a1 b1=a b calculates the number of moles of the same element in compound A and compound B respectively based on the stoichiometric relationship. Assuming that the molar mass of this element is m, there is the following relation:

The molar mass of compound A and compound B is calculated according to the molar number of the same element in compound A = n1 = m * A1 according to the molar number of the same element. Assuming that the molar mass of compound A is ma and the molar mass of compound B is mb, there is the following relationship: molar mass of compound A = ma = n1 m molar mass of compound B = mb = n2 m Finally, calculate their mass ratio based on the molar mass of chemosensitive woods.

Assuming that the mass of compound A is wa and the mass of compound B is wb, then there is the following relationship: the mass ratio of compound A and compound B = wa wb = ma mb According to the bridge or the above steps, the mass ratio of the two compounds can be found by knowing the mass ratio of the same element in the two compounds. The above calculation method is only applicable if the mass ratio of the same element is known.

1. xso2---yso3

64x 80y

m m64x=80y

x/y=5/4

i.e. 5SO2---4SO3 have the same mass.

The number of sulfur atoms is the mass ratio of the sulfur element 5:42If the mass of the sulfur element is the same, the number of sulfur atoms is the same, and the relationship SO2 --- SO3 is obtained

i.e. the mass ratio of sulfur dioxide and sulfur trioxide is 4:5

3.The mass of the oxygen element is equal, and the number of oxygen atoms is equal (observation, each molecule of the two substances contains two oxygen atoms, so the relationship is).

ch3cooc2h5-- co2

x 88g88/x=44/88g

x=176g

4.In pure NH4HCO3.

n％＝14/79 *100％ ＝

The advertisement gives high-quality ammonium bicarbonate NH4HCO3 the highest nitrogen content in the world (, which is obviously impossible to achieve.

5.The mass of nitrogen-containing elements is comparable, and the number of nitrogen atoms contained is equal, and there is a relationship between NH4NO3--CO(NH2)2

x79 x = in urea fertilizer n (pure urea mass * 28 60 * 100) urea fertilizer mass 42

Substituting the pure urea quality obtained above can obtain the required urea fertilizer quality

set, the same mass of sulfur dioxide.

and sulfur trioxide for 100g

The S content of 100g of sulfur dioxide is: 100g*32 (32+16*2)*100%=50g

The S content of 100g of sulfur trioxide is: 100g*32 (32+16*3)*100%=40g

For sulfur-containing sulfur and sulfur trioxide of the same mass, the ratio of sulfur-containing elements is 50:40=5:4

First of all, the relative mass of the carbon atom is defined internationally as 12, and the general carbon nucleus contains 6 neutrons and 6 protons, a total of 12 (the entire mass of the atom is concentrated in the nucleus, and the mass of electrons outside the nucleus is too small to be remembered.) Protons and neutrons can be seen as having equal mass, protons are positively charged, and neutrons are uncharged. It has 6 electrons outside the nucleus and is negatively charged, so the atom is not electrically conducted).

So it can be said that how many neutrons and protons in the nucleus of each element is its relative mass, which is what you call sulfur dioxide, sulfur is 32, and oxygen is 16.

Suppose that the same mass of sulfur dioxide and sulfur trioxide is 100g, and the content of sulfur dioxide in 100g is: 100g*32 (32+16*2)*100%=50g

The S content of 100g of sulfur trioxide is: 100g*32 (32+16*3)*100%=40g

For the same mass of sulfur dioxide and sulfur trioxide, the mass ratio of sulfur elements is 50:40=5:4

relative to the atomic mass... The oxygen element is 16, the sulfur element is 32, so the sulfur content of sulfur dioxide is 16*2: (16*2+32)=, and the same is true for sulfur trioxide

Suppose that the same mass of sulfur dioxide and sulfur trioxide is 100g, and the content of sulfur dioxide in 100g is: 100g*32 (32+16*2)*100%=50g

The S content of 100g of sulfur trioxide is: 100g*32 (32+16*3)*100%=40g

For the same mass of sulfur dioxide and sulfur trioxide, the mass ratio of sulfur elements is 50:40=5:4

relative to the atomic mass... The oxygen element is 16, the sulfur element is 32, so the sulfur content of sulfur dioxide is 16*2: (16*2+32)=, and the same is true for sulfur trioxide