It is known that 6sin squared sin cos 2cos squared 0, belongs to 2, , find the value of sin 2 3

6(sina) 2+sina*cosa-2(cosa) 2=03sina+2cosa)(2sina-cosa)=03sina+2cosa=0 or 2sina-cosa=0tana=-2 3 or tana=1 2

Because belongs to [ 2, )

So tana<0

tana=-2/3

sina = 2 root number 13 cosa = -3 root number 13sin (2a) = -12 13 cos2a = 5 13sin (2a + 3) = sin(2a) * cos 3 + cos(2a) * sin 3

12 13*1 2+5 13*root number 3 2 (5 root number 3-12) 26

First, write the formula as the product of two factors.

2sina-cosa)(3sina+2cosa)=0, because [ 2, ] then sina>0, cosa<0, so 2sina-cosa will not be 0

Only 3sina + 2cosa = 0 is needed to solve tana = -2 3, and a [3 4, ] can be determined as sin2a = -12 13 and cos2a = 5 13

sin(2 + 3)=sin2a*1 2+cos2a*root3 2=(5*root:3-12) 26

Both sides are divided by sin cos, converted to, according to belong to [ 2, ) to calculate tan, and then calculate sin, cos bar should. That's all I can think of.

Replace sina cosa=tana=3sina =3cosa

sin²a=9cos²a

Because the first Wu high sin a+cos a=1

So cos a=1 9

sin²a=9/10

sinacosa = (3cosa) cosa = 3cos a = 3 10 so the original ruler = 18 10-9 10 = 9 orange burn 10,4,

2tanα-1/tanα=-1

2tan²α+tanα-1=0

2tanα-1)(tanα+1)=0

tan = 1 2 or tan = -1 in eggplant pomace

tanα=1/2

2sin²a-sinacosa

2 Trembling Mountain 5 (1,3 quadrants).

tan = -1 (2,4 quadrant beam pose).

2sin²a-sinacosa

First of all, the known formula is factored: (3sina+2cosa)(2sina-cosa)=0, so sina cosa=-2 3 or sina cosa=1 ruler source 2, that is, tana=-2 3 or tana=1 2, and because a belongs to (2, ), tana should be less than zero, and mushan is tana=-2 3,a=

sin(2a+ 3)=sin2acos 3+cos2asin 3=1 2sin2a+2 fractions of the root number 3 multiplied by the Ling resistance state to cos2a=

sinθ+2cosθ=0

sinθ=-2cosθ

sinθ/cosθ=tanθ=-2

sin²θ+cos²θ=1

2sin²θ-3sinθcosθ+5cos²θ(2sin²θ-3sinθcosθ+5cos²θ)1(2sin²θ-3sinθcosθ+5cos²θ)sin²θ+cos²θ)

2tan²θ-3tanθ+5)/(tan²θ+1)..The numerator of the denominator is the same as cos

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Is it an acute triangle ratio?

Solution: 2cos +3cos sin -3sin =12cos +3cos sin -3sin =sin +cos differential search

The two noisy closed sides are divided by cos at the same time: ascending crack.

4tanθ+1)(tanθ-1)=0

TAN = -1 4 OR TAN = 1

Answer: tan = -1 4 or tan = 1