Ask a few equations for high two chemical organics.

Updated on educate 2024-05-19
6 answers
  1. Anonymous users2024-02-10

    C2H5OH+HCl=C2H5Cl+H2O substitution reaction.

    2ch3cho+o2=2ch3cooh catalyzed oxidation reaction.

  2. Anonymous users2024-02-09

    ch3ch2oh---ch2=ch2+h2o is eliminated.

    CH2 = CH2 + HC--- CH3CH2Cl addition.

    or C2H5OH+HCl=C2H5Cl+H2O substitution.

    2CH3CHO+O2---2CH3COOH (catalyst. heating) oxidation.

  3. Anonymous users2024-02-08

    1. CH3-CH2-OH - >concentrated sulfuric acid) CH2CH2 (dehydration).

    CH2 = CH2 + HC--- CH3CH2Cl addition.

    2. CH3CHO - >concentrated sulfuric acid) CH3-CO-OH (oxidation).

  4. Anonymous users2024-02-07

    C2H5OH+HCl=C2H5Cl+H2O substitution reaction.

    ch3ch0 +2 ag(nh3)2oh→△→ch3coonh4 +2ag +3 nh3↑ +h20

    Silver mirror reflects.

  5. Anonymous users2024-02-06

    Most of the chemical calculation questions in the high school entrance examination are based on the calculation of chemical equations and the comprehensive problem of solute mass fraction of solution, so one or several hydrogen in hydrocarbon molecules are replaced by hydroxyl groups to form a class of organic compounds. Aromatic hydrocarbons on the ring.

  6. Anonymous users2024-02-05

    Saturated hydrocarbons:

    Substitution reaction: CH3CH3+X2 (light) CH3CH2X+HX (X is a halogen element, the same below).

    ch3ch2x+x2 (light).

    ch3chx2+hx

    ch3chx2+x2 (light)ch3cx3+hxch3cx3+x2 (light)ch2xcx3+hxch2xcx3+cl2 (light)chx2cx3+hxchx2cx3+x2 (light)cx3cx3+hx2 (light)cx3cx3+hxElimination reaction: ch3ch3 (170 concentrated H2SO4)ch2=ch2+h2o

    Oxidation reaction: CH4+2O2 (ignition) CO2+2H2O unsaturated hydrocarbons:

    Addition reaction: ch2 = ch2 + x2 ch2xch2xch2 = ch2 + hx ch3ch2x

    ch2=ch2+h2o→ch3ch2oh

    ch≡chh2→ch2=ch2

    ch≡chx2→chx=chx

    ch≡chhx→ch2=chx

    C6H6 (benzene) + 3H2 C6H12 (cyclohexene) polyaddition: N

    ch2=chch=ch2 (catalyst).

    -ch2ch=chch2-]-n

    nch≡ch

    catalyst)-[ch=ch-]-n

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