High School Chemistry A formula derivation of the concentration of a solution obtained by a gas diss

Before derivation, you need to know that n=m m; The amount of a gaseous substance at standard atmospheric pressure n (gas) = v ; The formula for the quantity concentration of a substance is c = n (solute) v (solution); Density of water Water = 1000g cm 3 = 1000g ml

There is a question to know, c = n (gas) v (solution).

n (gas) = v

v (solution) = m (solution) (solution) unit uniform (solution) = 1000 m (solution) = m (water) + m (gas) = (water) * v (h2o) + n (gas) m

Bring it in, and let's guide it yourself after calculation.

c = n gas v solution = (v gas [(m solution) 1000] = 1000 v gas (solution) = 1000 v gas [solute + m water)] = 1000 v = 1000 v gas [m*v gas + 22400*v(h2o)].

This doesn't need to be memorized, it's easy to mix, just memorize by rote, it's very commonly used and not difficult to remember.

The basic formula is this: n (mol) = 1000 v m to get the molar n after c (solution concentration) = n vThis one you're talking about is a combination of the two formulas.

It's a pity that I've already passed the college entrance examination... Alas.

c = n gas with rock stove v solution fool = v gas m solution jujube ruler )1000] =1000 v gas (solution) = 1000 v gas [solute + m water)] 1000 v = 1000 v gas [m*v gas + 22400*v(h2o)].

The basic formula for the quantity concentration of a substance: c = 1000 m when the amount concentration of the substance c, the density of the solution and the molar mass m of the starving substance are determined. Only the mass fraction of the solution can be calculated.

The following is an explanation of the previously calculated title: 1 liter of water dissolves a gas v liters, and the resulting solution density is pg cm3 ,.. in the hood cavity

Because of the clever argument for c=n v n=v filial piety stove shout because =m v v=m so c=(v n=v so m gas=mv m total=mv v total=(mv so c=(v because it is g cm, so in multiplying 1 1....

c (quantity concentration of substance mol l) = 1000 * p (liquid density g ml) * c% (mass fraction) m (molar mass g mol).

C%=(C*M1000*P)*100% The unit of p (density of liquid) is g ml, but the unit of c (the concentration of the substance) is mol lTo convert ml to l, multiply by 1000

ps: g cm 3 = g ml This formula can be directly converted, which is convenient for doing problems.

From the basic formula of c=n v, it can be seen that the amount of substance concentration of the solution obtained by dissolving gas in water under standard conditions can be deduced by simply finding n and v respectively.

n=v/vm,vm= l/mol。

v = m (solution) p, m (solution) = v * p (water) + v * m .

Here, the unit of p is (g ml), and both v and v are l, so the unit of 1000p is l. After the unification of the unit, pay attention to the unified unit. Finally, by merging similar terms, the following formula can be obtained:

c = (v water) + v * m .

The concentration of a substance is a physical quantity that represents the composition of a solution, and the measure is the amount of solute contained in a unit volume of solution. The solute here can be elemental, compound, or ionic, or other specific combinations, and the unit is mol; Volume refers to the volume of the solution rather than the volume of the solvent and is measured in l.

The original topic must be that under the standard condition, 1000 ml of water (density of 1 g ml, so the mass is 1000 g) dissolved v liters of a certain gas (molar mass m) to obtain a solution with a density of , calculate the amount of concentration of the substance in the solution.

This kind of problem must first really know and understand the basic formula of the quantity concentration of a substance:

c=1000ρω/m

Obviously, both density and molar mass m are known conditions, only the mass fraction is unknown.

M (solute) = mv

m (solution) = m (solute) + m (water) = mv

m (solute) m (solution) = (mv

Bring into the formula.

c=1000ρ（mv/

Multiply the fraction line up and down and divide it by m.

c=1000ρv/（mv+22400）

m is the molar mass of the gas.

From c=n v, we just need to find n and v separately.

n=v/vm,vm= l/mol

v = m (solution) p, m (solution) = v * p (water) + v * m Here, the unit of p is (g ml), and v and v are both [l], so the unit of 1000p is [l]. After the unification of the unit, it will be calculated, and this kind of question that needs to be written with letters, pay attention to the unified unit.

Final merge: c=(v-water)+v*m

A good question from the landlord.

CB = NB V liquid;

nb = mb mb = (m liquid mass fraction) mbv liquid = m liquid density of the solution (because the unit of density is grams per milliliter, the volume calculated here is milliliters, and the unit of the amount concentration of a substance is mololiters, so when substituting the formula, milliliters should be converted to liters, so 1000 is the base system conversion).

Substituting the first formula respectively, we get cb = nb v liquid = (m liquid mass fraction mb) [m liquid density of solution) 10-3] = 1000 density mass fraction molar mass of solute.

c (quantity concentration of substance mol l) = 1000 * p (liquid density g ml) * c% (mass fraction) m (molar mass g mol).

C%=(C*M1000*P)*100% The unit of p (density of liquid) is g ml, but the unit of c (the concentration of the substance) is mol lTo convert ml to l, multiply by 1000

ps: g cm 3 = g ml This formula can be directly converted, which is convenient for doing problems.

c=(1000pw)/m

The unit of density is g m3

The unit of m is g mol

The unit of C is mol l

1000 is to replace ml with l.

c = n v n = m m m v v = m liquid p

So c = (m substance m) p (g ml) m solution.

m quality m liquid) * 1000p (g l) * m = 1000 pw m