The number of rabbit feet is 12 more than the number of chickens, a total of 172 feet, ask how many

Solution: There are x chickens and y rabbits.

4y-2x=12，2x+4y=172

According to the first equation, x=2y-6 is substituted into the second equation, as follows:

2(2y-6)+4y=172

4y-12+4y=172

8y=184

y=23x=2 23-6=40pcs.

A: There are 40 chickens and 23 rabbits.

Chicken feet = (172-12) 2 = 80

Number of chickens = 80 2 = 40.

Rabbit foot = 80 + 12 = 92

Number of rabbits = 92 4 = 23.

Suppose the chickens are x and the rabbits are y, and the chickens are known to have 2 legs and the rabbits have 4 legs, and the equation is 2x+4y=172, 4y-2x=12, and the solution is x=40, y=23. There are 40 chickens and 23 rabbits.

4 rabbits + 2 chickens = 172 (1).

4 rabbit-2 chicken 12(2).

8 Rabbit 184

Rabbits: 23 pcs.

4 23-2 chicken 12

2 chickens 92-12

2 chickens, 80 chickens, 40 chickens.

40 chickens and 23 rabbits.

Suppose there are x rabbits, then there are 2 chickens (4x-12), and the title gives 4x+4x12=172

The solution is x=23

Substitute x=23 into (4x 12) 2=(4 23 12) 2=40Answer: There are 23 rabbits and 40 chickens.

Hope, thank you.

Since there are x chickens and y rabbits, then 2x+12 4y, 2x+4y 172, and solving the system of equations gives x 40, y 23, so there are 40 chickens and 23 rabbits.

The breakthrough point is that "the number of chicken's feet is 56 smaller than the number of bending feet of the buried rabbit", that is to say, the rabbit's feet minus 56 is as much as the chicken's feet, so the silver bend is 200 feet minus 56 to get twice the number of chicken feet, so as to get the solution.

Chickens (sold 200-56) 2 2 = 36 chickens.

Rabbits (200+56) 2 4=32.

A: There are 36 chickens and 32 rabbits.

Sum problem: Hood front (sum - difference) 2 = decimal number, hollow (sum + difference) 2 = large number.

As we know from the question, the number of feet of rabbits is: (200+56) 2=128 (only) The number of rabbits is: 128 4=32 (only).

The number of chickens' feet is: 200-128=72 (only).

The number of chickens is: 72 2 = 36 (only) Hu Song.

Answer: There are 31 chickens and 32 rabbits. Carrying.

Reason: Suppose there are x chickens and y rabbits, then there are 2x feet of chickens and 4x feet of rabbits, according to the problem, because there are 200 feet of chickens and rabbits, so we get the equation 2x+4y 200, because the number of chickens has 56 fewer feet than the number of rabbits, so we get the equation 4y-2x 56, and the equation + can be obtained.

8y＝256

Solve y 32, and put y 32 generation into the equation can be clearly and faintly solved x 31, so there are 31 chickens and 32 rabbits.

The number of rabbits is (200+56) 8=32, and the number of chickens (200-56) is 4=36.

There are x repentant chickens.

Then there are (200-x) rabbits, 2x chicken feet, and 4 (200-x) rabbit front feet.

Then 4(200-x)-2x=56

The solution is x=124,200-x=76

Therefore, there are 124 chickens and 76 rabbits.

The total number of chickens and rabbits is 200, which is 68 less than the number of rabbits, if all rabbits have how many chickens, 200 feet 4, the number of chickens' feet is 200, and the previous judgment is 4 4 less than the number of rabbits' feet, and each chicken is more, then the difference between the number of chickens and rabbits' feet is 4+2 less, which is actually 200 less 4-68, that is, chickens (200) 4-68 (Huiji 4+2) = 122 rabbits 200-122=78

There are 124 broodstock chickens and 76 rabbits, and you can solve the problem with a column equation.

There were 124 chickens and 76 rabbits.

Chicken + Rabbit = 200, 4 Rabbit - 2 Chicken = 56, Rabbit = 76, Chicken = 200-76 = 124, so there are 124 chickens and 76 rabbits.

Solution: If there is a chicken, then there are (200 a) rabbits, according to the title.

2a+56=4(200－a)

6a=744

a=124When a=124, 200 a=200 124=76Answer: There are 124 chickens and 76 rabbits.

Answer: Chicken ten rabbits = 200, 4 rabbits - 2 chickens = 56, 2 rabbits - chickens = 28, 3 free = 228, rabbits = 76, chickens = 200-76 = 124, chickens are 124, rabbits are 76.

You can set the chickens and rabbits are x and y respectively, according to the title, we can know that x y 200, 4y-2x 56, from the first formula 2 plus the second formula to get it, 6y 456, y 76, x 124, that is, there are 124 chickens and 76 rabbits.

Solution: Let the chickens have x, then the rabbits have (200-x), then the equation is obtained.

200-x) 4-2x=56, the solution is x=124, 200-x=76

A: There are 124 chickens and 76 rabbits.

Let the chickens and rabbits each have x and y, and list the system of equations according to the problem:

x+y＝200 ①

4y-2x＝56 ②

Solve the system of equations: x 124, y 76

A: There are 124 chickens and 76 rabbits.

Suppose the chickens are x and the rabbits are y, and the equation x y 200 is obtained, the chickens have 2 legs, the rabbits have 4 legs, and the solution is x 124, y 76, and there are 124 chickens and 76 rabbits.

Chickens x and rabbits.

x+y＝200

4y-2x＝56

There are 124 chickens and 76 rabbits to solve the equation.

Suppose there are x chickens, y rabbits, chickens have two legs, and rabbits have four legs.

Then x y 2004y-2x

x＝200-y

Substitution. 4y-2 （200-y)＝56

4y-400+2y＝56

6y＝456

y 76 so x 124

The chicken has two feet and a rabbit has four legs.

x+y=100

x-y=28

128 divided by 2 = 64

64 Except for the pants with 4 = 16, there are 16 rabbits that are not fierce.

36 divided by 2 = 18 chickens have 18.

There are x chickens, rabbits (100-2x) 4 = brothers.

2x=4(2x=72-2x

4x=72x=18

Chicken Bizhou 18 hands dust, rabbit 16.

Solution: If there are x chickens, rabbits are 12-x, 4 (12-x)-2x 1848-4x-2x 18

6x＝48-18

x=30÷6

x = 5. A: There are 5 chickens.

Summary. Hello dear, this is a typical chicken-rabbit cage problem, we, with x chickens, y rabbits, then, 2x+56 4y, x+y=200, so x 124, y 76

There are 200 chickens and rabbits, and the number of chickens and rabbits is 56 fewer than the number of rabbits.

Hello kiss, this is a typical chicken and rabbit with the cage to ask the question of prudence, we, with x chickens, y rabbits, that file, 2x+56 4y, x+y=200, the mu is respectful to x 124, y 76

Hello dear, this is a typical problem of chickens and rabbits in the same cage, we have a friend empty smile x chickens, y rabbits, then, 2x+56 4y, x+y=200, so x 124, y 76, so there are 124 chickens, good contains 76 rabbits.