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To be honest, mathematics has a lot of points in the college entrance examination, in fact, everyone is different, you don't have to care about others, as long as you do your best, it's OK! "How can you be as good as you want, and you should be worthy of my heart" right, first of all, you should have confidence in yourself and try your best to fight, and don't care too much about the result.
My suggestion is less complicated and cumbersome, mainly as follows:
1.Closely following the teacher's ideas in class and actively cooperating can have the effect of getting twice the result with half the effort.
2.After class, it is important to do an appropriate amount of exercises, not more, do a question to fully understand the rules from this question, and then encounter similar problems quickly to have a clear idea, which is to draw inferences from one another.
3.That book is good, but you have to do it selectively, focusing on your own weak topics and types of training.
4.Every test should be taken seriously, and the questions you have done should be impressive, especially the wrong questions should be seriously reflected and summarized (you can consider establishing a collection of good questions for mistakes, which can be used for review before the test).
4.Don't say much else, usually communicate with the teacher more, ** learning problems, the teacher is the best choice!
5.Maintain a happy mood every day, easy and fast pace.
The above is just a personal opinion, you also have to combine your own actual reasonable arrangement, mathematics is like this, as long as you do the right amount of problems "every day", as long as you really pay, there will be a return. Come on!!!
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Without further ado, try to find out all the college entrance examination questions and mock questions you can find, and do a few questions a day. Everything will be fine. Also, don't doubt yourself, in the third year of high school, many people will have a big change in their math scores on each exam (including the best students), if your ability is up and you are enough to adapt to the mode of the college entrance examination, then, you will definitely do well in the college entrance examination.
I wish you the best of luck in the college entrance examination.
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First of all, memorize all the definitions, because there are many definitions and it is easy to be confused, and then go through the classic questions. Then you can find the hard ones to do.
Good luck.
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I graduated this year.
Everything upstairs is correct, so I won't go into details.
I'll just give you a little advice, and I'm sure you'll thank me if you do it!
For middle school students or below, be sure to do a good job of fill-in-the-blank multiple-choice questions, try to be good.
You will find that if you do a good job of fill-in-the-blank multiple-choice questions, your grades will definitely improve!
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Do the questions. You can only pass it by doing the questions.
I used to be like this, buying Huanggang's to do
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First of all, read the textbook well and get the basic knowledge solid.
The book you bought is good, the question is a must, but you have to do it well, you can't do it blindly, and you have to summarize it in time after you finish it.
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As shown in the figure below, you can directly substitute the equation of the circle into the equation of the straight line and solve it.
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Convert the line cos( +6)=1 to Cartesian coordinates The equation is: y= 3 -2, and the circle =4s n becomes =4sin then.
Ten y -4y=0, synonymous elimination of elements: 2 3x+3=0, =3, y=1, the intersection coordinates are (3,1), the use of = y), tan =y is the polar coordinates is:
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The first one is set to z=a+bi to be brought in, the second one is calculated directly, and the third one can be calculated by finding a similar number that is easy to calculate.
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I'm only in third grade, and I won't.
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When x belongs to 0 to 1, fx=sin x+1? Is this one? I can't see clearly.
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Personally, I think that the key is to lay a solid foundation and grasp 60% of the scores first. Then in the third year of high school, you must be good at summarizing, for example, physics, which aspect of the content is not very good, just find the right direction and work hard.
Also, be sure to make a note of mistakes, record the questions you made wrong in the exam or practice, and review them every day to ensure that you don't make mistakes a second time for this type of question.
Third, it does not emphasize the tactics of the sea of questions, but it must be done with fine questions, which are real questions or representative questions from previous years.
In fact, there are skills in the exam, such as the allocation of time, the order of answering difficult questions, etc.
But at the end of the day, if you want to improve your score quickly or get good grades, you have to work your own.
Fourth, it is also very important to buy a good review material and do questions, and the method of learning from the predecessors is even better, go to that ** to see it.
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Read the textbook several times, and you must do the practice questions after class. Skill comes from practice. Mathematics is a lot of practice, and you may not know much at first, but you must stick to it, and it will work.
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1. a=3, b=4, c=a-b =25, so c=5. Alignment x = a c = 9 5, the asymptotic equation just need to change the constant on the right side of the hyperbola to 0, and get: y= (4 3)x.
For convenience, set |pf1|=m,|pf2|=n, then mn=32,|m-n|=2a=6, so m2mn n=36, i.e. m n=, so the angle f1pf2 is 90°;
2. From the above question, this problem is equivalent to finding the height on the hypotenuse of the right triangle F1Pf2, using the area of the triangle, H=16 5, which is the distance from the point P to the X axis;
3. If the right focus is f(5,0), then the straight line is x y 5=0, substituting the hyperbolic equation is: 7x 90x 369=0, and the ab midpoint ab is half of the sum of the two roots of this equation, that is, 45 7,|ab|=[√(1+k²)]x1-x2|, using x1 x2 = 90 7 and x1x2 = 369 7 to calculate |ab|。
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Solution: AC2=(4sinq-3cosq) 2+(4cosq) 2+(3sinq) 2
25-24sinq*cosq
25-12sin(2q)
If and only if Q=45°, the minimum AC length is 13
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Draw the image according to the constraints, the feasible domain can be obtained, because a 0, b 0, so when x=1, y=2, the objective function can obtain the maximum value, i.e., a+2b=1, 2 a+1 b=(2a+4b) a+(a+2b) b=4+4b a+a b 8, if and only if 4b a=a b, i.e., a=1 2, b=1 4, take the equal sign, that is, the minimum value is 8
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