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Anonymous users2024-02-11The gain and loss of electrons are conserved, the valency is reduced and the valency is increased, and then the ratio is calculated.
value, in trim.
.This is to take a pen and paper to draw the drops, can't tell the white hunger, the most important thing is self.
I have to understand.
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Anonymous users2024-02-10It is enough to remember that oxygen and metals reflect this example
Universal trim method:
1 Label each substance with a coefficient, 2 According to the number of atoms of each element is about equal, you can list the equations, 3 Solve the equation and find the ratio of each coefficient
Example: 1 Set the coefficient:
a feso4+b hno3==c fe2(so4)3+d fe(no3)3+e n2o+f h20
2 Column Equations:
Iron: a = 2c + d
Sulfur: a = 3c
Oxygen: 4a+3b=12c+9d+e+f
Hydrogen: b = 2f
Nitrogen: b = 3d + e
3.Solve the equation:
There are tricks The second equation is simpler, so let c = 1, then a = 3, from the first equation d = 1, substitute a, b, d into the next three equations and slowly find out the other coefficients are b = 16 3, e = 13 3, f = 8 3 It is not necessarily an integer to find out, just divide it So a:b:c:
d:e:f=3:
8 I don't know how to talk in detail, but it's very useful
Bonus points!! I'm so my face
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Anonymous users2024-02-09The valency of iodine is +5 0 valence, and the coefficient is 2, so a total of 10 electrons are obtained from the bisulfite group by +4 +6 valence, and the coefficient is 5, so a total of 10 electrons are lost, so the oxidant is 2naio3 The reducing agent is Nahso3 The oxidation product is Nahso4 and Naso4 and the reduction product is I2
So the mass ratio of matter is 5:1, and you multiply that by their relative molecular mass, and it comes out!
5 is 3*naso4+2*naso4).
Hope it helps.
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Anonymous users2024-02-08(1) The oxidant in the reactant is Naio3, the arrow points to I2, it should be written: 2 5E-, the valency is reduced, and it is reduced.
The reducing agent is NaHSO3, and the arrow points to NAHSO4 and NA2SO4, which are written separately, lose 6E-, increase the valency, and are oxidized; Loss of 4e-, the valency increases, and it is oxidized.
2) The oxidation product is NaHSO4, Na2SO4, the total mass is 644, the reduction product is I2, and the mass is 254
The mass ratio is 322:127
Metals generally have only one valence state, and non-metals generally have only one negative valence state. Oxygen is generally -2 valence and, rarely, -1 valence. For example, in peroxides, oxygen is -1 valence. >>>More
The S in Na2SO3 is +4 valence, which is oxidized, and the valency increases, which can only be increased to +6 valence. There is a total of Na2SO3, then the electrons are transferred. >>>More
1.The number of electrons transferred is 2e-, Oxidant: Copper sulfate Oxidation product: Iron sulfate. >>>More
Increased valency, loss of electrons, oxidation, use as a reducing agent··· Reduced valence·· Get electron·· Restored·· To be an oxidant··· Hee-hee
In this reaction, there is only the electron gain and loss of nitrogen element, the valency has risen and decreased, so C is wrong, the increase of nitrogen in metadimethylhydrazine is oxidized, it is a reducing agent, so a is wrong, the reaction is the recombination of atoms, so there is an endothermic and exothermic process, C is wrong, D is left, of course, there are eight electrons transferred from two N2O4 to N2 D is correct.