A solid compound is known to consist of C h o cu

Carbon dioxide carbon monoxide passes the gas into the clarified lime water, the lime water becomes turbid, proving to be carbon dioxide gas If operation 1 is in "blue solution - solid m", operation 1 is filtration. The instruments are: glass rods, funnels, iron frames, beakers, and beakers to add excess a

Copper chloride is completely reduced to copper. (Fe+CuCl2=Cu+FeCl2) The purpose of adding a sufficient amount of b is to remove the excess iron in copper.

Fe+2HCl=FeCl2+H2) no longer produces bubbles, proving that the purpose has been achieved.

Solution: (1) According to the law of conservation of mass, "a solid compound is composed of four elements: C, H, O, and Cu", so it is conjectured that it may also be carbon dioxide;

Experiment: In order to verify the carbon dioxide, gas is passed into the clarified lime water to see if the lime water becomes turbid;

2) Separation of insoluble matter, the name of operation A is filtration; The glass instruments needed to complete the operation include a beaker, a funnel and a glass rod;

After adding excess iron powder to the blue-green solution, the iron reacted with copper chloride and hydrochloric acid, and the products were: FeCl2, Cu, H2

The method of determining whether B has been added to solid M is excessive: a small amount of B is added, and no bubbles are generated

Therefore, the answer is: (1) carbon dioxide, gas is passed into the clarified lime water, and the lime water becomes turbid, which proves to be carbon dioxide.

2) Filter, glass rod.

fecl2、cu、h2

Add a small amount of B and no bubbles are generated, which means that it has been excessive.

A, B, C, D are composed of three of the five elements of NA, H, S, C, O, the analysis can know that the substances composed of three of the five elements of NA, H, S, C, O are: Na2CO3, NaOH, Na2SO4, H2SO4, H2CO3, B + Butyl C + H2O + CO2, there is carbon dioxide generation, indicating that the reaction of B and D is the reaction of sodium carbonate and sulfuric acid, A + B C + H2O, thus indicating that B is sulfuric acid, then A is sodium hydroxide, and D is sodium carbonate, the resulting propylene is sodium sulfate

So the answer to this question is: Naoh, H2SO4, Na2SO4, Na2CO3

Carbon dioxide carbon monoxide passes the gas into the clarified lime water, the lime water becomes turbid, proving to be carbon dioxide gas If operation 1 is in "blue solution - solid m", operation 1 is filtration. The instruments are: glass rods, funnels, iron frames, beakers, and beakers to add excess a

Copper chloride is completely reduced to copper. (fe+cucl2=cu+fecl2)

The purpose of adding a sufficient amount of b is to remove the excess iron from the copper. Fe+2HCl=FeCl2+H2) no longer produces bubbles, proving that the purpose has been achieved.

Let me bubble up this 2012.

In fact, the reactions involving manganese dioxide in middle school are: hydrogen peroxide decomposition, potassium chlorate decomposition, and chlorine gas preparation three reactions, it is easy to grasp these, from the block diagram: c d is chlorine or oxygen, because the reaction 1 conditions are variable, so c: oxygen, d: chlorine b: hydrochloric acid.

F and B (hydrochloric acid) reaction, then F must be a metal oxide (non-metal oxide does not react with hydrochloric acid), a metal oxide can react with hydrochloric acid to form 2 substances, it means that F contains elements with different valences, recall, middle school is only: 4 oxide 3 iron. Therefore:

e is iron, i.e., a: potassium chlorate under heating conditions.

Unheated: Hydrogen peroxide.

It's been a year in college, and I don't forget much.

Here it should be about HCl mnO2 making Cl2

and the manufacture of O2 by MNO2

cucl2、caco3

NH4Cl and Cu can react with hydrochloric acid to produce gas is calcium carbonate, gas B passes into the clear lime water, lime water becomes turbid, so gas B is carbon dioxide, copper chloride is dissolved in water is a blue solution, so A must contain copper chloride, D is copper chloride solution; After adding hydrochloric acid, there are insoluble solids in hydrochloric acid, so A must contain copper, so C is copper; A is added to sodium hydroxide solution to produce gas, only ammonium chloride can produce gas with sodium hydroxide solution, ammonium salt and sodium hydroxide produce ammonia gas and purple litmus solution, litmus solution turns blue, so a must contain ammonium chloride

1) From the above analysis, it can be seen that B is carbon dioxide, and the chemical formula is CO2 (2) From the above analysis, it can be seen that there are 4 substances in mixture A: (3) Since copper does not react with hydrochloric acid, solid C is copper

4) Solution g is the solution after the reaction of sodium hydroxide with copper chloride and ammonium chloride, and the solute in the solution is sodium chloride, so the metal ions in the solution are Na+

5) In the experiment, sodium hydroxide reacts with copper chloride to produce a blue precipitate, so the reaction chemical equation is CuCl2

2naoh═cu（oh）2

2nacl．

So the answer is: (1) CO2

2）4（3）cu （4）na+

5）cucl2

2naoh═cu（oh）2

2nacl