Why the gravitational force exerted on the object and the force exerted by the inclined force on the

The gravitational force is vertically downward, the frictional force given to the object by the inclined plane is parallel to the inclined plane, and the supporting force given by the inclined plane to the object is perpendicular to the inclined plane. The resultant force of friction and support is counter to the direction of gravity, and both cancel out.

Because the object is at rest on the inclined plane, that is, it is in equilibrium, the object is subjected to a balancing force, and the object is only subjected to the gravitational force and the force of the inclined force on it, so the gravitational force on the object and the force exerted on the object by the oblique force are a pair of equilibrium forces.

The force of the oblique force on the object refers to the supporting force perpendicular to the object of the oblique face, or the elastic force, the component of the elastic force and the gravitational force along the straight line in the direction of the elastic force is a pair of equilibrium forces, and the other component force and friction force of gravity are a pair of equilibrium forces [equal size reverse collinear] The decomposition of the force is understood after high school.

The oblique aspect of the object is the supporting force, and because the supporting force makes the object still , it is the opposite... I'm messed up myself.

The force of an object on an inclined plane includes pressure and friction, and the force on an inclined plane includes a supporting force and frictional force.

The gravitational force of the object creates the pressure and friction on the inclined plane.

The static friction and the resultant force of the supporting force.

On Earth, the gravitational pull is relatively balanced.

You're sure it's an inclined plane, and if it's an inclined plane, you're wrong.

。。This proposition itself is false.

How to learn physics? Obviously failing.

Who said that the children of the wrong people ...

The force exerted by the bevel on the object refers to the force exerted by the bevel on the object, including support and friction.

1.Support Force: The force exerted perpendicular to the inclined plane by the bevel on an object is known as the support force.

It is the force exerted on an object by the molecular junction of the inclined plane and the arrangement of electron clouds. The direction of the supporting force is perpendicular to the inclined plane and upward to the direction of gravity to keep the object at rest or moving along the inclined surface.

2.Friction: The force exerted by the bevel on an object parallel to the inclined plane is known as friction.

The magnitude of the frictional force depends on the roughness between the object and the inclined plane and the pressure between each other. The direction of friction is opposite to the direction of motion of the object relative to the inclined plane to prevent the object from sliding down the inclined plane.

On an inclined plane with an inclination angle of , when the object slides along the inclined plane or remains stationary, the force exerted on the object can be decomposed into two components: a component perpendicular to the inclined plane (supporting force) and a component parallel to the inclined plane (frictional force). The direction of the resultant force of these two forces is perpendicular to the inclined plane and may have different magnitudes and directions depending on the state of motion of the object.

If the hypogonal surface of the pants has support and friction on the object, the force on the object at this time, including:

The support force of the oblique to the object, the frictional force of the oblique to the object.

Not necessarily! With the slope.

The state of motion of the object on the body varies from one to the other.

1. If the object crop accelerates downwards early, the support force of the ground to the inclined body is less than the total gravity of the object and the inclined body.

2. If the object moves at a uniform downward speed, the supporting force of the ground on the inclined body is equal to the total gravity of the object and the inclined body.

3. If the object is in downward deceleration motion, the supporting force of the ground towards the inclined body is greater than the total gravity of the object and the inclined body.

No. When an object slides, part of its cavity gravity provides downward acceleration, so its pressure on the inclined plane decreases, so that the amount of support force on the inclined body will be smaller than the total gravitational chain of the object and the inclined plane.

Yes. The motion of the object does not affect the force in the vertical direction, so it is still their total weight.

It's resistance. Because the gravity force in Lu Shendan can be decomposed into the component g1 along the inclined plane and the component g2 perpendicular to the direction of the inclined plane, g1 is the opposite direction of movement of the trolley, which is the resistance. G2 is equal to the support force of the early perturbation slope.

1) The first half of the sentence "decomposes into a plane along the inclined plane."

The downward component "is correct and can also be said".

the force that causes the object to slide down".

2) But it cannot be said that "decomposition is pressure on the inclined plane".

It can only be said that "the force that decomposes into which pants makes the object press against the inclined plane".

3) Because force can only be synthesized and decomposed, Xiangkuan cannot be transformed.

The force that causes the object to press against the inclined plane is numerically equal to the pressure of the object on the inclined plane, but it can only be a component of gravity, not the pressure of the object on the inclined plane.

Are you a year taller? It's all over.

Why do you still ask ......

1.When there is an object moving at a uniform speed on a rough inclined plane, the object is subjected to three forces, the gravity of the vertical leaky bench downward, the support force perpendicular to the inclined plane and the frictional force along the inclined plane, the resultant force of these three forces is 0, that is, the net force of the support force perpendicular to the inclined plane and the frictional force along the inclined plane is equal to the gravity force, and the direction is vertical upward, and the force applied to the object is an inclined plane by the support force perpendicular to the inclined plane and the positive friction force along the inclined plane upwards, that is, the force on the inclined object at this time is equal to gravity. The direction is vertically upward. According to Newton's third law, the force of the object on the inclined plane is also equal to the gravitational force, and the direction is vertical downward, so that the inclined plane is not subjected to the force in the horizontal direction, and the inclined plane has no tendency to move in the horizontal direction, so the inclined plane has no friction force with the ground.

Note: Here the force of the bevel towards the object is not only the supporting force but also the frictional force. Here the force of the object on the inclined plane is not only pressure, but also rough friction.

1. The component of gravity and this static friction force form a pair of equilibrium forces. And it is possible to calculate f=mgsin (i.e. the component of gravity).

2、.If the resistance of an object is 20N, [this resistance pin dissipation must not be frictional force, but only another force] to push it with a force of 8N, the object will definitely not move, [it cannot be determined that it will not move], so it is in equilibrium and cannot be determined to be in a balanced attitude], so the thrust and resistance are equal, but 20N is not equal to 8N, [so your conclusions are wrong].

Dear, don't forget to be in time. If you have any questions, I will help you at any time.

How can you tell if an object is acting on a balancing force?

Rest, Constant velocity, Linear motion, Equilibrium force, Balance of forces.

The bevel support force on the object placed on the upper and the pressure on it on the bevel are a pair of interaction forces. There are three forces on this object, gravity, support, and friction with the inclined plane.

The bevel force on which the object is subjected to its support and the pressure on it on the bevel are a pair of interaction forces. (acting on two interacting objects respectively).

This sentence is a bit ambiguous......Let's give you a specific analysis:

A pair of balancing forces refers to a pair of forces [acting on the same object] and reversing the same straight line in equal proportions. If the force on the object is such a balance. (Uniform linear motion or stationary).

A pair of interaction forces refers to a pair of forces [acting on different objects] along the same straight line in the opposite direction.

First of all, the object is inclined to the plane.

The pressure exerting force on the object is an object, whereas the force object is an inclined plane. After decomposing the gravitational force, the gravitational force is absent and the object experiences two forces.

One "makes the object slide down the inclined plane" and the other "causes the object to press perpendicular to the inclined plane". That is, the object that is subjected to this force is that object. Hence the nature of the two forces is different.

However, if the object is moving along an inclined plane or at rest, the two forces should be equal.

The object is at rest on an inclined plane.

The amount of pressure on the inclined plane of the object is the magnitude of the force of gravity perpendicular to the inclined plane, but the two forces are not equivalent, the force of gravity is the earth, and the force object is the object. The object of force of pressure is an object, and the object of force is an inclined plane.