C asks, C asks?

a is assigned to -1, and then the octal code and the unsigned decimal code are output.

You just have to turn on the computer's calculator and do it.

The int type is a 4-byte integer, and -1 is the ffffffffff calculator point hexadecimal, enter ffffffff

Point occimal 37777777777

Point decimal 4294967295

Your two lines of program output these two numbers, with a comma in the middle.

Hello First of all, you have a question:

k /= 10;His meaning is : k = k 10; , where = is the composite operator in c, in modern compilers the composite operator and ordinary: k = k + 10; is indistinguishable (but in the past k&r c, it was thought that composite operators can produce a more compact **), and finally my suggestion is:

Try to use composite operators because: 1, he can make your ** look cooler; 2, For example: b[a*2+d*(c+1)] = 10;

b[a*2+d*(c+1)] = b[a*2+d*(c+1)] / 10;Which one you say is better?

Now comes your second question:

It's called an epoticon in C, and the way it is used is to round it to zero, so that when K is a single digit, it will round it to zero, and the natural result is 0, understand?

Hope it helps.

k = 10 means k = k 10

If k is a single digit, k=0

It is to seek quotient % is to seek surplus, and to seek surplus is to seek model.

When you can't finish a line of the program, write it in a new line.

k = 10 means k = k 10 If k is a single digit, how many is the single digit divided by 10.

It depends on the type of k, if it is a floating-point type, it should not be zero, if it is an integer type, of course, it should be zero.

Hello landlord, you are only established in the case of k as int type.

If it is a double type, k is a decimal.

There are similar ones in c.

k+=10；k*=10；k-=10；

k = 10 means k = k 10

k is the word of the book k=0

It is to seek business and to seek surplus.

<> the first program should not need these 4 lines, plus these 4 lines is equivalent to reading the three letters of boy into ABC, so there is no content in the output statement after reading.

The second program is not played when you run it, which is equivalent to no input, so there is no output.