Math Questions: Two questions for questions 7 and 8, and 8 questions for math questions

Updated on educate 2024-06-13
12 answers
  1. Anonymous users2024-02-11

    7.Through C to do the extension of BC, cross AD with point E, AC=10, CE:EA=1:

    3, so CE:AC=1:2,EA:

    ac= 3:2, so, ce=10 2=5m, ea=10 3=10 3, ea=10 3 3m, so be= (ab2-ea 2), bc=be-ce

    I can't see clearly, just use I, pass A to do the BC perpendicular line, cross BC at the point F, the angle B is equal to 60 degrees, AB=6, so AF=3 3, BF=3, so DE=AF=3 3, I know, therefore, EC can be found, and the area is naturally found.

  2. Anonymous users2024-02-10

    No one answered for a long time, so I'll do it.

    1. Extend BC to cross AD and point E

    It is known that bea=90° because the slope ratio is 1:3 and ac=10 m, so ce=5 ae=5 3 m.

    It is known that ab=14m, ae=5, 3m, and get be=11mbc=be-ce=11-5=6m.

    2. Make af bc at point f

    It is known that b=60° ab=6 gives bf=3 af=3 3. af=de=3√3

    Because i=1: 3, so ec=de* 3 =9 because ad=fe , we get bc=bf+fe+ec=3+4+9=16s=(ad+bc) de 2

  3. Anonymous users2024-02-09

    The square is the cubic meter, 24d =, then, first calculate the volume of a square log: the bottom area is high, 500 square trees = 500

  4. Anonymous users2024-02-08

    24dm=

    3*A: There are 360 square meters of wood.

  5. Anonymous users2024-02-07

    7. Proof:

    ad bisects bac,de ab,df ac de=df

    In RT DEB and RT DFC.

    de=dfdb=dc

    deb≌△dfc(hl)

    be=cf8, may it help you!

  6. Anonymous users2024-02-06

    It is enough to prove the congruence of two triangles, ad is the bisector of the angle, de, df are perpendicular to both sides of the angle, so de=df, and by db=dc, two right angle conditions, the congruence can be proved, and then the two sides are equal.

  7. Anonymous users2024-02-05

    Question 7:

    Solve the equation to obtain: x=50

    Question 8: The first lock, you need to try 4 times.

    The second lock needs to be tried 3 times.

    The third lock needs to be tried twice.

    The 4th lock needs to be tried 2 times.

    The 5th lock needs to be tried 0 times.

    4 + 3 + 2 + 1 + 0 = 10 times.

  8. Anonymous users2024-02-04

    (87-78)÷(

    9 = 50 (person).

    Question 8 (1st lock) is opened with a maximum of 4 keys, 4 times.

    2……3……Try 3 times.

    Total: Up to 10 times.

  9. Anonymous users2024-02-03

    <> I'm glad to answer the questions for you.

  10. Anonymous users2024-02-02

    <> Sen Qingcheng, this seepage is like shouting stuffy pictures.

  11. Anonymous users2024-02-01

    You just need to know how many elements a has, and the number of non-empty true subsets of a = 2 n -2

    The numerator is 3, so the denominator can only be 1,3,-1,-3

    So x has four, so the number of true subsets is 16-2=14

  12. Anonymous users2024-01-31

    8。(4 5) Divide the closed culture by the shed guess (2 3).

    4 Chain type 5)x(3 2)] divided by [(2 3)x(3 2)].

    4/5)x(3/2)

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