How many people are in Class 6 of the 3rd grade of Hongya Elementary School

52 maps. This data is ** on the map, and the final result is subject to the latest data on the map.

(1) (47+52+49+50)÷6=198÷6

33 (people) A: The average number of people per car is 33.

2) 47 + 52 + 49 + 50 = 198 (person) 198 2 = 99 (person).

99 people< 100 people.

99 33 = 3 (vehicles).

A: It should be divided into two batches, one batch of 99 people, each batch with 3 vehicles.

ps: By the way, what grade are you, uh?? Such a simple question...

Question 1: You will. The second question is divided into two batches, each batch has 99 people (47 + 52) (49 + 50) and three cars.

Total number of students in the third grade Number of cars = average number of people per car.

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People don't know what they like when they're young Besides, early love is not a good thing I think you better put your mind on studying You still have a long way to go Although there are many people in today's society who are young in love But you are still very young If you fail to confess Don't you feel embarrassed to meet in school? I think you should study hard, at least you can be friends first.

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Faint to death, now that you're young, wait until you're older.

Think of the fifth grade as a unit"1"

1-7 20=13 20 (Note: One shift.)

The corresponding score rate with the second class is a fraction of the fifth grade of the first and second classes) 13 20 2=13 40 (Note: the first class accounts for a fraction of the fifth grade) 7 20-13 40=1 40 (Note: the third class is a few fractions more than the first class) 3 1 40 = 120 (people) (Note:

The number of fifth-graders can be calculated by dividing the extra number of people by 3 and dividing the corresponding score of 1 40).

Analysis: The number of students in the third class accounts for seven-tenths of the whole grade, and the number of the fifth grade can be divided into 20 parts, of which the third class accounts for 7 parts, the first class and the second class each account for (20-7) 2 = shares, and the third class has more than the first class, then the total number = 3 people.

Since there are 20 copies in the fifth grade, the total number of students = 20x6 = 120 students.

Solution: (20-7) 2=

3 (20x6=120 (person).)

Set: The first shift is x, then the second shift is also x, then the third shift is x+3.

x+3/3x+3=7/20x=39

39 + 39 + 42 = 120 (people).

3*7-20=1 (3+3)/1=6 6*20=120

Because the number of people in the third class accounts for 7 20 of the whole grade, that is, the fifth grade is divided into 20 parts, and the third class accounts for 7 of them, if the first class and the second class are added to 3 people, then the first, second and third classes are all 7 parts, so that the total number of people is 1 more than 6 people, and the fifth grade has a total of 20 parts, which is 20 * 6 = 120 people.

Set up a class with x people According to the title, the number of people in a class = the number of people in a second class = x the number of people in a third class = x + 3

x+3) [(x+3)+x+x]=7 x=39 of 20 solutions So the total number of people in the fifth grade: 39+39+39+3=120

Set a class size of x

x+3）/(x+x+x+3)=7/20

x = 39 for 120 people.

There are 120 students in each grade, 39 in both the first and second classes, and 42 in the third class

x*7 20+(x*7 20-3)*2=x to obtain x=120, 120*7 20=42 42-3=39

There are x people in the first class, x people in the second class, and x+3 people in the third class.

x+3）/(x+x+x+3)=7/20

The solution is x=9, so there are x+x+x+x+3=30 people in the whole grade.

Twenty-tenths minus seven-tenths equals thirteenths of twenty-tenths equals three and thirteenth-twentieths.

I didn't get a mistake, I didn't get a single reference value.

There is a class of X people, a second class of Y people, and a third class of Z people.

Because the number of people in the first and second classes is equal.

So x=y because the third class is seven-twentieths of the whole grade.

So z=7 20(x+y+z).

Because there are 3 more people in the third shift than in the first shift.

So z=x+3

These three systems of equations can be solved.

z=42y=45

x = 45 total number of grades = 42 + 45 + 45 = 132

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114…And elementary school students don't understand this.

Hypothesis: It turns out that there are x boys and 1 girl, and among the 3 people who transfer in, there are boy y and girl (3-y).

x,y must be an integer, and y can only be taken as 0,1,2,3

The equation is as follows:

Then it is calculated according to the situation:

When y=0, it is calculated that x=90, 90 boys, 72 girls, the total number of students in the original class is 162, and later transferred to 0 boys and 3 girls.

When y=1, it is calculated that x=35, 35 boys, 28 girls, the total number of students in the original class is 63, and later 1 boy and 2 girls are transferred.

When y=2, it is calculated that x=5, 5 boys, 4 girls, the total number of students in the original class is 9, and later 2 boys and 1 girl are transferred.

When y=3, the calculated x is a negative number, which is impossible, excluded.

Theoretically, the first three are possible, but considering the actual situation, I think the second one may be larger, depending on your choice and specific situation. ）

80 The fraction is 4/5, subtract 4/5 from 6/5, which is equal to 1/30, and 3 is divided by 1/30, = 90 (person).

A: There were 90 people.

First: 5/6 — 80% = 1/30

Find out how much is the difference between the original and the present.

1 out of 30 corresponds to 3 people.

So: 3 divided by 1/30 = 90 (person).

What grade are you in? This question is a typical example of a fraction application problem and should be learned in the sixth grade.

5/6 — 80% = 1/30

3 divided by 1/30 = 90 (person).

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Six classes and six classes, always striving to be the first. Heroic and invincible!

Six classes in two years! Dare to climb high! Challenge yourself! Push the limits! One! Two! Three! Four!

Twenty-six, twenty-six, everyone is excellent, and all activities are never lagging behind.

Two-six-two-six is always at the end, and eating is at the end! Dressing the last !! But the spirit of learning is always in the first 6!! Yes!!!

The wonderful "class slogan" is shared with you.

1) Class Goals:

l Thrive every seedling and gorgeous every flower.

l Grow in happiness and harvest in hard work.

l Happy learning and common development.

l Promote students' personality and build class characteristics.

Let every child have a happy childhood.

l Give every child a clear sky to fly over.

l Let our childhood be full, happy, and wise.

Let every child's childhood become the pearl of life memory.

l Happy to learn, upward, everyone strives to be a good student of "I can do" l Read good books, learn good habits, write well, and be a good person.

l Sunshine shines on every student, every day is happy, every day is harvested l Everyone loves the collective, and everyone has development.

l The sun is new every day, and we are making progress every day.

l Strive for progress and success.

l Wisdom and happiness.

2) Class style. l Diligent and enterprising.

l Civilized, disciplined, diligent and enterprising.

l Unity, discipline, truth-seeking, and pioneering.

l Diligent study, discipline and unity.

l Quiet, pure, respectful and competitive.

l Diligent study, discipline and innovation.

l Unity, happiness, harmony and forge ahead.

l Vigorous and uplifting, brilliant personality.

l I am proud of my class The class is proud of me.

3) Class spirit.

l We work hard and we are happy.

l Let love stay in my class.

As long as everyone has love, the class will always be spring.

l Honest, down-to-earth and realistic.

l Diligence and happiness Grow and be happy.

There is no best, only better.