Interpersonal Masters !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Respect, politeness, and enthusiasm to help others are the virtues of educated people, but if you are not a tendon, you have to use your brain, what to do, what to say, you have to learn to protect yourself, you have done well, how can others look down on you? Find shortcomings from yourself first, how to treat others, we don't understand the situation and can't say anything, or you need to experience and face it yourself.

That's right! Maybe that's how you feel! You may be too sensitive! I care about what others say and do! I used to think so, but then I found out that it wasn't like that!

So go ahead and be yourself and don't care what others say!

Try, friend!

Hehe, first you have to figure out why you want to be nice to them, is it to get a good interpersonal reputation or do you really like to be kind to others (which makes you feel good)? If you talk about the former, please don't have too much extravagance from others, and if you say the latter, just let it be, there will always be friends who are compatible with you and understand you. The most important thing is to have self-esteem and self-confidence, and not to care too much about what other people think

Frivolous, rude, and indifferent to others.

I have people like this around me. Less contact.

It's not that you're doing something wrong?

The problem is to take advantage of you. Look down on those who look down on you!

You need to continue to be respectful, polite, and helpful. I believe that the "love" in you will touch the people around you, and they will also respect you, be polite to you, and be enthusiastic!

As long as you stick to it!!

Thank you! If only everyone in the world were like you!

The circle you live in is full of many villains, because the school or work unit is not a good place, and your character is not suitable for that place, so you have to change circles.

Keep being yourself.

Shine, gold.

OC divides j aob, pe oa, pg ob

pf = pg angle bisector nature

pm=pn is not necessarily true. The position of doe within AOB is uncertain. If, aod boe, then pm=pn holds.

Proof: PE OA, PF OB

oep=∠ofp=90º

again eop= fop, op=op

oep≌⊿ofp（aas）

ep=fp, these are perfectly available" The distance from the points on the angular bisector to both sides is equal, ep=fp. To summarize].

and pg=ph, gep= hfp=90 rt gep rt hfp(hl).

eg=fh

pf = pg The distance from the point to both sides of the angle on the bisector of the angle is equal.

Theorem: PM and PN are not necessarily equal.

pf=pg

Because OC bisects AOB and the distance from the bisector to both sides is equal, PF=PG

PM does not necessarily = PN because it is not said that OD is the bisector of the angle AOC.

OE is the bisector of the angular COB.

Let's just say, AOB contains DOE

So I feel that pm is not necessarily = pn

Because according to the angle bisector theorem, pf and pg are originally equal, but pm and pn are not equal you can think about it, the position of od and oe is not limited in the question, od is a little to the left oe is a little left, pm is greater than pn.

The distance from the point on the bisector of the angle to both sides of the corner is the same.

oc bisects aob aoc= cobafp= pgb (as can be seen from the graph) and po=op (common edge), so fop is equal to gop(aas), so pf=pg

In the text, it is written that they have superhuman strength when they think that the expedition they are undertaking is the immortal cause of mankind. In fact, it would not have been possible to engage in this undertaking without a dedication to exploration, superhuman strength and courage. And when they fought against death on the way back and died one by one, none of them were of a bad seed, they were all well-known men, living clearly and dying tragically.

A strong spirit of collectivism. Expeditions require a spirit of teamwork and sometimes the courage to sacrifice one's own life to protect one's fellow travelers at critical moments. That's what Scott and his team did.

Selfless love. In the last breath of his life, Scott did not think about his own interests, but always thought about others: friends, companions, wife and children, as well as his country and people.

His last suicide note was not for fame and fame after his death, but completely a true expression of love; The letter was written so calmly that it did not look like a dying man in the slightest! Scott left that cold world with a passionate love and without the slightest hint of hate.

The cosine theorem is used to find the length of AD, DE, and AE, which is proved by using the cosine theorem.

1) Pass the point d as df, chuichang yinsun is straight in bc, and bc is in the chain ffc=bc-bf=bc-ad=3 cd=5, so df=4 ab=df=4

2)ae=af=x+3

ab^2+be^2=ae^2

16+y^2=(x+3)^2

y^2=x^2 +6x-7 (x>1)

1、ab=4

2. y=-16 (2 Horn DFE and Horn Deg "Horn AEG" so this kind of love wheel will not appear.

50x13 20 = 65 2kg of zinc weight.

65 2 2 5 = 325 4kg alloy weight after adding iron.

325 4-50 = 125 4kg weight of iron added.

Solution: Set: need to add iron x kg.

50×13／20﹚÷﹙50+x﹚=2／5

x = A, need to add 31,25 kg of iron.

The zinc content in the alloy of 50kg is 50*13 20 and iron x kg is required

50*13/20/(50+x)=2/5

The solution is x=

Solution: Let add iron x kilograms, then.

50*13/20=(50+x)*2/5

The solution is x=