Math Problems Any Angle Problems, Elementary Math Corner Problems

If the angle from the minute hand to 12 o'clock is (angle 1), and the angle from the hour hand to 12 o'clock is (angle 2), and the number of minutes is 5 minutes, then the minute hand points to the number 1 of the clock, (angle 1) = 360° 12 = 30°

If the number of hours is 8 o'clock, then the hour hand points to the number 8 of the clock and less than 9, the number of minutes is 5 minutes, 1 hour is 60 minutes, 5 minutes = 5 60 = 1 12 hours, and the number of the hour hand pointing to the clock is (8 and 1/12 = 97 12) (angle 2) = (12-97 12) * 30 ° =

4.The angle is (angle 1) + (angle 2) =

The angle of 8:00 is 150°

The angle of 0:05 is 360 of 1 12, that is, 30 °

The hour hand of 8:05 passed 30 degrees of 1 12.

So the angle is 150+

Measure it up against the wall clock! Twelve numbers are 360 degrees, one division is 30 degrees for a grid, 5 minutes is a grid, 8 points for 5 is 150 degrees, but the hour hand goes a little bit, 5 minutes should be 1/12 of an hour, 30 divided by 12 is degrees, and the final answer is: degrees.

7/6π。The hour hand is the starting edge and the minute hand is the final edge, which should be rotated counterclockwise.

The way to count the number of angles is to use the formula, the number of angles s=(n+1)(n+2) 2, where n is the number of lines separating the big angles.

The law of counting angles is:

1. When the number of edges of the number of corners is n, the total number of angles is continuously added from 1 to n-1.

2. When the number of small angles divided into is n, the total number of angles is continuously added from 1 to n.

Learn about the law of angles with the following example:

**There are three sides on it. There are two distinct angles, and one is the angle where the two corners are combined.

It can be clearly seen through ** that the number of angles is 2+1, and an arrow represents an angle.

When there are four edges, the number of corners changes.

There are 3 small corners, 2 horns, and 1 with 3 horns. There are a total of 6 corners.

When the graph has 3 sides, the number of corners is 2+1, and when the graph has 4 edges, the number of corners is 3+2+1.

In this way, you can find the law of counting angles, there are three sides, and the number of angles is 2+1.

There are four sides, and the number of corners is 3+2+1.

There are five sides, and the number of corners is 4+3+2+1.

There are six sides, and the number of corners is 5+4+3+2+1, and so on.

Let be an n-sided shape with an inner angle of x

n-3）*180-x=2060

n-3=(2060+x)/180

Because n-3 is an integer.

So (2060+x) 180 is also an integer (0 x360) to find x.

Bring it into the original style. (2).

Same as above (n-3)*180+x=2060.

The sum of the inner angles of the polygon (number of sides 2)*180, it is known that 2060 divided by 180 is equal to 11 and 80.

1) According to the title, 2060 plus an angle should be a multiple of 180, so this angle is 180 80 100 degrees, and the number of sides of this polygon is 14;

2) According to the title, 2060 minus an angle should be a multiple of 180, so the degree of this outer angle is 80 degrees, and the number of sides of this polygon is 13.

According to the sum of the inner angles of the quadrilateral.

180(n-2)

where n is the number of sides.

Get the inner angles and polygons greater than 2060°:

The sum of the internal angles of the 14 sides is 2160°

15 sides are 2340°

2340-2060=280° 180° (round) then the polygon is 14 sides and the angle is 100°

The sum of the outer angles of the convex polygon is less than 180° and greater than 0°

Therefore, if the inner angle is 180°, then the sum of the outer angles is 2060-180=1880° and 0°, then the sum of the inner angles is 2060-0=2060°, then the sum of the inner angles of the polygon is in the range of .

Between 1880° and 2060°.

And in between the inner angles and degrees only.

13 ° of 1980

Then its sum of internal angles is 1980°, and the outer angles are 2060-1980=80°, with 13 sides.

This inner angle should be 100, because the sum of the inner angles of the polygon is a multiple of 180, so 2060 is left except for one inner angle, so the minimum sum of the inner angles should be 2160, so it is a 12-sided polygon.

This outer angle should be 80 degrees, and this one is an 11-sided shape, because the sum of the inner angles should be 1980, so the above conclusion is reached.

1 Polygon.

Internal angle and c = (n-2) 180°

11 and 4 9

Because one less inner corner.

while the inner angle is 180°

So n=12

So this polygon is 12+2=14 sides.

This inner angle is.

2 Polygons.

Internal angle and c = (n-2) 180°

11 and 4 9

Because an outer corner is added, n = 11

So this polygon is.

11 + 2 = 13 sides. The inner angles and for.

The outer corner is.

The sum of the inner angles of the n-sided shape is (n-2) 180, (the sum of the inner angles of n-2 triangles, each of which is greater than 0 and less than 180, 2060 180 = 11....80, so it is a 14-sided shape, and the angles removed are 180-80=100

1.Within the same plane, two straight lines have (

parallel) and (intersect.

Two positional relationships.

2.Two points are arbitrarily determined on a straight line, and the part in between these two points is called (line segment, and the ray has only (one.

endpoints, the length of the line is (not measurable.)

3.An isosceles triangle whose apex angle is equal to 4 times the angle of a base is then its apex angle is (120

Degree. By the angle, this is a (obtuse angle.

Triangle.

Because Bo, Co are angular divisions, and the angle A is equal to 60, then the angle obc + angular COB is equal to one double of the (angular abc + angular acb) = 180 minus 60 The result is divided by 2. Utilize the triangle inner angle and angle BOC 120 degrees.

Corresponding angle; internal misalignment; Same as the inner corner.

Isotopic angles, i.e., in the same position, both angles are on the same side of the third line, above or below the two lines being truncated.

Inner wrong angle, "inner" refers to between two straight lines to be truncated; "Wrong" means staggered, on both sides of the third straight line. (One corner is on the left side of the third line, and the other corner is on the right side of the third line).

i.e., "i.e.", "i.e.", i.e., i "Inner" means between two straight lines that are truncated.

Solution: (1) 2= b (known).

ab de (equal isotope angles, two straight lines parallel).

2) 1= d (known).

AC DF (equal internal misangle, two straight lines parallel).

3) 3+ f = 180° (known).

AC DF (complementary to the internal angles of the same side, two straight lines parallel).

The point at which the distance to the three sides is equal is the intersection of the bisector of the three inner angles of the triangle. That is, the one point you are looking for is the intersection of the bisector of the inner angle and the other three points are the intersection of the bisector of the outer angle... Only.

(1) AB is parallel to DE, because the isotopic angle is equal, the two lines are parallel (2) AC is parallel to DF, because the internal error angle is equal, the two lines are parallel (3) AC is parallel to DF, because the same side of the internal angle is complementary, the two lines are parallel to take it!!

The sum of the outer angles of all convex n polygons is equal to 360°, and the sum of the inner angles is equal to the first (n2) 180°.

1. The inner angle of this polygon is 180°, which should be a triangle.

2. If the sum of the internal angles is 720°, then (n 2) 180°=720°, and the solution is n=6.

As long as the sum of the outer corners of the application is 360, it will be fine.