Physical Water Pressure Questions Urgent need to answer, Physical Questions: Is Water Pressure?

The pumping station is built on the ground floor of the high-rise building, and the appropriate pipe diameter is selected according to the water flow of the high-rise building, and it is estimated that the pump with a head of 35 meters can be used to a height of 28 meters, and the installation height of the centrifugal pump (the height of the pump shaft to the lowest water surface of the suction tank) is generally 2 5 meters.

This problem cannot be solved by a simple pressure formula, and the pump head must be determined by the hydraulic calculation of the pump line.

For a simple pipeline, the pump head h can be calculated using the following formula:

h =(z2-z1)+slq^2

Where: H - pump head, Z2 - outlet elevation, Z1 - pump suction pool water surface elevation; s - pipeline friction; l - pipe length; q – Flow.

The water supply pipeline of high-rise buildings cannot be regarded as a simple pipeline, but a complex water supply system with multiple forks and even rings, which is more complicated to calculate. For details, please refer to books such as "Water Pumps and Pumping Stations" and "Building Water Supply and Drainage Engineering".

The general water pump cannot be installed higher than ten meters, and it is not left to care, as long as the power is large enough.

Do you mean a pump or a water tower?

The pump doesn't say the height, right?

The water tower can be solved by using the principle of the communicator, which is more than 28m.

With a pump, the tower was built at a height of 19 meters.

1) The tower is built at a height of 19 meters, and using the principle of the communicator, the water can reach a height of 19 meters.

2) The reuse pump can pump the water up to about 10 meters high, and you can make the water ** to 28 meters.

What the brother said is very reasonable, the water pump has a lifting type and a pumping type, and the pumping type cannot be higher than the height of the water column at an atmospheric pressure! The current question is not clear and detailed, so I don't know what this question is asking.

The pressure of the water is related to the buoyancy of the water.

The pressure and pressure on each surface of the object in the water are related to the depth (p pgh), so the pressure on the deeper the object is greater, so the resultant force of the water pressure on the surface of the object is always vertically upward, which is the reason for the buoyancy to occur.

Taking a cube-shaped object in water as an example, the water has pressure and pressure on its upper, lower, left, right, front and back six surfaces, and the pressure and pressure of the water on the front and rear sides and Hengchang quietly on the left and right sides are balanced and can be counteracted, that is, the resultant force of the pressure of the water on the four sides is 0, and the pressure on the upper and lower surfaces will be greater than the upper surface due to the different depths in the water, and the pressure on the two surfaces is the same, their resultant force is not 0, and the direction is vertical upward, The resultant force of the whole object, i.e., the buoyant force, is equal here to the net force of the pressure of water on the upper and lower surfaces, and the direction is vertical and upward. The buoyancy of other irregular objects in the water is also caused by the combined force of the pressure exerted by the water on the surfaces of the object.

Horizontal component: The total hydrostatic pressure acting on a 2D surface is equal to the total hydrostatic pressure acting on the lead projection surface of the surface. According to this point, the pressure distribution map of the left and right sides of the surface is made respectively, and the more special one is h1=2h2, so after the pressure on the left and right sides is canceled, the shape of the pressure distribution map on the left is:

Above h2 is a triangle, and below h2 is a rectangle. From this, the magnitude and point of application of the horizontal component can be determined.

Plumb weight: draw the pressure body on the left and right, the upper part of the left side is projected from the surface boundary to the free liquid surface, and the direction of the pressure body is downward, and the lower part of the left is projected from the surface boundary to the free liquid surface, and the direction of the pressure body is upward, so the upper part of the pressure body is offset by the lower half. For the right one, in the same way, the pressure body is directed downwards.

After the pressure bodies on the left and right sides are canceled, the magnitude and application point of the plumb weight component can be calculated.

I can draw a picture if I need to.

Is there a picture? I didn't imagine what a model it was.

First of all, you don't use a trachea, because the trachea is ventilated at both ends. You're supposed to be using a test tube.

Secondly, the atmospheric pressure plus water pressure is much larger than the air pressure in the tube? In fact, the big difference is the water pressure at the horizontal position of the nozzle, because the inside of the pipe is atmospheric pressure, and the outside of the pipe is atmospheric pressure + water pressure.

If you do the math of the difference, which is the water pressure at this depth, it's actually very small, it's not enough to compress the air in the tube and squeeze the water into it (in fact, there is still a little bit of water being pressed into it, but this value is too small and too small), and if you dive deep enough, then you can see that some of the water will enter the duct. If it's deep, it's deep, it's deep... Then your tube will explode...

It's too much pressure ...

The trachea should form a negative pressure before water can enter, you first seal a head of water!

The atmospheric pressure at the same altitude is equal, unless the air in the duct is removed first.

Water pressure and air pressure are equal; One kilogram of air pressure is equal to one kilogram of air pressure.

Formula P Water = PGH

It's just the pressure generated by the water, not the air pressure, in fact, the person is 2m underwater

The pressure to be subjected to.

It should be the pressure of the water plus the air pressure at that time.

Just say"Water pressure at a depth of one meter", which has nothing to do with atmospheric pressure.

If it is said"What is the pressure at a depth of 1 meter in water? "When the atmospheric pressure value is given, the pressure here should be equal to the water pressure at a depth of 1 meter, plus the atmospheric pressure at that time.

The residual air in the air duct passes through the water pressure at the mouth of the air duct plus the pressure of the atmosphere, and it will be compressed, knowing that it is equal to the sum of the outside water pressure and atmospheric pressure.

The discomfort in the water is mainly chest tightness, in the standard atmospheric pressure, the lungs and the outside world are connected, the internal and external pressure is balanced, so you will not feel uncomfortable, after immersion in the water, the pressure on the outside of the body is equal to a standard atmospheric pressure plus the pressure of the water, the external pressure is greater than the internal pressure, so there will be a sense of pressure, if the lungs can be filled with water, and the external water is connected, it will not feel any discomfort (of course, it is not possible).

If you are two meters in the water, you will bear it.

The atmospheric pressure is combined with the pressure created by two meters of water.

Because there is already one on the surface of the water.

Atmospheric pressure.

p= ghp: pressure.

The density of the water. g: acceleration due to gravity.

h: Height. So h=

In addition: a simplified estimation method - generally speaking, 10 meters of water column is equal to about one atmosphere.

It is approximately equal to one atmosphere, which is about 8m of water head.

When the water is still holding the orange chaotic section, the pressure in the water is the same ().

a.Zhengwu is fighting.

b.Mistake. Correct answer: B

1.The buoyancy received is:

2.buoyancy = density of water * g * volume of immersion; So the buoyancy experienced when fully submerged is 3Spring dynamometer readings.

4. Add salt, the principle of selecting seeds with brine is to use the buoyancy of brine is that those seeds that are not full float up, and now the seeds are not floating, indicating that the density of the water is not enough, and salt should be added (assuming that the volume of the seeds remains the same).

The pressure sensor in the washing machine reflects the pressure difference between the inside and outside of the sensor, when there is no water in the bucket, the sensor pipe communicates with the outside atmosphere through the opening, the inner and outer atmospheric pressure (actually refers to the pressure) is equal, the pressure (pressure) difference is zero, and the pressure sensor indicates zero. When the water is injected into the barrel, the water level rises, according to the knowledge of the internal pressure of the relevant liquid, when the opening of the sensor pipe is below the liquid level, the internal pressure generated by the corresponding liquid level height can be transmitted to the air in the pipe of the sensor through the opening and sensed by the sensor, and the pressure (pressure) difference between the inside and outside gas is displayed, and the pressure (pressure) difference is generated by the liquid level height (that is, the water inlet height in the bucket), and the magnitude is equal to the product of the liquid density and the liquid level height h, and has no relationship with the indoor air pressure. Therefore, the pressure (pressure) perceived by the sensor actually directly reflects the height of the liquid level in the barrel, and the pressure generated by the height of the water column of 10 meters is calculated as 1 atmosphere, when the sensor senses the atmospheric pressure, the opening is 1 meter below the water surface, or the water level in the barrel reaches 1 meter.

The pressure should be balanced, p = density * h * g. This height h is the difference between the water level in the air chamber and the water level in the barrel.

The pressure in the air chamber is p

1. This is the principle of atmospheric pressure, when the piston moves upward, the pressure between the activity and the water decreases, and under the action of atmospheric pressure, the water surface rises. 2. Because there is gas in the tube, and the tube is not vacuum, the air pressure difference between the inside and outside of the tube is not 760mmHg.

Atmospheric pressure can enter the top of the water, creating downward air pressure, and the water falls under the force of gravity.

Barometric pressure is the atmospheric pressure acting on a unit area, i.e., the gravitational force exerted on a vertical column of air that extends up to the upper boundary of the atmosphere per unit area. The famous Magdeburg hemispheric experiment proves its existence. The international unit of air pressure is Pascal, abbreviated as Pa, and the symbol is Pa.

1]。In meteorology, people generally use kilopascals (kpa) or hectopa (hpa) as the unit. Other commonly used units are:

bar (1 bar = 100,000 Pa) and a centimeter of mercury (or centimeters of mercury). Air pressure varies not only with altitude but also with temperature. Changes in air pressure are closely related to weather changes. [2]

Do you have a diagram of the washing machine?

The pressure in the air chamber is equal to one atmosphere plus the relative head of the barrel to the air cell.

I'm rubbing, that's what you're doing.

p= *g*h, i.e.: pressure = density of the liquid * gravitational constant * height. It has nothing to do with the diameter of the drain pipe. Here the pressure should be 1000 (density of water) * gravitational constant) * 8 (height) = 78400 pascals (pressure).

f=ps, where f is the pressure, p is the pressure, and s is the area of the force. If the diameter of the drainage pipe is the same, the pressure here f = 78400 * circle area * radius squared) = 34619 (N), and then divide by the gravity constant, 3532kg, that is, about tons of something pressed on it.

You can't feel the pressure, the drain pipe will be filled with water, because the word (bottom) is used, so the pipe is longitudinal, it is impossible to break the blockage longitudinally, even if it is flushed, there should be a water room in the drain, at the bottom because of gravity can not be blocked, but not in the water.

The formula for calculating pressure is p= gh = 1000kg cubic meters * 10n kg * 8m = 8n square meters.

Cross-sectional area s = (75 2 100) square* square meters.

f=ps=8*

The weight of an egg is about 50g-60g, g=50 1000*10=, which is equivalent to the weight of about 7 eggs.