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Failing only in mathematics: 1-94%-4%=2%, failing only in Chinese: 1-90%-4%=6%, passing in both Chinese and mathematics: 1-4%-2%-6%=88%, total number of students in the class: 44 88%=50.
The diameter of the largest circle in the square is equal to the length of the sides of the square, and the area of the square = the length of the sides.
Area of the circle = square of the radius.
Suppose the side length is 1, then the area of the square is: 1 1 = 1, and the area of the circle = 1 2= so the answer is: ( 100%=
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Method 1: Number of students passing in Chinese + Number of students passing in mathematics + Number of students who fail both subjects - Number of students who pass both subjects = Number of students in the class.
Therefore, the number of students who pass both subjects accounts for 90%+94%+4%-1=80%, so there are 44 80%=55 students in the class.
Method 2: Set up x number of people in the class.
Then the number of language passers is.
The number of passing students in mathematics is.
The number of students who fail in Chinese and mathematics is.
So x= -44
So x=55 people.
2.Remember that the side length of the square is 1, then the area of the square is 1, the radius of the maximum circle is 1, and the maximum circle area is 4
The area of the square is larger than the area of the largest circle inside it.
1-Pai 4) 1=
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Question 1: There are people who only fail in mathematics: 1-94%-4%=2%, and those who only fail in language are:
1-90%-4%=6%, so both Chinese and Mathematics passed: 1-4%-2%-6%=88%, so the total number of students in the class is: 44 88%=50.
Question 2: The diameter of the largest circle in a square is equal to the length of the side of the square, and the area of the square = the length of the side The length of the side.
Area of the circle = square of the radius.
Suppose the side length is 1, then the area of the square is: 1 1 = 1, and the area of the circle = 1 2= so the answer is: ( 100%=
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The diameter of the largest circle in the square is equal to the length of the sides of the square, and the area of the square = the length of the sides.
Area of the circle = square of the radius.
Suppose the side length is 1, then the area of the square is: 1 1 = 1, and the area of the circle = 1 2= so the answer is: ( 100%=
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There are people who only fail in mathematics: 1-94%-4%=2%, and those who only fail in Chinese: 1-90%-4%=6%, so there are people who pass both Chinese and mathematics:
1-4%-2%-6%=88%, so the total number of people in the class is: 44 88%=50 =
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Let the first digit of the number be x, and the last two digits are a (a is a two-digit number), then the original number = 1000x+a, and 9xyz = 9*(100x+a) 1000x+a=9*(100x+a).
2a=25x, only a=2 when a=25, or x=4 when a=50 or a=75 x=6, the number of the box is respectively
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1.Answer: 643210.
Answer: The sum of the numbers is determined, and there is no repetition, but also the maximum, then only the more digits of this number, the larger, and the more digits, only the smaller each number, the more digits can be, from 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 of the 10 numbers from top to back, then you can choose 0, 1, 2, 3, 4, 6 these five numbers.
2.Answer: 150 meters.
Answer: From the first time A overtakes B to the second time B, the distance between is exactly 400 meters, then the speed difference between A and B = 400 (22-6) = 25, then the distance A runs more in the first 6 minutes = the distance A runs behind B = 25 * 6 = 150
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1。A natural number, the sum of the numbers on all sides is 16, and all the numbers are different, and the maximum number that meets the requirements is (643210).
2。A and B practice race walking on the 400-meter track in the playground, both of them start at the same time, A is behind B at the time of departure, A overtakes B for the first time 6 minutes after departure, and A overtakes B for the second time at 22 minutes. Suppose the speed of the two remains the same, and A is 150 meters behind B at the time of departure.
400 (22-6) = 25 (m).
25 6 = 150 (meters).
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Maximum: 64321
Answer: 150 meters.
After departure, A overtakes B for the first time to B's second time, and it takes 22 6 16 (minutes);
The difference in the distance of the second excess is 400 meters in one lap, and A walks 400 16 25 (meters) more than B per minute;
The first time to overtake the catch-up distance 25 6 150 (m).
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The cheetah pursues the hare 35 meters ahead. The cheetah has a big step, he runs 3 steps and the rabbit runs 7 steps. But the rabbit moves fast, and the cheetah can run 4 steps in the time it takes for the cheetah to run 3 steps. How far does the cheetah have to run to catch up with the rabbit.
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1.In 100, choose a number of numbers so that their sum is greater than 3, so how many numbers should you choose?
2.Use the nine numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 to write three fractions of equal size. (Use once for each number).
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Let us give x sheets, then the formula is 90 + x 4 (60 x), and if we solve x 30, then we need to give 30 sheets.
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90+60=150
Xiao Qiang wants to give Xiao Ming 30 sheets.
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Aren't you almost all right, send 30 tickets, Xiao Ming has 120, Xiao Qiang has 30. Isn't it just that Xiao Ming's picture is Xiao Qiang's 4?
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Give 30 cards 90 + 60 = 150 150 (1 + 5) = 30 So Xiao Ming 120 Zhang Xiaoqiang 30 cards is right.
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