Today, there are chickens and rabbits in the same cage with 23 heads and 60 feet under them

There are 16 chickens and 7 rabbits.

Analysis]: This question tests the ability to apply the idea of "chickens and rabbits in the same cage" to solve problems.

There are many formulas for chickens and rabbits in the same cage, but as long as you master the principle of the idea of chickens and rabbits in the same cage, you don't have to memorize these formulas, and the hypothetical method can basically solve all the problems of chickens and rabbits in the same cage

Suppose it is all chickens, 23 chickens, a total of 23 2 = 46 (chickens), for every less chicken there is one more rabbit, the total number of legs will be 4-2 = 2 (only), now the actual number of feet is 60-46 = 14 (only) more than the assumption, so there are 14 2 = 7 (rabbits) and 23-7 = 16 (chickens).

The column formula is shown in the figure above.

Suppose all chickens: 23x2=46 60-46=14 14 2=7 rabbits, chickens 23-7=16 (chickens).

Suppose all rabbits: 23x4 = 92 92-60 = 32 32 2 = 16 chickens have 16; Rabbits have 23-16=7 (only).

Equation: The solution has x chickens. then there are 23-x rabbits.

23-x）x4+2x=60

x=16

Chickens and rabbits in the same cage. There are 21 heads, and the lead has 54 legs, so there are (15) chickens, (6) rabbits, and 4*21-54) (4-2) Huai brothers.

15 (only) 6 (dust liters).

Chop the feet and reduce the head, rabbit 54 2-21 = 6, chicken 21-6 = 15.

There are a total of 15 trapped rabbits and 6 chickens. Formula.

The idea of this problem is to calculate all the animals according to rabbits, drag 4 legs all the time, and then use the difference in legs to find the number of rabbits.

20x2=40 (only).

54-40=14 (only).

Rabbits: 14 (4-2) = 7 (only).

Chickens: 20-7=13 (pcs).

Today, there are chickens and rabbits in the same cage, with a total of 20 heads and 54 legs. There are (13) chickens and (7) rabbits.

Assuming it's all chickens, then rabbits have:

10 chickens: 20-10=10

A: There are 10 chickens and 10 rabbits

So the answer is: 10, 10

Chickens and rabbits in the same cage Huibi, a total of 20 heads, 56 skin source feet, how many chickens and rabbits are there?

Chicken (4, 20-46), (4-2).

12 pcs. Rabbit front grip 20-12 = 8.

20x2=40 (only).

54-40=14 (only).

Rabbits: 14 (4-2) = 7 (only).

Chickens: 20-7=13 (pcs).

Today, there are chickens and rabbits in the same cage, with a total of 20 heads and 54 legs. There are (13) chickens and (7) rabbits.

Today, there are chickens and rabbits in the same cage, with a total of 20 heads and 54 legs. There are (13) chickens and (7) rabbits.

With x chickens, there are 20-x rabbits.

2x+4(20-x)=54

2x=26x=13

There are x chickens and (20-x) rabbits.

2x+4（20-x）=54

2x+80-4x=54

2x=-26x=13

There are (13) chickens and (7) rabbits.

1.Chickens and rabbits in the same cage problem solution: the first 30 are a total of 30 chickens and rabbits, assuming all rabbits, there are a total of 120 feet.

At this time, the rabbit has 120 more legs than the chicken, and for each chicken, there will be six legs less (2 more chickens, 4 less rabbits), so the chicken has (120-60) 6 = 10, then the rabbit has 30-10 = 20.

2.Binary Equation Solution: Let there be x chickens and y rabbits. then x+y=30 (a total of 30 heads), 4y-2x=60 (60 more feet), and the simultaneous solution is x=10, y=20.

Solution: Let there be x chickens and y rabbits, and the binary equation is arranged.

4y-2x=60

x+y=30

A: There are 20 rabbits and 10 chickens.

Chickens: 6, Rabbits: 6:

Chickens and rabbits in the same cage, a total of 12 heads, that is, chickens and rabbits a total of 12, if the rabbits in the cage are 2 feet on the ground, then there should be 24 feet, 12 less than the 36 in the question. The extra 12 legs are all rabbits, and each rabbit has 2 more legs than the chicken, so there are 6 rabbits, and the chicken also has 6.

There are 6 chickens and 6 rabbits.

Problem solving ideas: Method 1 The chicken has two legs and the rabbit has four legs, so 12 animals, each animal has at least two legs, a total of 12x2 legs.

That extra 36-24=12 legs are rabbits.

Because, each rabbit has two more legs than each chicken, so rabbits = 12 2 = 6 pcs.

Then there are 12-6 = 6 chickens.

Method 2: Set x chickens and y rabbits.

x+y=12,2x+4y=36

Solve the equation to get x=6, y=6

Foot chopping method: 36 2 = 18 Because at this moment it is equivalent to two animals at the same time to fold half of their feet, so 18-12 = 6 is the number of rabbits. Chickens are naturally also 6

Binary equation method: let the chicken have x and the rabbit have y to construct two equations x+y=12, 2x+4y=36Add and subtract the elimination method or bring in the elimination method to get 6 chickens and 6 rabbits.

Spoof algorithm: Suppose every time an order is given to the animals, the animals lift a foot. Then, after two consecutive orders, the chickens are lying on the ground, and all the rabbits standing on the ground are rabbits, and they are also rabbits with 2 legs, that is to say, the number of rabbits = (36-12x2) 2 = 6, so the number of chickens is also 6

Of course, the method of 1 and 3 is, to put it bluntly, 2

The method of deformation. ）

Set up a chicken and ask for a rabbit.

12 chickens and rabbits; Each rabbit has 2 more legs than a chicken; If they are all rabbits, then they must have 48 legs; Now there are 36 legs, (48-36) (4-2) = 6

So there are 6 rabbits and 6 chickens.