Today there are pheasant rabbits in the same cage, there are 70 heads on the top, and there are 188

The crux of the chickens and rabbits in the same cage problem: the same cage problem is the same. First of all, we will think of animals as the kind of animals that have more feet. In this question, it is first seen that 70 rabbits are all rabbits. Then do the quotient of the difference to get the answer.

Number of myriapods = (total number of feet - total head * number of feet of least animal) (number of feet of many animals - number of feet of few animals).

Rabbit: [188-(70*2)] 2=(188-140) 2=48 2=24

Chicken: 70-24=46

The problem is the same for turtles and cranes, as they have 4 and 2 horns respectively. Let's assume that they are all turtles.

1) Solution 1 (arithmetic):

The arithmetic formula: number of myriapods = (total number of feet - total head * number of feet of least animal) (number of feet of many animals - number of feet of few animals).

188-(70*2)] 2=(188-140) 2=48 2=24 rabbit x pheasant = 70-24=46

Solution 2 (Equation):

Let pheasant = x rabbit = y

then x+y=70 2x+2y=140

2x+4y=188

2y=48yrabbit=24

x pheasant = 70-24 = 46

2) Solution 1 (arithmetic):

282-140*2] 2=1 turtle 139 crane.

Solution 2 (Equation):

Let turtle = x crane = y

x+y=140 2x+2y=280

4x+2y=282

2x=2x=1 turtle 139 cranes.

Question 1: Because a1, s2, -2a2 are proportional sequences.

So(s2) 2=a1x(-2a2).

So (a1a2) 2=-2a1a2

s2=a1a2=0 or s2=-2, and then bring s2 into the second question: if you have a problem,,, decompose the original formula into s(n)+a(n+1)=s(n)a(n+1), and then separate the formula, a(n+1).

24 rabbits, 46 chickens (top).

139 chickens, 1 rabbit.

One turtle, 139 cranes. This seems to be right.

This is the problem of "chickens and rabbits in the same cage". This kind of problem can be easily calculated if you use arithmetic methods, and it is even simpler if you use column equations, which can be a one-dimensional one-time equation or a two-dimensional one-time equation. The binary equation is like this:

Let the pheasant be x and the rabbit be y, and the equation will be listed according to the problem.

x＋y＝35

2x＋4y＝94

Shift: y 35 x, substitution:

2x＋4(35－x)＝94

2x＋140－4x＝94

2x 46x 23, substitution:

y＝35－x

y 12 So, there are 23 pheasants and 12 rabbits.

(94a-35 2) 2

94-70) 2

12 pcs. 35-12 = 23.

A: There are 23 pheasants and 12 rabbits.

The problem of chickens and rabbits in the same cage. Now there is a cage for pheasants and rabbits. There are 35 heads on the top and 94 legs on the bottom.

Q: How many rabbits and pheasants are there? Solve with binary linear equations. So what to say?

gu ab l。Let's say the pheasant has one. Rabbit, with a b-compartment.

Then there are two equations. A plus b equals. Family.

Four coins are equal to 94. Sister, this binary equation.

Suppose the pheasant has x heads and the rabbit has y heads.

x+y=35, 2x+4y=94, and the solution is x=23, y=12

If there is a chicken and a rabbit B, there are: A + B 35, 2A + 4B 94

Solution: A 23, B 12

Set x chickens, 38-x rabbits.

2x+4(38-x)=106

2x+162-4x=106

2x=56x=28

28 chickens and 10 rabbits.

Assuming it's all chickens, rabbits have:

96-40 2) (4-2), 16 2, 8 (only);

Answer: There are 8 rabbits with losses

So the answer is defeat: 8

Solution: Suppose all rabbits have legs:

35x4=140 (only).

More than actual: 140-94=46 (only).

Therefore the number of chickens to be obtained is:

46 (4-2) = 23 (only).

The number of rabbits is:

35-23=12 (only).

35 heads, all rabbits, there are 35 4 140 feet, but there are actually 140 94 46 feet less.

Two less is enough to mean that there is one pheasant, so there are 46 2 23 pheasants, so there are 35 23 12 rabbits.

The answer is: if there are x chickens, then there are 35-x rabbits.

2x+4(35-x)=94

2x+140-4x=94

2x=46x=23

A: There are 23 chickens and 12 rabbits.

There are 23 chickens and 12 rabbits. You can have Y chickens and x rabbits. Then you can list two equations:

x+y=35;2y+4x=94,, and finally solve it. Because the chicken and rabbit both have only one head, x+y=35,,, and because the chicken and rabbit have two and four legs respectively, 4x+2y=94

Chickens have 2 legs and rabbits have 4 legs, assuming that all are chickens, 35 heads should have 70 feet, and 94 minus 70 to get 24, which is the extra feet of rabbits, you can find that rabbits are 12, and chickens are 23.

Assuming that all 35 heads are chickens, i.e., all have two legs, then 35x2 70 feet and the extra 94 70 24 feet are the other two legs of the rabbit, then the rabbit has 24 2 12.

There are 35-12 = 23 chickens.

(94-35*2) 2=12, a head corresponds to two feet, the extra is the rabbit divided by 2, rabbit 12, chicken 23, the landlord please give points, thank you!

Let the number of rabbits be x and the number of chickens be y. Yes.

x+y=35

4x+2y=94

Simultaneous equations, solved.

x=12,y=23

Rabbits have 94-35 more feet than chickens 2=24 feet. So there are 12 rabbits and 23 chickens.

There is chicken x, there is rabbit y

then there is a system of equations.

x+y=35

2x+4y=94

Just solve the system of equations.

x=23 y=12

So, there are 23 chickens and 12 rabbits.

There are x rabbits and y chickens. x y=35

4x 2y=94

x=12，y=23

There are 12 rabbits and 23 chickens

12 rabbits, 23 chickens.

Let the rabbit be x and the chicken be y

x+y=35

4x+2y=94 system of simultaneous solution equations.

Let the chicken have x and the rabbit have y and only list the equation: x=23 y=12

There is a chicken and a rabbit.

a+b=35

2a+4b=94

Solution: A 23, B 12

Chicken and rabbit are substituted.

x+y=35

2x+4y=94

2(x+y)+2y=94

i.e. 2y=24

y=12, that x=23

Chicken 23 Rabbit 12

Method 1:

Suppose it's all rabbits then there are legs:

35x4=140 (only).

More than actual: 140-94=46 (only).

Therefore the number of pheasants that can be obtained is:

46 (4-2) = 23 (only).

The number of rabbits is:

35-23=12 (only).

Method 2: Set the rabbit as x and the pheasant as y

x+y=35 ①

4x+2y=94 ②

Solution: x=12, y=23

The pheasant is a pheasant and has two legs. So it's still a matter of chickens and rabbits in the same cage.

If you count rabbits as chickens, each rabbit will have 2 legs (= 4 - 2). Then the total number of feet that are few = 94 - 35 2 = 24 only. So, the number of rabbits:

94 - 35 2) (4 - 2) = 12 number of pheasants = 35 - 12 = 23.

The answer is: if there are x chickens, then there are 35-x rabbits.

2x+4(35-x)=94

2x+140-4x=94

2x=46x=23

A: There are 23 chickens and 12 rabbits.

Now there are pheasant rabbits in the same cage, there are 35 heads on the top, and there are 94 feet under it, and the pheasant rabbits have their own geometric solutions: there are 99 rabbits.

4x=94-2(35-x)

4x=94-70+2x

4x-2x=94-70

2x=24x=12

Pheasant: 35-12=23.

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Today, there are pheasants and rabbits in the same cage, there are thirty-five heads on the top, and ninety-four feet under it.

Pheasant (4, 35-94) (4-2).

23 pcs. Rabbit 35-23 = 12.

The hypothetical method is a more common method for elementary school students Teaching the number of total rabbits into the number of decimals of the number of rabbits The number of simple integers is equal to the number of several Suppose all the chickens are subtracted from the number of feet to the number of feet of each rabbit Say yes The number of feet of each rabbit At first sight, the number of feet of each chicken is equal to the number of rabbits Using this formula, we can easily list the formula: Suppose there are 35 rabbits, the number of chickens is equal to 35 4-94 4-2 = 23, the number of rabbits is equal to 35 -23 = 12 For the convenience of memorization, someone summarized the formula Suppose it's all mecha authorization diagrams, there are a few more feet, a few fewer pigs, divided by the horns, and the difference is a polar rabbit.

94 2=47 47-35=12 35-12=23 There are 12 rabbits and 23 chickens, because the chickens are counted first, and the extra ones are rabbits, and the extra ones are half of the rabbits, and then subtract half to get the number of chickens. Check: 12 4 = 48 23 2 = 46 48 + 46 = 94

If there are x chickens, then there are 35-x rabbits.

2x+4(35-x)=94

2x+140-4x=94

2x=46x=23

A: There are 23 chickens and 12 rabbits.

There are x chickens and y rabbits.

Then there are: x+y=35(1), 2x+4y=94(2) simultaneous two equations, and the solution is: x=23, y=12

A: There are 23 chickens and 12 rabbits.

The answer is: if there are x chickens, then there are 35-x rabbits.

2x+4(35-x)=94

2x+140-4x=94

2x=46x=23

A: There are 23 chickens and 12 rabbits.

Solution: Chickens x and rabbits (35-x) are available.

Column equation: 2x+4(35-x)=94

Solution: x=23

So, the number of rabbits is 35-23=12.

A: The number of rabbits is 12 and the number of chickens is 23.

If there are x chickens, then there are (35-x) rabbits.

2x+(35-x)×4=94

2x+140-4x=94

2x=46x=23

35-x=35-23=12

The answer is: if there are x chickens, then there are 35-x rabbits.

2x+4(35-x)=94

2x+140-4x=94

2x=46x=23

A: There are 23 chickens and 12 rabbits.

62 chickens, bai

38 rabbits. Set x chickens, y rabbits.

x+y=100

2x=4y-28

x=62, y=38

The general step of solving a quadratic DAO equation by factorization zhi method:

1. Turn the right side of the equation to (0).

2. The left side of the genus equation is decomposed into the product of (two) factors.

3. Let each one-time equation be (0) to obtain two unary one-dimensional equations.

Fourth, the solution of two unary quadratic equations is the solution of the unary quadratic equation sought.