Elementary school math problems about selling clothes.

The original price of money-making clothes is 240 120% = 200, and the original price of loss-making clothes is 240 80% = 300

Money-making clothes earn 240-200=40, and loss-making clothes lose 300-240=60

So, the boss is losing, losing 20

The original price of one piece: 240 (1 + 20%) = 200 (yuan) The original price of another piece: 240 (1-20%) = 300 (yuan) 200 + 300 - (240 + 240) = 20 (yuan) Answer: 20 yuan is lost.

Lost. The original price of the dress that earned 20% was 240 (1+20%)=200 yuan, and the original price of the dress that lost 20% was 240 (1-20%)=300 yuan.

In this way, 200 + 300-240 * 2 = 20 yuan, so the boss lost 20 yuan.

240 (1+20%)=200 (RMB).

240 (1-20%)=300 (RMB).

200 + 300-240x2 = 20 (yuan).

The boss lost 20 yuan. The ** of two clothes is 500 yuan, and now the two clothes are only sold for 480 yuan.

Lost. The first piece is 240 (1+ yuan) and the second piece is 240 (yuan.

300 is greater than 200

A: Lost.

The cost of earning that piece is 200, and the cost of losing that piece is 300, and the two pieces are 500 for a total of 500, but the boss only sells it for 480 yuan, so it loses.

The selling price after the first 20% discount: 600

Let the purchase price be xx(1+25)=480

x=480/（

Profit of 100 sets: (480-384) 100 = 9600 and then 80% off the selling price: 480

Equal to the purchase price, not profitable.

So: the total profit is 9600 yuan.

You should eat it safely! Twenty percent is always that much, no matter what.

A total of x pieces of clothing cover dismantling are set up, and the cost of each piece is Y yuan. Then we get: (60-y)120=120y*20% and (60-y)120+(60*90%-y)*(x-120)=xy15% solution:

y=50,x=206 (Note: use this equation to get x as a decimal place, rounded up to 206).

Set the fabric a meter, jacket and pants x pieces, then a 200 * x + a 300 * x = a

Approximate the two sides to a, and get 1 120*x=1

x=120

A total of 120 sets can be made.

You said it was a question for the 5th grade of elementary school, and I forgot what formula I used, but 120 sets must be right.

x, y are algebras;

If the set price is reduced by x yuan, the profit per piece is 20-x yuan, and the weekly sale is 300+20x, then the profit is;

20-x）*（300+20x）=6000+400x-300x-20x²=6000+100x-20x²=20[300+x(5-x)];To make this equation large, you need to have x(5-x) maximum, and since x is a natural number, it is maximum when x=2 or x=3; The maximum profit is:

6000+100*2-20*4=6120；or 6000+100*3-20*9=6120;

If the set price increases by Y yuan, the net profit per piece is 20+Y, and the weekly socks sold are 300-10Y; then the profit is;

20+y)(300-10y)=6000-200y+300y-10y²=6000+100y-10y²=10[600+y(10-y)]；To make this formula maximum, you need y(10-y) to be maximum, i.e., maximum when y=5; The maximum profit is:

That is, when the price is 65 yuan, the weekly profit is the largest;

The base price of Weiling rose by 5 yuan, and Wang Slip made the largest profit.

Let the price be calculated at x yuan, the profit is maximum, (20-x) x (300 + 20x) is the extremum.

Let the price increase be y, the profit is the largest, (20+y) x (300-10y) to find the extremum.

What to ask?

The cost of a set earned is 120 (1+20%) = 100 yuan, and 120 100 20 yuan was earned.

The cost of a set of losses is 120 (1-20%)=150 yuan, and the loss is 150-120=30 yuan.

A total loss of 30-20 10 yuan.

The first set of purchase price: 120 (1 20%) 100 (yuan), earned: 100 20% 20 (yuan).

The second set of purchase price: 120 (1 20%) 150 (yuan), loss: 150 20% 30 (yuan).

30 20 10 (yuan).

Obviously, the business lost 10 yuan.

Solution: The first set of purchase price: 120 (1 20%) 100 (yuan), earned 100 20% 20 (yuan).

The second set of purchase price: 120 (1 20%) 150 (yuan), loss: 150 20% 30 (yuan).

The two sets of clothing were sold for a total of 120 + 120 = 240 (yuan), and the purchase cost 100 + 150 = 250 (yuan).

So, the business lost 250 240 10 (yuan).

There are a total of x pieces of clothes, and the cost of each piece is Y yuan. Then we get: (60-y)120=120y*20% and (60-y)120+(60*90%-y)*(x-120)=xy15% solution:

y=50,x=206 (Note: use this equation to get x as a decimal place, rounded to 206).

Set the cost of clothes to be a yuan per piece, and there are x pieces of this batch of clothes.

60-a）/a=

The solution is a = 50 yuan.

60x120+

Solution x = 205 pieces.

Set a total of y pieces set the original price x yuan 60 x) x cost price: 50 yuan a piece 10% off 54 pieces a piece.

y-120)x54+60x120－50y>/50y=15/100

??206 pieces.

I was wrong?

The cost of each piece is 60-60*20%=48, and there are x pieces in total.

60*120+(x-120)*60*90%-48x=

x = 600 pieces.

The original price of money-making clothes is 240 120% = 200, and the original price of loss-making clothes is 240 80% = 300

Money-making clothes earned 240-200=40, and loss-making rent-renting clothes lost 300-240=60

Therefore, the boss is at a loss of dust, and the loss is 20

The store sells clothes, the original price is 1200, and then it rises by 110%, which is double on the basis of the original price, and it can be calculated with the root formula 1200 110% 1320, which means that consumers have to spend 1320 yuan to buy this dress.

The mall lost 100 yuan.

Let the cost of A be x and the cost of B be y.

1+，x=1000，y=1500

That is, the total cost of goods A and B is 2,500 yuan, and the income from selling is 2,400 yuan, so the shopping mall loses 100 yuan.

To spend more: 1200 110 1320 (yuan).

Current price: 1200 1320 2520 (yuan).

27 is seen as 30

48 is seen as 50

So not enough.