How to chemically identify CH3CH3, CH3CH CHCL, CH2 CHCH2CL, CH3CH2CL ?

The upstairs is too complicated.

It can be solved with a solution of silver nitrate and carbon tetrachloride of bromine.

Dropwise addition of silver nitrate, CH2=CHCH2Cl immediately reacts to produce a precipitate.

Ch3CH2Cl, CH3CH=CHCL reaction is slow.

CH3CH3 does not react.

CH3CH2Cl, CH3CH=CHCL were identified by BR2 CCL4, and CH3CH=CHCL fading the carbon tetrachloride solution of bromine.

Simple, right.

First, it is cooled to the following (the boiling point of ethyl chloride is ), and CH3CH3 is distinguished; Then use bromine water to distinguish CH3CH2Cl (non-reaction); Hydrolysis in NaOH solution, CH3CH=CHCL hydrolysis to obtain CH3CH2CHh, the latter hydrolysis to obtain CH2=CHCH2OH, and then silver ammonia solution to distinguish.

1) After the oxygen cylinder is burned and absorbed with dilute NaOH, the AgNO3 solution is added dropwise, and the CH3CH3 is not precipitated by white AGCL.

2) After treatment with alcohol to KOH at room temperature, only CH2=CH2Cl will dissociate the chlorine in the molecule into inorganic chloride and show chloride ion reaction (i.e., the precipitation reaction of the same as above and AgNO3). None of the other compounds are visible. The reason is that CH2=CHCH2Cl has the characteristics of allyl structure, and the allyl cation is relatively stable, so the chloride ion can be freed.

3) The remaining CH3CH=CHCL and CH3CH2Cl can be identified by bromine water test, the former can react with bromine to fade the brown bromine water, while the latter has no change, so as to identify.

It's hexane because there are six carbon atoms in it.

Alkanes belong to saturated chain hydrocarbons, between its hydrocarbons and hydrocarbons, there is only a pair of electrons shared between carbon atoms, it is a carbon-carbon single bond, its carbon elements are -4 valence, it belongs to saturated hydrocarbons, it can be completely burned, the flame is bright and light blue, generating carbon dioxide and water. However, in addition to combustion, its chemical properties are very stable, it will not be oxidized by potassium permanganate solution, nor will it react with strong acids and bases, but it can replace and react with halogens (fluorine, chlorine, bromine and iodine, etc.) to generate a series of derivatives.

Alkanes are named by adding a number before the word "alkane" to indicate the number of carbon atoms. If the number of carbon atoms is between one and ten, it is expressed by the heavenly stem, that is, A, B, C, D, E, H, G, XIN, NON, and decane, while if the number of carbon atoms is more than ten, it is expressed by numbers, such as methane, ethane, propane, butane, undecane, etc.

Summary. These three compounds can be identified by the following methods:1

Reactivity identification: These three compounds have different reactivity and can be identified by different reactions. For example, CH3CH2CHHCH3 can be converted to aldehydes by oxidation reaction, while (CH3)3COH cannot be oxidized.

CH3CH2CH2CH2OH can be converted to 2-propanol by an acid-catalyzed racemic reaction, while the other two compounds cannot. 2.Melting Point Identification:

These three compounds also have different melting points and can be identified by determining their melting points. The melting point of CH3CH2CHHch3 is -120, that of CH3CH2CH2CH2OH is -126, and that of (CH3)3COH is -117. 3.

Mass spectrometry identification: The mass spectra of these three compounds are also different, and their mass spectra can be determined by a mass spectrometer. The mass spectra of each compound have their own unique peak positions and molecular ion peaks, and the structure of the compound can be determined by aligning the spectra.

These three compounds can be identified by the following methods:1Reactive identification:

These three compounds have different reactivity, and they can be identified by different reactions. For example, CH3CH2CHHch3 can be converted to aldehydes by oxidation, while round pre-lead (CH3)3COH cannot be oxidized. CH3CH2CH2CH2OH can be converted to 2-propanol by an acid-catalyzed racemic reaction, while the other two compounds cannot.

2.Melting point identification: These three compounds also have different melting points and can be identified by measuring their melt shock chain points.

The melting point of CH3CH2CHHch3 is -120, that of CH3CH2CH2CH2OH is -126, and that of (CH3)3COH is -117. 3.Mass Spectrometry Identification:

The mass spectra of these three compounds are also different, which can be identified by measuring their mass spectra by a mass spectrometer. The mass spectra of each compound have their own unique peaks and molecular ion peaks, and the structure of the compounds can be determined by aligning the spectra.

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Summary. Here are some commonly used identification methods: Flame test:

This method can identify compounds by looking at their color in the flame. CH3CH2CHHCH3 is isopropanol, CH3CH2CH2CH2OH is n-butanol, and (CH3)3COH is tert-butanol. They produce different flame colors when burned in a flame because they differ in their molecular structure and oxygen-containing groups.

By observing the difference in the color of the flames, it is possible to initially identify the difference between them.

Here are some of the commonly used methods for identifying glitz chains: Flame test: This method can identify compounds by looking at their color in flames.

CH3CH2CHHCH3 is isopropanol, CH3CH2CH2CH2OH is n-butanol, and (CH3)3COH is tert-butanol. They produce different flame colors when burned in a flame because they differ in their molecular structure and signal-containing oxygen groups. By observing the difference in the color of the flames, it is possible to initially identify the difference between them.

Chemical Reagent Reactions: Each chemical disturbant has its own specific chemical reaction that can be used to identify them. For example, alcohols can be identified using an acidic potassium dicarbonate solution.

Both isopropanol and n-butanol can produce precipitation, whereas tert-butanol does not. In this way, they can be identified by chemical reactions. Oxygen Stain Flavor Reagent Reaction:

This method uses an oxidizing agent to oxidize the compound. For example, an acidic solution of potassium permanganate can be used to oxidize alcohols. Both isopropanol and n-or silver-butanol can be oxidized to form corresponding aldehydes, while tert-butanol cannot undergo oxidation reactions because it does not have active hydrogen atoms.

This allows the detection of the product to identify different compounds.

Oxidizing Reagent Reaction: This method uses an oxidizing agent to oxidize a compound. For example, an acidic potassium permanganate solution can be used to oxidize alcohols.

Both isopropanol and n-butanol can be oxidized to form corresponding aldehydes, while tert-butanol cannot undergo oxidation reactions because it does not have active hydrogen atoms. In this way, the different compounds can be identified by detecting the products. Comparison of physical properties:

This includes identifying their physical properties, such as melting point, boiling point, and solubility. Comparing these differences in physical properties can provide clues to distinguish them. For example, isopropanol and n-butanol both have lower melting points and boiling points of tert-butanol, while tert-butanol is higher.

In addition, they also have slight differences in solubility.

Which reagent can be used to identify CH3CH2C CH with CH3CH=CHCH3? Why?

CH3CH2C CH and CH3CH=CHCH3 can be identified using bromine water (BR2). This is because CH3CH2C CH is an unsaturated alkyne, while CH3CH=CH3 is an unsaturated alkene. Bromine water can undergo addition reactions with unsaturated compounds.

When bromine water reacts with CH3CH2C CH, the bromine atom of the bromine water nucleus is added to the triple bond to form the product of bromoalkane. The reaction equation is as follows: ch3ch2c ch + br2 is changed to ch3ch2cbr=chbr and when bromine water reacts with ch3ch=chch3, the bromine atom of bromine water will be added to the double bond to form the product of bromoalkane.

The reaction equation is as follows: CH3CH=CHCH3 + BR2 CH3CHBRCH2BR The difference between the two compounds can be identified by observing the color change of the product after the reaction. The product of CH3CH2C CH reaction with parabromide scattered water is a colorless liquid, while the product of CH3CH=CH3 reaction with bromine water is a colorless liquid.

Therefore, the two compounds can be distinguished by the color change.

The CH3CCH3 chemical name is propylene.

1.Properties: colorless gas.

2.Melting point ( ).

3.Boiling point ( ).

4.Relative density.

Water 1):.

5.Relative vapor density (air 1): .

6.Saturation vapor pressure.

kpa）：。

7.Heat of combustion.

kj/mol）：－

8.Critical.

9.Critical Pressure (MPa):

10.Octanol Water Partition Coefficient:.

11.Flash point ( )30.

12.Ignite the temperature of the sensitive ( ) code to dismantle.

Methane and propane are alkanes in the same organic chemistry and have similar chemical properties. But there are also differences (1) structural formula:

The molecular formula of methane is CH4, and the structure formula is CH4

The molecular formula of propane is C3H8, and the structure is Ch3CH2CH3, and their chemical formula is CNH2N+2