A train is 75 meters long, travels 24 meters per second, and passes through a bridge in 30 seconds,

These 30 seconds is the time it takes for the train to enter the bridge from the front to the end of the train leaving the bridge, and the actual length of the bridge should be the locomotive.

The distance from the head of the bridge to the locomotive to the end of the bridge, so the length of a train should be subtracted from this 30-second distance, so the length of the bridge should be:

24*30-75 645 meters.

Encounter Problems. The speed and multiplied by time is equal to the distance and speed = distance time, i.e. 342 18 = 19 (meter seconds).

Train speed in meters and seconds).

2.Pursuit problem, the difference in speed multiplied by time equals the distance:

Going head to head means that the front position of the train is the same, and if the fast train overtakes the slow train, the front of the slow train and the rear position of the fast train are the same. This distance is the distance from the front of the fast train to the front of the slow train, and it is also the length of the fast train.

When the tail of the car is in line and advancing forward, the position of the rear of the car is the same, and when the fast train overtakes the slow train, the rear of the fast train and the front position of the slow train are the same. This distance is the distance from the end of the fast train to the rear of the slow train, that is, the length of the slow train.

So the first question can be solved:

Express train length: (18-10) * 12 = 96 (m).

Slow train length: (18-10)*9=72 (m).

The second question is that the fast car catches up with the slow train, that is, the front of the fast car reaches the rear of the slow car, and the two cars leave the tail of the fast car and leaves the front of the full car. We can divide this process into two parts: the fast car catches up with the slow car until the second car is in front of the car, and the front car is in line with the second car and leaves.

Obviously, the latter is known (12 seconds), and the former part of us refers to the slow seat, that is, the process of the head of the fast train from the tail of the slow train to the front of the slow train, obviously this is the time when the tail of the two trains is in line with the same direction at the same time, the time of the fast train exceeds the slow train by 9 seconds, so the time: 12 + 9 = 21 (seconds).

The third question is still assuming that a car does not move, and here it is assumed that the slow car does not move eastward. The problem of two cars meeting is equivalent to the problem of crossing a bridge, and the distance is the sum of the lengths of the two cars (think that the fast car is the car, and the slow car is the bridge; The distance is the length of the car + the length of the bridge): 96 + 72 = 168 (meters).

Then the speed of the fast train is the sum of the two speeds: 10 + 18 = 28 (meters and seconds).

The time required is: 168 28 = 8 (seconds).

3.The width of the train window is too small for the length of the train, and we think that the window is a point. Then there is:

The slow car looks at the fast car, and the car of 200 meters passes in 4 seconds, and the sum of the speeds can be obtained 200 4 = 50 (meters and seconds).

Fast cars look at slow cars, and 150-meter cars have a relative speed of 50 meters per second.

passed, the available pass time is 150 50 = 3 (seconds).

Summary. According to your meaning, with 24 30-75 = 645 meters, the length of this bridge is 645 meters, if you don't understand something, you can ask me, dear.

How many meters is a train that is 75 meters long, travels 24 meters per second, and passes through a bridge in 30 seconds?

According to your meaning, with 24 30-75 = 645 meters, the length of this bridge is 645 meters, if you don't understand something, you can ask me, dear.

I hope it helps you.,If there's no other problem.,Can you give a like?,Thank you(.

This problem can be solved using the column suffocation equation, assuming that the total length of the train is x meters. Since it can only be counted as passing from the locomotive on the bridge to the rear of the train. According to this column, the formula of the muffled hood state is 35 57 x+1770, and the equation is 225. So the train is 225 meters long.

Set the train length x meters, got.

35×57=1770+x

solution, x=225

The train is 225 meters long.

Summary. Dear, the calculation process is as follows: (825+75) 25=900 25=36 (seconds) It takes 36 seconds for the whole car to pass this bridge.

How many seconds does it take for a train to cross an 825-meter bridge with a total length of 75 meters per second, traveling 25 meters?

Dear, this question will take about two minutes, and I'll send it to you right away!

Dear, the calculation process is as follows: (825+75) 25=900 25=36 (seconds) It takes 36 seconds for the whole car to pass this bridge.

Dear, in the process of this question, you must add the length of the bridge and the length of the train together, and then divide it by the speed of the Congheng train, and you can calculate the time it takes for the entire fire seepage car to pass through the bridge. Chongqin.

（572+328）/20=45

A 328-meter-long train crosses a 572-meter-long bridge for 20 seconds, and the train travels 45 meters per second.

If you pass through the bridge, you actually have to look for the length of the bridge, plus the length of the train, they add up to more than 800 meters, and if you go through the bridge, it will always be ten meters per second.

The distance traveled by the train is the sum of the length of the bridge and the length of the train.

20 seconds.

In this question, you can calculate how many seconds it takes for the front of the car to pass the bridge.

320 25 = seconds).

It takes a few seconds for the rear of the car to pass the bridge.

180 25 = seconds).

Finally, it takes a few seconds for the entire train to pass through the bridge. seconds).