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There is a direct formula (1+2+
Extend the three unadjacent sides to give a large triangle with an area of 3*(1+2+
The area of a regular hexagon is 2 3 of the area of a large regular triangle
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: The point d is a straight line perpendicular to AC, AC is intersected with E, AB is crossed at F 1= 2, AED= AEF=90°, and AE=AE AED AEF AFE= ADE, FE=DE and CED= CEF=90°, CE=CE CED CEF CFE= CDE, CF=CD AFC= ADC and BC=CD=CF, then B= CFB then B+ ADC= B+ AFC=180°
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The area of the right triangle is 40 and is solved by the column equation.
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Take a look below and click to enlarge:
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There is a direct formula (1+2+
Extend the three unadjacent sides to give a large triangle with an area of 3*(1+2+
The area of a regular hexagon is 2 3 of the area of a large regular triangle
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As shown in the figure below:
According to the inscription, after cutting off the lower triangular pyramid along the red line, the upper part of the figure on the right side is obtained.
If you want to do a fill-in-the-blank question, I won't go into details, but I'll just talk about one: the height of the cut part is 1 6 of the overall height.
So, the height of the remaining part is 5 6 of the diagonal length of the cube.
h=√3×6×5/6=5√3
The m pattern in the formation problem is:
h=5√3=√75
So: m=75
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This is because the tetrahedron is an equilateral triangle with a base side length of 3 2 and is a regular triangular pyramid. The intersection of the height of the base and the bottom is the center of the triangle, as you say m 3.
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Let the radius of the bottom of the bucket be r, and the high level l
When it is horizontally squared, it occupies a quarter of the circumference, so when placed horizontally, the bottom area of the water is: r2-r2 2 (the area of a quarter of a circle minus the area of an equilateral triangle with a radius as the side length) The 2 after r is squared, and the slash is divided.
So the volume of water v1 = (r2-r2 2) times l the volume of the bucket: v bucket = r2 times l
v1 v bucket = ( -2) 4
Both r and l are gone.
Do you understand? If you don't understand, I'll give you the picture.
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abc is an equilateral triangle, and ad=be=cf, ae=bf=cd, and a= b= c=60°, ade bef cfd,df=ed=ef, def is an equilateral triangle phoenix feifei.
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Direct ruler pure hand-hitting.
Adopt it!
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I don't think so, because the title doesn't say that ab bc ac is three straight lines, and the topic is not rigorous.
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The egg hurts, I want to do it with trigonometric functions, but it's too complicated...
Pick me, I'm serious about it
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