Find a few math problems geometry diamonds .

1.In rhomboidal ABCD, E is the midpoint of AB, and DE is perpendicular to AB, so AE= 1 2AD. In a right triangle, the sides of the 30-degree angle pair are half the hypotenuse, so the angle dae = 60.

The degree of abc = 120 The side length of the rhombus is 2, find the area of the rhombus = ab*de= 2* the root number is set to the rhombus abcd, and the angle c is the angle of 108 degrees.

With point C (the vertex of the larger corner) as the center of the circle and Cb as the radius, points E and F are intercepted on AB and AD respectively. Even EF, CE, CF.

Then the triangles AEF, EFC, CBE, CDF are the four required isosceles triangles.

2.Let the diamond-shaped ABCD, angle A = angle C = 108 degrees, angle B = angle D = 72 degrees.

With C as the center of the circle and Cb as the radius, the E and F points are intercepted on AB and AD. Even ef.

The triangle BCE, ECF, FCD, and is three isosceles triangles with a vertex angle of 36 degrees.

The triangle AEF is an isosceles triangle with a top angle of 108 degrees.

3.Use a diagonal line in 4 equal parts, where the two equal parts add up to an acute isosceles triangle. The remaining two parts are an 18-degree isosceles triangle with a short diagonal as the base, and the remaining part is exactly two isosceles triangles.

4.Use a diagonal line in 4 equal parts, where the two equal parts add up to an obtuse isosceles triangle. The remaining two parts are made with two obtuse isosceles triangles with the two original sides as the base, and the bottom angle is 36 degrees. The rest can be exactly an isosceles triangle.

The second question is very easy to do, in the right triangle AEB, EB=, so the angle B=60 degrees. I'm sure you can handle it!

AH CF, AF CH, AFCH are parallelograms.

and ach= dch= odh= aod, ah=ch,, afch is a diamond.

Brother tells you that the quadrilateral AFCH is definitely not a rectangle. You have a problem with the topic. It's diamond-shaped.

**Cannot be plugged in. Look at the text.

1) From the meaning of the question, BCA=60 = F= ACD, so AB=2BC=CF

In ADC, ac=de, acd=60

So ad=cd=ac=cf=af

Therefore, the quadrilateral AFCD is diamond-shaped.

2) The quadrilateral ABCG is rectangular.

After e, EF is perpendicular to AB, so AG EF BC is because BC=CE AC=2BC

So e is the ac midpoint.

So f is the midpoint of ab and e is the midpoint of bg.

So EF is the median line BC=AG=2EF

Because of BC AG

So the quadrilateral ABCG is a parallelogram.

And because AC and BG divide each other equally.

So the parallelogram ABCG is rectangular.

Rotate RT abc 60 degrees to get RT dec because dec e knows that the angle ACB is 60 degrees on the AB edge.

Getting the angle bac cde is 30 degrees and you can know that the side bc is half the side ac.

There is RT ABC flipped 180 degrees along the AB edge.

Get half of bc=fb=ac and ac=dc known.

So fc=dc and the angle fac=bac is twice the angle fac=60 degrees.

That is, FA parallel cd has fc=dc

So it is prismatic.

The circumference of the rhombic ABCD is 16cm, DAB = 60 °, de ab, DF BC are EF, then DB = (4) cm, ac = (4 3) cm def circumference = (6 acres with 3) cm, the area of the rhombus ABCD is resistant to this Zheng Xun = (8 3) cm

Solution: Connect the diamond-shaped short diagonal.

Because the circumference of the diamond is 48cm

So the side length of the diamond is 12cm

This gives you an equilateral triangle.

So one of the inner angles of the rhombus is 60°

So the degree of the adjacent inner angle is 120°

First of all, you need to grasp the characteristics of the rhombus: the sides of the rhombus are equal in length, the opposite sides are parallel, the diagonals are perpendicular to each other, and the diagonals are bisectors of the inner angles.

So the side length is 48 4=12

Draw the diamond and its diagonal, the intersection of the diagonal line and any two adjacent fixed points of the diamond form a right triangle The diagonal is 12 and half is 6, and this side is half of the hypotenuse 12, so the angle corresponding to the length of 6 right angles is 30 degrees, so the inner angle corresponding to the diagonal of length 12 is 30 * 2 = 60 degrees, and the other obtuse angle is of course 180-60 = 120 degrees (the sum of the inner angles of the parallel lines is equal to 180).