The master and apprentice work together to process a batch of parts

The result is 25 parts per hour for the master and 15 parts per hour for the apprentice.

Analysis: This question examines the application of engineering problems, from the meaning of the question, if the master processes x parts per hour, the apprentice processes the number per hour (x-10), find out the equivalent relationship, and list the equation to solve.

The process of solving the problem is as follows:

Solution: Set the master to process x parts per hour, and the apprentice to process x-10 parts per hour. Column:

6x+8(x-10)=270

6x+8x-80=270

14x-80=270

Shift 14x = 270 80

14x=350

x=2525-10=15 (pcs).

A: The master processes 25 parts per hour, and the apprentice processes 15 parts per hour.

Root-finding method:

General approach. There are five steps to solve a one-dimensional equation, i.e., denominating, deparentheses, shifting terms, merging similar terms, and coefficients to 1, all of which are performed according to the properties of integers and equations.

In a univariate equation, the denominator step is usually multiplied by the least common multiple of each denominator, and if the denominator is a fraction, it can be multiplied by the reciprocal of the fraction on the denominator for the other parts of the term.

If there is an irrational number on the denominator, you need to rationalize the denominator first.

Value significance: The unary equation can solve most of the engineering problems, travel problems, distribution problems, profit and loss problems, integral table problems, billing problems, and number problems. If you use only arithmetic, some problems can be incredibly complex and difficult to understand.

The establishment of the unary equation model will be able to find the equiquantity relationship from the practical problem and abstract it into a mathematical problem that can be solved by the unary equation. For example, in a Diophantine problem, it may not be possible to use an integer alone, but finding the "age" as an equiquantitative relation through a one-dimensional equation simplifies the problem.

Solution: Set up an apprentice to process x parts per hour.

8x+6(x+10)=270

x = 15 apprentices: 15 * 8 = 120

Master: (15+10)*6=150

The total number of units processed by the master and apprentice per day: 840 6 = 140 (pieces), and the number of units processed by the master per day: (840-140 2) (9-2), (840-280) 7,560 7

80 (pieces), the number of apprentices processed by hail early every day: 140-80 = 60 (pieces).

Answer: The apprentice adds 60 stools to imitate parts every day

The master processed 5x, and the apprentice Yuansun processed 3x, for a total of 8x.

5x-3x=64

2x=64x=32

A total of 8x=256 feasts were processed.

Dear, give a good hail to close the chain, you can ask if you don't understand.

The solution master does x a day.

6x-30(6+3)=12

6x-270=12

x=282÷6

x = 47.

The master makes 47 a day.

Solution: Let the master do x per day (Note: Equivalence relationship: the total number of things done by the master - the total number of things done by the apprentice = 12).

6x-30(6+3)=12

6x-270=12

x=282÷6

x=47 Master makes 47 per day.

The apprentice made a total of 6 + 3 = 9 days, so the apprentice made a total of 30 * 9 = 270 parts, so the master made 270 + 12 = 282 parts.

So the master does it every day: 282 6 = 47.

For equations, let the master do x every day, according to the question, 6x-12=30*(6+3).

Solution x=47

The ergonomic effect of two people is 1 12

If the apprentice's efficiency is x, then the master's efficiency is 1 12 -x

According to the title: 18x+ 8(1 12 -x) = 118x+ 2 3 -8x = 1

10x + 2/3 =1

10x=1/3

x=1/30

The apprentice's ergonomics is 1 30, and the total product volume is "1".

Therefore the apprentice should go it alone for 1 (1 30).

30 days.

198 again 1 196 times 1 197

2.The apprentice processed 3,200 minutes more than the master, which is the time that the apprentice used alone.

The output of apprentices during this time = 3200 100 = 32.

The master and the apprentice process together, and the apprentice needs 100 * 2 3 = 200 3 to set the simultaneous processing time to x, and there is an equation.

x 90 + x (200 3) = 96-32 gives x = 2451 minutes (approx.).

Then the master's time = 2451 minutes and hours.

Apprentice's time = 2451 + 3200 = 5651 minutes and hours.

3.Originally, there were x language books, Y math books, and Z language books.

x*(1-2/5)=y(1-1/4)=z+30x+y+z=570

Solve equations. x=250 y=200 z=120

Hello, I'm glad that the pants are rolling big for you

There are x parts in this batch.

List the equations according to the title:

150:30% x 2=50% x 2:x 2 solution: x=2000

There are a total of 2,000 parts in this batch.

If I can help you.

Please be satisfied in a timely manner

Give people roses and leave a lingering fragrance in your hands

Help each other and make progress together

Question comprehension hours, the master and apprentice processed 21 parts, and then processed another 9 hours, the master had a total of 42 more parts than the apprentice;

That is, the master processed 42 more parts than the apprentice in an hour. That's easy to calculate.

Solve with binary linear equations. Design: The master processes x parts per hour, and the apprentice processes y parts per hour.

Solution: {1 1 multiply both sides to get: 1

2 2 Multiply both sides to get: 2

1 minus 2 to get: y=5 Substitute y=5 into 1 to get:

x=9x=9 (hours) y=5 (hours).

A: The master processes 9 parts per hour, and the apprentice processes 5 parts per hour.

1 hour, 2 people for a total of 21.

1 hour, more master than apprentice: 42 (pcs.)

Master per hour: (14+4) 2=9.

42 (9+, 4 more masters than apprentices per hour.)

4*pcs 21-6=15

The master processes 9 pieces per hour.

If the master processes x per hour, the apprentice processes (

Equation 9x-9*(

Simplify, we get x=28 3

Therefore, the master processes 28 3 per hour, and brings in the calculation, and the apprentice processes 14 3, 28 3-14 3 = 14 3, 14 3 * 9 = 42 per hour, so the answer is correct.