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Let the automatic operation be x days, and the manual operation is x+13 x (x+13)=1 14 x=1 is 1 day for automatic operation, and 1+13=14 days for manual operation.
The second problem is still simple to solve with chickens and rabbits in the same cage. Group 2 (680, 20%-118) (20%-15%)=360.
The first group is 680-360 = 320.
The third question is less conditional.
14-1 (1+120%) 30=4 11 Originally accepted the processing task 32 4 11 14-32=1200 pieces.
It turned out to be 1200 30 = 40 pieces per day.
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Solution:1. If it takes x days for automatic operation, it will take (x+13) days for manual operation.
x/(x+13)=1/14
Solution x=1
x+13=14 (days).
A: It takes 1 day for automatic operation and 14 days for manual operation.
2.If the first group was originally planned to produce x pieces, the second group was originally planned to produce (680-x) pieces.
x(1+20%)+680-x)(1+15%)=680+118 to get x=320,680-x=360
A: The first group originally planned to produce 320 units, and the second group originally planned to produce 360 units.
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1. Set manual to x, automation to x 14
x-x 14=13 gives x=14
It takes 14 days for manual work and 1 day for automation.
2. Set up the first group originally planned to produce x, then the second group originally planned to produce 680-x20% * x + 15% * 680-x) = 118 x = 320 the first group 320 and the second group 360
Clause. The third or fourth questions are wrong, it should be that you sent the wrong questions.
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The time spent sailing along the water is equal to two-thirds of the time spent sailing against the current.
So the velocity of the water: the velocity of the reverse water = 3:2
Downstream speed = water purification speed + water speed = 20 + water speed.
Reverse water velocity = water purification velocity - water velocity = 20 - water velocity.
20 + water velocity) :(20 - water velocity) = 3:2
So, water velocity = 4
Downstream velocity = 20 + 4 = 24 km hours, that is, the speed of traveling 24 km per hour along the river is V, then B's speed is 5V 7
ab distance. Traveling in the same direction, the distance difference = ab distance = 6v 7
Speed difference = v-5v 7 = 2v 7
Catch-up time = (6v 7) (2v 7) = 3 hours: It takes 3 hours for A to catch up with B.
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1.Solution: Sailing against the current Sailing with the water (the same distance) Time 3 2
Speed 2 3
Downstream velocity = hydrostatic velocity + water velocity flow.
Backwater velocity = hydrostatic velocity Water flow velocity.
Solution: Let the water velocity be x kilometers per hour, 20 x = 2
20+ x 3
3(20-x )=2(20+ x)
x=42.Solution: Dog rabbit.
Stride size 3 2 (because the hound's stride is large, it runs 2 steps, and the rabbit runs 3 steps).
Step 3 4 (The rabbit moves fast, the hound runs 3 steps, the rabbit can run 4 steps.) )
Speed 3 3 4 2
Distance 9 8 (The speed ratio of hounds and rabbits is 9:8, so the ratio of distance they travel in the same time is also 9:8,).
Solution: Let the hound run 9x meters to catch up with the rabbit, 9x=8x+10
x=10 9 10=90 (m).
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1.Solution: Let the water flow velocity be x kilometers per hour.
Then (20+x) (20-x)=3 2
Solution: x=4
Then travel 20-4=16 kilometers per hour.
Algebra: 20 (2+3) 4=16 km Hour 2Solution: Suppose it takes x hours for A to catch up with B, as follows.
Ratio of time = 1 ratio of velocity.
That is: x solution gets: x=3
A: It takes 3 hours for A to catch up with B.
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If the velocity is x, then the velocity against the water is two-thirds x
x + two-thirds x = 20x2 = 40 So x = 24 (2) so that A's velocity is x, then B's is 5x 7
So the distance difference is 6x 7
The speed difference is 2x 7
So time 6x 7 divided by 2x 7 equals 3
So less than 3 hours.
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1. Set the water flow to V
20-v)/(20+v)=2/3
v=4 Therefore: 24 km h of downstream.
2. If A is x, then B is 5x 7
According to the inscription, the total distance is (x+5x 7)*
Time = distance speed.
x+5x 7)*hours.
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1. Set the water to travel x kilometers per hour, and the water flow speed is a kilometer per hour 20 + a = x
2--x20-a=3
The solution is a=4 x=24
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If you only ask about the distance between the home and the library, it is 4500 meters. Because Y represents the distance between Xiao Ning and Xiao Qiang, one was at home and the other was in the library at the beginning.
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Your topic does not match the graphics, and there are too many people in the title, so first unify the names of the people.
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The whole journey is 7 + 11 = 18 parts, A traveled a total of 7 3 = 21 parts, 80 kilometers is the distance of 21-18 = 3 parts, and the whole journey is 80 3 18 = 480 kilometers.
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Let the distance be l, and the speed of A is 7x, and the two people share the same time, then l 11x+(l-80) 11x=l 7x+80 7x is simplified, so that the denominator is the same to get l=216 km.
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Solution: Let B's velocity be x m-hours, then A's velocity is (x+1) m-h.
A's velocity time + B's velocity time = total distance.
x+1)×(40/60+
x m hours).
The velocity of A is (x+1) = meters and hours).
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