Knowing ab 0, a 2 ab 9b 2 0, find the value of lg a 2 ab 6b 2 lg a 2 4ab 15b 2 50

Let a=a 2-2ab-9b 2=0

then lg(a 2 ab 6b 2) lg(a 2 4ab 15b 2)=

lg[（a+5b)/(2a+8b)]

and a 2-2ab-9b 2 = (a-b) 2-10b 2 i.e. a-b=+ or -b* root number 10

Get a b = 1 + root number 10, 1 - root number 10 where 1-root number 10 is negative number and"A and B have the same name"The proposition wants to be reversed, so a b = 1 + root number 10

Final Answer: lg(a 2 ab 6b 2) lg(a 2 4ab 15b 2) =

lg[（a+5b)/(2a+8b)]=

lg[(6+root:10)2(5+root:10)].

This one is more difficult, I consulted my sister, it seems to be the same as the one above:

Let a=a 2-2ab-9b 2=0

then lg(a 2 ab 6b 2) lg(a 2 4ab 15b 2)=

lg[（a+5b)/(2a+8b)]

and a 2-2ab-9b 2 = (a-b) 2-10b 2 i.e. a-b=+ or -b* root number 10

Get a b = 1 + root number 10, 1 - root number 10 where 1-root number 10 is negative number and"A and B have the same name"The proposition wants to be reversed, so a b = 1 + root number 10

Final Answer: lg(a 2 ab 6b 2) lg(a 2 4ab 15b 2) =

lg[（a+5b)/(2a+8b)]=

lg[(6+root:10)2(5+root:10)].

You believe it, it must be right!

A -2ab-9b = 0 and both sides are divided by b (b ≠0) to get (a b) -2(a b) - 9 = 0

Solution: a b = 1 10

A and B have the same nameSo a b 0

a/b=1+√10

LG(A +AB-6B)-LG(A +4AB+15B)=LG[(A +AB-6B) (A +4AB+15B)]=LG (up and down divided by B at the same time).

lg=lg(1+2√10+10+1+√10-6)/(1+2√10+10+4+4√10+15)

lg[(6+3√10)/(6√10+30)=lg[(2+√10)/(2√10+10)=lg(√10/10)

lg10(-1/2)

Solution: obtained by a + b -2a-6b + 10 = 0: (a-1) +b-3) =0

a-1=0,b-3=0

a=1,b=3

a+b=1+3=4

Liu Lang Wenying, all the sesame seeds are open to the open and sincere for you to answer the brother's change.

Your early judgment is the driving force for us to insist.

A -2ab-9b = 0 and both sides are divided by b (b ≠0) to get (a b) -2(a b) - 9 = 0

Solution: a b = 1 10

A and B have the same nameSo a b 0

a/b=1+√10

LG(A +AB-6B)-LG(A +4AB+15B)=LG[(A +AB-6B) (A +4AB+15B)]=LG (up and down divided by B) = LG=LG(1+2 10+10+1+10-6) (1+2 10+10+4+4 10+15).

lg[(6+3√10)/(6√10+30)=lg[(2+√10)/(2√10+10)=lg(√10/10)

lg10(-1/2)

a^2－2ab－9b^2=0

A2 2ab + b 2 = 10b 2 i.e. |a-b|=√10|b|=√10b

Because a and b are both positive numbers, we can only get a=(1 + 10)b and substitute a into the calculation formula.

Because (a+b) is greater than or equal to 0，|2b-1|Greater than or equal to 0, so a+b=0, 2b-1=0, so b=1/2, a=-1/2. substitution, in the end to minus a quarter, I don't know if the result is right, the solution idea must be right......

∵a²+b²+4a-2b+5=0

a²+4a+4)+(b²-2b+1)=0∴(a+2)²+b-1)²=0

a+2=0，b-1=0

a=-2，b=1

a-b) (a+b).

-2-1) (-2+1).

-3) (-1).

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Solution: obtained by a + b -2a-6b + 10 = 0: (a-1) +b-3) =0

a-1=0,b-3=0

a=1,b=3

a+b=1+3=4

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Yours is the driving force for us to persevere.