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Solution: Draw a picture. In the case of a diagonal connecting rectangles, the length and width are right-angled, and in the case of a direct triangle with a diagonal of hypotenuse, hypotenuse = (length + width).
It is about <14dm
Some people may think that they are done here, but they are not.
Because this pool is a cuboid, the longest diagonal of the cuboid is a point from the upper plane to a point diagonal to the bottom plane, that is, the high and bottom sides are diagonally to the right angle. The box is a triangle with beveled sides, so the longest hypotenuse = [(4, 10) +3 ].
So it can't be completely overwhelmed.
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First, find the hypotenuse of the plane, and use the Pythagorean theorem to find the 4 times the root number 10dm
Then find the three-dimensional hypotenuse to get 13dm, so it can't be submerged.
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Think about it, the best way to put the longest is to put the diagonal diagonally.
The diagonal length of the side is: open root number (3 2 + 4 2) = 5 Then, the diagonal length is: open root number (5 2 + 12 2) = 13 The longest can only be put 13dm, so it cannot be completely submerged.
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Can be completely submerged;
According to the width and height of the pool, the length of its hypotenuse is calculated to be 5dm, and then the longest possible size in the pool is 12 square + 199 square root number, that is, 199 open root number, and the length of the metal rod is 14, and its square is 196
So it can be completely submerged.
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It can't be completely submerged, because the longest side of the box is its diagonal diagonal, and the calculated length is less than 14dm, so it can't.
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1 Let the specified date be x,2 [1 x+1 (x+3)] +1 (x+3) (x-2)=1
x=62 33 a
4 Make sure that all the brackets are added before you count ......x x-2 is x (x-2) bar ......It is the parentheses added according to the four rules of ......Change it to this, do you see it clearly, the following representation is 1 divided by x+3 and multiplied by x-2.
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1, 2+(1-(1 a+1 (a+3))x2)(a+3)=a to get a=6
2, a+b/c=b+c/a
a+b)ab=(b+c)bc
axa+ab=cxc+bxc
axa+axb+(b/2)(b/2)=cxc+bxc+(b/2)(b/2)
a+b 2) square = (c + b 2) square if a = b = c de 8 if a + b = -c ....de -13, k=-8 The title is unclear.
4. b** is m, sell is n, and the profit is (n-m) mCount it yourself 5, please add an expansion sign I can't see it clearly.
Still can't see clearly.
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1.The date is 6 days! Set the date to A, the efficiency of A, and B to C.
Then ab=(a+3)c and (b+c)x2+c(a-2)=(a+3)c, the solution of b = is brought into the first formula, and a 6 2First of all, the question you gave seems to be a little less conditional, there should be a is not equal to B is not equal to C, right? Or there are many answers, e.g. all equal to 1 then the answer is 8.
When the three are unequal, multiply the original three formulas respectively to get three new equations, and then subtract them respectively to obtain a+b+c=0 b+c=-1, that is, a=1, and then bring in the original equation to get b=2 c=-3, then the answer to this question can be brought in, if you want to calculate, you can assume that you can enter a piece of clothing. 4.Did you make a mistake in the title?
It's x+1 x—x+3 x-1=4, right? This kind of only needs to be divided and then solved by solving the binary equation, and everything else is pretty much the same! These are all personal misunderstandings, please understand.
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①(-4)×57+(-4)×43
Solution: Original (-4) (57+43) (4) 100 -400 -11 Thirty-nine and one-third)-11 Two-thirds Solution: Original -11 (thirty-nine and one-third + two-thirds) -11 60-11 40 -11 (60+40) -1100
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1: Solution: original (-4)x(57+43).
-4)x100
2: Solution: Original 11x (one-third - two-thirds) = 11x (-100).
3;Solution: Original formula = - 99% x - 98/99. x - one half.
Per cent. 4: Solution: original formula = 11/24 x 24
Solution: Will it be copied by mistake?
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1, = (-4) x (57 + 43) = -4x100 = -4002, = -11x (thirty-nine and one third + 2 3) = -11x60-11x40 = -11x(60 + 40) = -1100
4, =1 3x24-1 4x24+3 8x24=8-6+9=115, the question is incorrect.
According to the wrong one, 100x10 + 510x2-4x8-1x15 = 1973 is adopted.
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