A four digit number of 9 after being divided by 10, 8 after 9 divided, 6 after 7 divided, and 4 afte

9 after being divided by 10, 8 after 9 divided, 6 after 7 divided, 4 after 5 divided, then, this number can be divisible at the same time after adding 1.

This number is four digits.

Well, this number is greater than 1000 and less than 9999 The program is as follows: include

int main()

int i,n;

for(i=1000;i<=9999;i++)n=i+1;

if(n%10==0 &&n%9==0

n%7==0 &&n%5==0)

printf("%d",i);

return 0;Running Result:

It's okay to use if in the loop.

Add this two-digit number to 2, then it can be divisible by 9,8,4, and the smallest number divisible by 9,8,4 is 72

The two-digit number of this can be said is 70

Let's look at the first 3 conditions, obviously adding 1 is a common multiple of 8, 9, and 10. The least common multiple is 360. The common multiple is 360k, k is a positive integer, and subtracting 1 is the solution of the first 3 conditions. 360k-1 is a multiple of 11.

360k-1

11x32k+8k-1

11x32k is a multiple of 11, so 8k-1 is a multiple of 11.

When tested one by one, when k = 7, 8k-1 = 55 is a multiple of 11.

So the minimum number is 360x11-1=3959

From the title, it can be seen that this number must be a multiple of 11, and this number plus 1 must be a common multiple of , because the common multiple of is ...So this number could be:

Characteristics of the number by multiples of 11: The difference between the sum of the odd digits and the sum of the even digits is divisible by 11, and it can be seen that this number may be:

So the minimum number is:

8 is a multiple of 4, and the most wild of 8 and 9 is:

Therefore, the smallest number divisible by 9, 8, and 4 is 72

A: This two-digit number is 70

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A number is divided by 7 by 5, 10 by 2, 8 by 4, this number is.

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Pro, the expression is as follows: a certain number is divided by 7 by 5, 10 by 2, 8 by 4, this number is 12

Hold and empty in person, calculate the blind range as follows: 12 7 = 1 surplus 5 12 10 = 1 surplus 2 12 8 = 1 remainder 4 A certain number is divided by 7 by a surplus of 5, divided by 10 by a remainder 2, divided by 8 by a remainder 4, this number is 12.

Pro, 162 also meets the requirements of this topic, and the equation is as follows: 162 7 = 23 surplus 1 162 10 = 16 surplus 2 162 8 = 20 surplus 2

Being divided by 5 by 2 by 6 by 3 by 7 by 4 can also be understood as 3 less than a multiple of 5, 3 less than a multiple of 6, and 3 less than a multiple of 7

Therefore, to find the maximum quadrangle number divided by 5, divided by 2, divided by 6, divided by 3, divided by 7, and divided by 4, you can first find the largest quadrangle divisible by 5, 6, 7, and then subtract 3

The least common multiple of 5,6,7 is 5*6*7=210, so the maximum 4 digits divisible by 5,6,7 are 47*210=9870, so the maximum four digits divided by 5 by 2, 6 by 3, 7 by 4 are 9870-3 = 9867

This number plus 1 is exactly divisible by 3,5,7,9, so it is a common multiple of 3,5,7,9.

This number can be set to 315n+314, and n is a non-negative integer.

In addition, this number is divisible by 11, so 315n+314 is divisible by dividing 11315 by 11 to make it 7, and 314 by dividing it by 11 to make it 6

So 315n+314 divided by 11 is the remainder of 7n+6

n=7.

Therefore, the minimum number is 315*7+314=2519

A three-digit number, divided by 9 by the remainder 8, by 6 by the remainder 5, by 7 divided by the remainder 6 This number +1 is a multiple of the round muffled common of 9,6,7.

The minimum three-digit difference of 126,252,378,504,630,756,882 is 125,251,377,503,629,755,881

If you add 2 to this number, it is divisible by 4 and 6, and the number that is divisible by 4 and 6 is divisible by 9 and 1.

ZaozhouDivide by 9 and the remainder of the noisy rock is, liter 6, .,

So this number does not exist.

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