High School Mathematics Requires Detailed Solutions to High School Sophomore Mathematics

<>I'm sorry, I'm too watery.

Those are drafts. Do you need me to rewrite it? And I'm not sure about the accuracy ha. Guidance, guidance.

If the length is x, the width is x, and the height is y

4*（x+x+y）=24

i.e. 2x+y=6

Volume = length * width * height.

v =x^2*y

x^2*(6-2x)

6x^2-2x^3

v‘=12x-6x^2

v'=0 gives x=0 (rounded) or x=2

x<2,v'>0

x>2,v'<0

x=2 to get the maximum.

If my is helpful to you, please choose it as a satisfactory answer in time, thank you

The key is how to surround this, if it can't be broken.

In the case of folded length, width and height, the length is x, the width is x, and the height is 24-2x volume v=x*x*(24-2x).

24x^2-2x*3

Because x is between 0 and 24.

So you can draw a diagram and see that between 0 and 8 is incrementing, and after 8 it is decreasing, so there is a maximum, if and only if x=8 is to obtain a maximum value of 512

If the drawing is not available, you can find the derivative, and you can see the increasing and decreasing intervals as well.

Let the length be x meters, which is derived from the properties of the box: 4*x+4*x<24 (the sum of the lengths of the sides of length and width) 0

If the length is x, the width is x, and the height is. The derivative is 12x-6x 2Let the derivative value be zero, and get x=8 3The maximum volume brought in is 8

Set the length and width to x, and the height to y

4x+4x+4y=24 y=6-2x

Volume v=x*x*(6-2x) Just find x where the derivative is equal to 0.

A(n+2)=4a(n+1)-3an gives a(n+2)-a(n+1)=3[a(n+1)-3an], which shows that (a(n+1)-an) is a proportional series proportional to 3, where the first term a2-a1=3

So a(n+1)-an=3 n

an=[an-a(n-1)]+a(n-1)-a(n-2)]+a2-a1)+a1

3^(n-1)+3^(n-2)+.3+1=(3 n-1) (3-1) (sum of proportional sequences) = (3 n-1) 2

(1) (an+1-an) is a proportional series with a ratio of 3

2）an=（1-3^n）/(-2)

Solution: According to the problem, let Z=0, the slope of the line X+My=0 can be obtained as 1m, combined with the feasible domain, it can be seen that when the line X+My=0 is parallel to the line AC, any point on the line segment AC can make the objective function Z=X+My obtain the minimum value, and the slope of the line AC is -1, so M=1

So the answer is:1

Question 8?!|af1|+|af2|=2a=4===a=2a(1, root number 3 2) on the ellipse ===1 a 2+3 4b 2=1===3 4b 2=3 4===b 2=1c 2=a 2-b 2=4-1=3==c=root number collapsed 3, so e=c a=root number 3 2=== shirt closed Chunna d

f(x)+g(x)=5x²-3x+1 (1)

f(-x)+g(-x)=5(-x)²-3(-x)+1＝5x²+3x+1

Then the left side changes according to parity, ie.

f(x)+g(x)=5x²+3x+1 (2)

1)+(2), then divide the two sides by 2 to get g(x)(1)-(2), and then divide the two sides by 2 to get f(x).