In order to bomb a bridge, an airplane flying in the air must be either directly above or after 5

The bomb should be dropped before the plane reaches the height of the bridge, because the bomb will move a certain distance due to inertia when the plane drops the bomb during the flight.

First of all, you have to explain whether this is a physics problem or a math problem.

If you just talk about throwing bombs, it's simple.

Because the plane drops a bomb in flight, the bomb will remain in its original motion for a certain distance even if it leaves the plane.

It is to continue to fly forward by inertial potential energy), so it is necessary to calculate the amount of advance and drop it before reaching the bridge.

Conclusion Throw before flying towards the target bridge.

Most of the modern bombers are high-altitude bombers, as well as supersonic or subsonic, the basic ceiling is more than 10,000 meters, not the dive bombers of World War II, the main bomber of the US military B-52 bomber is known as the "stratofortress", flying at an altitude of more than 13,000 meters, the general air defense facilities basically cannot reach that height, how can the bomb blow up itself?

According to the physical motion of the parabolic body. Aircraft flying high in the air carried bombs. The plane drops the bomb, and the bomb moves in a uniform acceleration curve. So the plane had to be in front of the bridge, dropping bombs.

It should be directly above, because the bomb has inertia and will move at a certain speed after leaving the plane, which, combined with gravity, will form a parabolic curve.

The plane was going to drop a bomb in front of the bridge, and when the air resistance was not taken into account, when the plane was above the bridge was a bomb**.

Before the upper part of the bridge, there was also the initial velocity of the plane when the bomb fell.

After that, of course, you can't even blow up your plane directly above you.

Before. When a bomb is dropped, the bomb still has forward velocity in the air.

Mentally retarded, regardless of factors such as wind direction, it is in the rear.

It was supposed to drop the bomb directly above the bridge.

It must have been before, there was inertia.

Before. Because bombs have inertia.

Before, it was a freshman physics.

I don't know if it's before or after, but it's a simple flat toss, so think for yourself.

It's a difficult topic. What to do in case the bomb goes out of flame???

For 5 points so many people in this egg hurt -

It depends on what kind of plane, what kind of bomb... If it's a missile, it doesn't matter where it is.

You have to ask Obama about it.

Of course, it was just above before the bomb was thrown and flew over, how to blow it up.

When a bomber flying at a constant speed in the horizontal direction continues to move forward due to inertia, the bomb should be dropped before it reaches the target before it reaches the target

So the answer is: before

=, the probability of the bridge being blown up》1, the probability of being blown up =

The probability that the bridge will be blown up.

1- The probability that the bridge will not be blown up.

All shot down) Shot down 2) Shot down 1) All passed) ===

If you have any questions, please ask.