x 2 3 x how to solve? Process Thank you!

Multiply the left and right sides by x. :-x-square+2x=-3 Shift: -xsquare+2x+3=0Mention minus: -(x-square-2x-3)=0

x1=3 x2=-1

Hope it helps. (See if there are any special requirements for the topic, such as whether x can't be negative or something.)

x is on the denominator, so x is not equal to 0

Multiply x on both sides to get -x +2x=-3

x²-2x-3=0

x+1)(x-3)=0

x=-1 or x=3

x+2=-3 x is divided into (x 2-2x-3) x=0 then x 2-2x-3=0, and the solution of the equation yields x=-1 or 3

x/3+x-x/2-x=2 x/3+3x/3-x/2-2x/2=2 4x/3-3x/2=2 8x/6-9x/6=2 -x/6=2 x=-12 ..To simplify, x 3-x 2=2 multiply both sides of the equation at the same time.

Multiply both sides by x at the same time. Then it's easy to get x=3 or -1

When x is not equal to 0, the two sides are multiplied by x, and then the unary quadratic solution is solved.

Equation into a standard quadratic equation form, i.e.:

x² -3x - 4 = 0

Next, use the root finding formula:

x = b sqrt(b -4ac)) 2a where a = 1, b = 3, c = 4

Bringing a, b, and c into the formula yields:

x = 3 sqrt(9 + 16)) 2 simplify: x1 = 4

x2 = 1

So the solution of the equation x = 3x+4 is x1 = 4 and x2 = -1.

Here's how, please refer to:

If it helps,.

Because (x+1) 0, (x-3) 0, the inequality holds if and only if x-4 0.

So x 4

The cavity slip on both sides of the left and right Wulula is multiplied by x. :-x square + 2x = -3 shift terms: -x square + 2x + 3 = 0 minus sign:

x-1=±2

x1=3x2=-1

Hope it helps. (See if there are any special requirements for the question.)

For example, whether x can't be negative or something).

1. There is an error in the solution. When both sides of the equation are multiplied by x-3, the premise that x is not equal to 3

2.Here's how to solve it. (2-x) (x-3)=1[(3-x)-2]x≠3 and x≠1, the numerator and denominator are cross-multiplied to obtain x-3=(2-x)[(3-x)-2].

x-3=(2-x)(1-x)

After finishing x2+4x-5=0, so x=1 or x=-5According to the denominator is not zero. So x=-5