Primary School Olympiad Age Questions 10, Primary School Olympiad Age Questions

This year, Xiao Fang's age is 3 5 of Xiao Gang, and the age difference between the two is 1-3 5 = 2 5 of Xiao Gang's age this year

After 10 years, Xiaofang's age is 4 5 of Xiaogang, and the age difference between the two is 1-4 5=1 5 of Xiaogang's age 10 years later

That is, Xiao Gang's age of 2 5 this year is equal to 1 5 of his age in 10 years, so his age in 10 years is (2 5) (1 5) = 2 times of this year's age.

So Xiao Gang is 10 years old this year.

Solution: From the meaning of the question, it can be seen that there is a 3 age difference between 3 and 42, so the column formula:

42-(42-3) 3=29 (years).

The age problem is often closely related to the problem of sum difference, sum times and difference times, especially the solution idea of the difference multiple problem is the same, and it is necessary to firmly grasp the characteristic of "the age difference remains unchanged".

You can use the solution ideas and methods of the "difference multiple problem".

The age difference between two people is constant;

The age of two people increases or decreases at the same time;

The multiple of two people's age is varied.

The commonly used formula is:

Age of the smallest at multiplication = difference between the age of the size and the age (multiple-1).

Age a few years ago = young present years - young age at multiples.

Age in a few years = age when it was doubled - age of the young now.

Example 1, Dad is 35 years old this year, Liangliang is 5 years old this year, how many times is Dad's age this year? What about next year?

Solution: 35 5 = 7 (times).

35+1) (5+1)=6 (times).

A: This year Dad's. The age is 7 times that of Liangliang, and next year Dad's age will be 6 times that of Liangliang.

Example 2: The mother is 37 years old this year, the daughter is 7 years old this year, and the mother will be 4 times older than the daughter in a few years?

Solution: (1) How much older is the mother than the daughter? 37-7=30 (years).

2) How many years later will the mother be 4 times older than the daughter? 30 (4-1)-7=3 (years).

Listed as a composite equation (37-7) (4-1)-7=3 (years).

A: After 3 years, the mother is 4 times older than the daughter.

For example, the age of father and son was 49 years old a year ago, and this year's father's age is 4 times the age of his son.

Solution: The age of the father and son this year should be increased by (3 2) years compared with 3 years ago, and the age sum of the two this year is 49 + 3 2 = 55 (years).

If the age of the son this year is taken as 1 times, then the age of the father and son this year is equivalent to (4+1) times, so the age of the son this year is 55 (4+1) = 11 (years).

This year the father's age is 11 4 = 44 (years).

A: This year, the father is 44 years old and the son is 11 years old.

First of all, you sort out each clue clearly, according to each clue to list the equivalent relational formula, if you have studied the equation, one formula and one equation to solve it, then if you have not learned to solve complex equations, then fix a person's age, see that the age of other people in the same year is several times that of this person, so that it adds up to a one-dimensional equation, just solve it.

What grade is the Olympiad about age?

He was 88 years old. Let the largest be x, then the ages of the five from oldest to smallest are x, x-a, x-b, x-c, x-6, and the equation can be listed.

x+(x-a)+(x-b)+(x-c)+(x-6)=85*5x=85+(6+a+b+c)/5

The middle three of them are all younger than X, older than X-6, and one is younger than the other, so there is.

1≤a<5

2≤b<5

3≤c<5

6≤(a+b+c)<15

Since the age of a person is limited to an integer, (6+a+b+c) must be divisible by five, and.

12 (6+a+b+c)<21, take a multiple of 5 in between, only 15, a, b, c can be rounded at the same time, so the maximum age is 88

Hello! The largest is x, and the lowest is x-6

Anyway, the age of the other old people is in the middle.

It can be assumed that they are all 85 years old

However: x+x-6=85*2

Get x=88 me, are you still satisfied?

According to the title, the sum of the ages of the panda Panpan and the golden snub-nosed monkey is: 16-6=10;Because the golden snub-nosed monkey is older, there are several situations:

1. When the golden monkey is 9 years old, the age of the panda Panpan is 1 year old, and it is not satisfied that "the age of the panda Panpan is exactly 2 times the age difference between the age of the golden monkey", so this situation is not good;

2. When the golden monkey is 8 years old, the age of the panda Panpan is 2 years old, and it is not satisfied that "the age of the panda Panpan is exactly 2 times the age difference between the age of the golden monkey", so this situation is not good;

3. When the golden monkey is 7 years old, the age of the panda Panpan is 3 years old, and it is not satisfied that "the age of the panda Panpan is exactly 2 times the age difference between the age of the golden monkey", so this situation is not good;

4. When the golden monkey is 6 years old, the age of the panda Panpan is 4 years old, and then the age of the panda Panpan is exactly 2 times the age difference between the age of the panda Panpan and the golden monkey, so this situation can be, that is, the age of the golden monkey is 6 years old, and the age of the panda Panpan is 4 years old.

So the panda Panpan is 4 years old.