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This is a disproportionation reaction.
Cl changes from zero valence to positive and negative valence, then the ratio of chloride ions and hypochlorite ions is 1:1, and the gain and loss of electrons are conserved.
Then determine the conservation of charge, the hydroxide root has to be two, and finally look at the conservation of mass.
The trim of an ionic reaction is first the conservation of electrons gained and lost, then the conservation of charge, and finally the conservation of mass.
Cl2 +2 Oh- === Cl- +Cl- +H2O, for example, Cl2+6Oh-=Cl- +ClO3-+3H2OFirst, Cl changes from zero valence to positive pentavalent and negative monovalent, then the coefficient of chloride ion is 5, chlorate is 1, which satisfies the conservation of gain and loss electrons, and then according to the conservation of electrons, the coefficient of hydroxide is 6, and finally, the coefficient of water is 3, ok
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Cl2 + OH- === Cl- +Cl- +H2O by this equation.
It can be seen that Cl2 is both an oxidizing agent and a reducing agent.
The gains and losses of electrons are as follows:
Cl2 +OH- === Cl- +Cl- +H2O electrons gain and lose equilibrium, so only the atomic number of this reaction needs to be balanced.
That's it, and the result is as follows:
cl2 +2oh- === cl- +clo- +h2o
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According to the valence rise and fall of chlorine gas to balance, one in the chlorine rises and one decreases, so the chloride ion is matched with one chloric acid and finally leveled.
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First standardize the valence, and then make the total number of lifts and falls equal.
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There are 2 hs on the right side of the equation, and o is 2 oh-.
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Cl2 + Oh- =Cl- +Cl- +H2OFrom this equation, we can see that Cl2 is both an oxidizing agent and a reducing agent, and the situation of its electron gain and loss is as follows: 0 +1 -1Cl2 +OH- =Cl- +Cl- +H2O's electrons are out of balance, so it is only necessary to balance the atomic number of the reaction, and the result is as follows: Cl2 +2Oh- =Cl-..
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Cl2 (0 valence) reacts with OH- to produce Cl- (to decrease 1 valence to gain electrons) and Clo3- (to +5 valence, to lose electrons), that is, electron transfer occurs in chlorine gas because the electrons are conserved in general. Clo3- loses 5 electrons (in terms of the number of electrons) and has 5 chlorine to gain electrons, then we can know that there are 5 Cl- according to the conservation of atoms, then chlorine gas should be 5 Cl- + a Cl3- Clo3- One chlorine atom is 3 Cl2
3Cl2+OH-=5Cl-+ClO3-+H2O According to the conservation of charge, the right side is 6 negative valences, then the left side should also be 6, so there are 6 oh-According to the conservation of atoms, we can know that there are 3 3Cl2+6OH-=5Cl-+ClO3-+3H2O
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First, determine the chemical value of chlorine in each compound.
Therefore, positive 4 becomes positive 5 liters of one price, and positive four descending rulers are matched with negative one and 5 prices, so in order to make the balance of the rise and fall, it is necessary to match Linghong 5 before the 5 price of chlorine, and the price of one price is 1...Then according to the conservation of materials, 6 is matched before CLO2
So 6clo2---5clo3- +cl-
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Cl in HCO2 is +3 valence.
If clo2 cl is +4, then the pin band loses 1 electron.
Cl- is-1 valence gives 4 hand reed electrons.
then 5HCl2=4ClO2+Cl-+2H2O+H+
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2clo2+h2o2+2oh-=2clo2-+o2↑+2h2o;
Hope it helps.
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2CN-+CLO-+H2O=2HCO3-+N2+5Cl-CN-medium C+2 valence n-3 valence.
CL - CL+1 valence.
HCO3- C+4 valence, N0 valence in N2.
Cl-medium cl-1 valence.
cn-→hco3-
c:+2---4.Losing 2e, the chemical price rises by 2
2cn-→n2
Lose 6e, increase the valence by 6
clo-→cl-
cl:+1.-1...2e is obtained, and the chemical valence drop of 2 is conserved according to the gain and loss of electrons, so the cn- coefficient is 2, the HCO3- coefficient is Zheng Chunheng 2, the N2 coefficient is shouting 1 and the clo- coefficient is 5
The cl- coefficient is 5
Finally, according to the conservation of Senwang materials, the atomic conservation H2O coefficient is 1
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