About high school math insights, high school math, please explain in detail.

You have to look at the problem first, just like you look at **, and fall in love with these skills and methods of solving the problem.

For these wonderful solutions, you should yearn and pursue!!

I think that's important! Then you will become interested in mathematics. And to read the book, then the answers to this book must be detailed, I highly recommend the "Full Solution Question Bank", you really don't need to do it, you just need to keep reading 10 questions a day, and after a month, your math score will soar!!

And what is the book "King of Science" that I haven't used myself, but I heard that it's okay, don't you try it!!

It can cultivate your "mathematical thinking" and breakthrough in problem solving!

Then, you must buy a copy of "Mathematics, Physics and Chemistry Formula Theorems" to help you!!

That's all I have to say, I hope it will be helpful to you!!

A lot of it is beautiful! In fact, it is not easy to learn mathematics, just cope with the college entrance examination.

Of course, the book has to be about the same, and then I crazy about doing college entrance examination questions and mock questions! (If you are about to be in the third year of high school) there is a big question behind what you said, which is divided into special categories, which is very smart.

Imitate those answers more, and if you do more, you will find that those questions are all according to a certain routine, and you can easily deal with them, of course, you have to know the formulas in the book, or you will work in vain.

It's not just a matter of looking at the computer screen, the steps must be flawless, it's all pen work.

1.Do more questions, and do them quantitatively every day according to your ability.

2.Copy the questions you did wrong in a special notebook. The problem is solved on the same day.

3.Every day, make the next day's mistakes and redo them again.

4.As long as you make a test book, you must insist on finishing it, because every book has its own system! If you give up halfway, you lose the meaning of being him.

5.If you do the questions you have done, you will not make a second stool.

6.Functions, determinants, sequences, trigonometric functions. It's all the same workaround. As long as you stick to it every day, you will definitely be able to get to the top of the class in math within two months.

I don't want to be too dogmatic and talk about what I experienced at the time.

Method: Listen carefully to the class, memorize the knowledge points, and do the questions.

High school mathematics should not be difficult to understand, listen carefully to the teacher's explanation during class, memorize the knowledge points hard after class, and be able to write it out silently (in fact, you can memorize it in 10 minutes), don't rush to do the problem, take the knowledge point and then do the problem, do not remember the problem before going to the book to see.

When you find that you have memorized all the knowledge points and do the questions, you will suddenly be enlightened (most of the knowledge points that you don't know are clear or not memorized).

Actually, I think it's enough to practice a little more in a subject like mathematics. But to summarize in time, review in time, put a set of wrong questions around you at any time, and do it repeatedly, I guarantee that your math score can improve quickly.

For example, I have been working on 38 sets of papers recently, and I have achieved an unforgettable topic:

Let's not talk about the topic, let's talk about the content.

Knowing the (n+1) power of 4an-a(n+1)=-2, find the general formula for an.

In the past, I didn't pay attention to summarizing when I was learning a series, so I didn't even know the conventional solution of this kind of series. Later, after reading the answer, it turned out to be.

4 (n+2 to the nth power) = a(n+1)+2 to the (n+1) power.

Then the sequence becomes a proportional series with a1+2 as the first term and 4 as the common ratio, and it is easy to solve like this.

That's why I said that mathematics focuses on practicing more, then reviewing more, summarizing more, doing what you know how to do, and doing what you are not familiar with, how can you not succeed in mathematics?!

Note that 5*3=15

So 2 n = 1 p+1 pn

2/n=(n+1)/pn

So n+1=2p

p=(n+1)/2

q=pn, so p+q=(n+1) 2

The most conventional way of thinking is:

Let the coordinates of a and b be a (x1,y1)b(x2,y2) through ab of the straight line l:y=kx+b

There is the intersection of a and b, so y=k(1 4)ysquare+b, i.e., k*ysquared-4k+4b=0 has roots.

y1+y2=-4/k

y1y2=4b/k

The conditions that are met are parabolic and vertical, and the list is reached.

y1 square = 4x1, y2 square = 4x2

x1-x2) square + (y1-y2) square = x1 square + y1 square + x2 square + y2 square.

x1x2 + y1y2 = 0

Then the expressions x1 and x2 are brought in.

1/16）y1y2（y1y2+16）=0

Y1 and Y2 are not 0, so Y1Y2+16=0

Sort out 4b k = -16 again

b = -4k instead of l expression.

y=kx-4k=k（x-4）

At this point, the fixed point (4,0) is passed

When k does not exist, the straight line is perpendicular to the x-axis.

Find the coordinates of A and B to verify that OA and OB are still vertical.

Therefore, the constant point (4,0).

The sum of the two terms is greater than zero, the product is less than zero, so one positive and one negative, and the number column is an equal difference series, so it is a decreasing number series, the 2005th term is greater than zero, and the 2006th term is less than zero, that is, from the first term to the 2005th term are greater than zero, so the first 2005 terms are the maximum.

Solution: f(x-2) = f(-x-2).

x-2+(-x-2)=-4

x=-2 is the axis of symmetry of f(x), let f(x)=a(x+2) 2+m(a =0) make x=0, f(0)=a(0+2) 2+m=ax4+m=4a+m=1, let the intersection of f(x) and x-axis be a(x1,0), b(x2,0), x1,x2 are the two real roots of f(x)=0.

Let f(x)=0

a(x+2)^2+m=0

x+2)^2=-m/a

x+2=+-(m/a)^1/2

x=+-(m/a)^1/2-2

x1=(-m/a)^1/2-2,x2=-(-m/a)^1/2-2/x1-x2/=/(-m/a)^1/2-2+(-m/a)^1/2-2/=/2x(-m/a)^1/2-4/=2x2^1/2

2x(-m/a)^1/2-4=+-2x2^1/2(-m/a)^1/2-2=+-2^1/2

m/a)^1/2=2+-2^1/2

m/a)^1/2=2+2^1/2

m/a=4+4x2^1/2+2=6+4x2^1/24a+m=1

m=(6+4x2^1/2)a m=-(6+4x2^1/2)a4a-(6+4x2^1/2)a=1

4-6-4x2^1/2)a=1

2-4x2^1/2)a=1

a=1/(-2-4x2^1/2)=-2^1/2/7+1/(-m/a)^1/2=2-2^1/2

m/a=4-4x2^1/2+2=6-4x2^1/2-m=(6-4x2^1/2)a

m=(4x2^1/2-6)a

4a+(4x2^1/2-6)a=1

4x2^1/2-2)a=1

a=1/(4x2^1/2-2)

Then substitute a into m, find the corresponding m, and get the corresponding 2 leases, that is, the analytic formula of f(x) is obtained, and the two sets of solutions correspond to the two analytic formulas

If c is selected, the equation for p is y=0

q: f(x-1) is the function f(x) image to the right translation by one unit, not necessarily symmetrical with respect to x=1.