det A can the minus sign come up with 110

#include

#include

int main()

float a,b,c;

float x1,x2,det;

cout<<"Please enter the quadratic term coefficient a, the primary term coefficient b, and the constant term c:";

while(cin>>a>>b>>c)

Displays the current equation.

cout<< a <<"x^2"<<(b>0" + ":" - ")<0" + ":" - ") det=b*b-4*a*c;

if(a!=0)

if(det>0)

x1=(float)((b+sqrt(det))/(2*a));

x2=(float)((b-sqrt(det))/(2*a));

cout<<"The equation has two different roots:"<<"x1="x1=(float)(b/(-2*a));

cout<<"Equations have heavy roots:"<<"x="cout<<"Equations have no real roots"cout<<"There is a single root of the equation:"<<"x="<<(c/b)return 0;

When a has an even number of rows, deta=det-a, and when there are odd rows, it is true.

No, you can't-1-a|Not equal to -|1＋a|, when -1-a<0|-1-a|=-1-a)=1 a, when -1-a>0,|-1-a|=-1-a。

No, [-1-a] is greater than or equal to 0, and -[1+a] is less than or equal to 0

Since the positive and negative properties of -1-a are not known, the absolute value of a positive number is itself, and the negative number is its opposite.

In this question|-1-a|itself is a positive number, if it becomes -|-1-a|It's less than 0, and it can't be deformed by constant deformation, so it can't.

Conclusion: |-1-a| =1+a|

1-a|It is not possible to simply mention that the negative sign becomes -|1+a|, the result obtained by this method is just the opposite except for a=-1.

The proof is as follows: when (-1-a) < 0, i.e., a>-1, |-1-a|=1+a；At this time, 1+a>0,|1+a|=1+a=|-1-a|

When (-1-a) > 0, i.e., a<-1, |-1-a|=-1-a；At this time, 1+a>0,|1+a|=-1-a=|-1-a|

Finally, when a=-1, |1+a|=0=|-1-a|Therefore, no matter what value a takes, |-1-a| =1+a|Total establishment.

No, because I don't know the plus or minus of -1-a.

A matrix cannot raise a minus sign from a single line. Because if you want to come up with a negative sign from a matrix, all the elements of the matrix need to be mentioned together, and here the difference is with the determinant, which can be derived from a single line of the common factor.

1. The number multiplication of the matrix satisfies the following operation law:

2. The addition of matrices satisfies the following arithmetic laws (a, b, and c are all homomorphic matrices):

Only between homogeneous matrices can addition, addition and subtraction of matrices and multiplication of matrices can be performed in linear operations of composite matrices.

No, you can'tIf you want to come up with a minus sign, all elements of the matrix should be mentioned together, and the minus sign of each line of the determinant can be mentioned separately.

For matrices, multiplying with the number l is the multiplication operation of the matrix and the number, multiplying each number by l.

Application of quantity matrix.

Image processing: In image processing, the affine transformation of an image can generally be expressed as a form of multiplying an affine matrix with an original image.

Linear transformations and symmetry: Linear transformations and their corresponding symmetries play an important role in modern physics.

Linear combination of quantum states: When Heisenberg proposed the first quantum mechanical model in 1925, he used infinite-dimensional matrices to represent theoretical operators acting on quantum states.

Normalization mode: Another general application of matrices in physics is to describe linear coupled harmonic systems. The equations of motion for such systems can be expressed in the form of matrices, i.e., a mass matrix multiplied by a generalized velocity to give the motion terms, and a force matrix multiplied by a displacement vector to characterize the interactions.

There is a line of fractions multiplied by the denominator, and the other lines should not be multiplied.

If there is a negative sign on one line, the other lines must follow, but generally do not have a negative sign on one line, but multiply this line by -1.

Yes, but not to propose, but to multiply this line by -1

If this elementary transformation is only to find the rank of the matrix, it can be extracted.

But if it's for the determinant, pay attention to whether you change the value of the determinant.

Yes, it's multiplying by c

Solution: b-a).

-b+a)a-b) i.e.: (b-a) extracts the negative sign equal to -(a-b).

No, you can'tThe true number of the logarithmic function must be positive, with a negative sign indicating that the rest is negative.

There are other factors that cannot be proposed, and the logarithmic function is not linear.