Chemistry questions, competition questions, puzzles

Simple, chickens and rabbits in the same cage!

The oxidation number of o is 2,2*2,9=

It shows that the average oxidation number of tungsten is that if x tungsten atoms in 1 part of tungsten are 5 valence, 1-x hexavalent, then: 5x+6(1-x)=, x=, 1-x=, and the ratio is 1:4I would like to adopt!!

Whistleblowing |14 mins ago See you at the sight of the eye.

5 price to 6 price = 1:4 Follow-up question: how to calculate? The process is similar to ferric tetroxide.

Tungsten and oxygen are multiplied by 10 at the same time, and then because tungsten as a whole shows +58 valence, then tungsten with two valences is +5 and +6 and then the column formula 5x+6y=58;x+y=10, and the result is out.

According to the calculation of the amount of H+ substance, it can be seen from the equation that H+ and NH4+ are 1:1 relationship, and H+ can be obtained according to the amount of sodium hydroxide, that is.

So the ammonium ion is:

ammonium root can be obtained in n: grams.

So A is correct, and D is also possible, because if this ammonium salt is ammonium nitrate (NH4NO3), then D is also correct.

The mass of N in 10 ml of solution, the mass of N in 100 ml of solution.

(1) According to the calculation, the amount of alkali used should be, so the amount of substances that generate H ions is also the amount of substances that produce ammonium ions in 10ml of solution, so the amount of ammonium substances in the original 100ml solution and 2g of ammonium salts is. Because the relative molecular mass of ammonium is 18, in this ammonium salt, the mass of the ammonium should be calculated by calculation), and the mass of the anion in the ammonium salt is calculated by calculation), assuming that there is only one ammonium in the ammonium salt, then the relative molecular mass of the anion = , and the anion (chloride ion, sulfate.

carbonate, nitrate, etc.), only the relative molecular mass of nitrate is 62, so the ammonium salt may be NH4NO3, and the nitrogen content of the substance = (14*2) (18+62)=35%. The answer D is correct.

2) Assuming that there are two ammonium roots in this ammonium salt, the amount of the substance of the anion = can be calculated in the same way. Among the common anions, sulfate has the largest relative molecular mass (relative molecular mass of 96), so this assumption is not valid.

Hence the answer is d. For answer a, there seems to be no second anion other than nitrate in secondary school chemistry so far with a relative molecular mass of 62. Therefore a is wrong.

This question... Let's find the amount of nitrogen in the ammonium salt (mass fraction), but what if it is ammonium nitrate? NH4NO3, how do you ask for it.

The amount of matter of g metal aluminum is, and the amount of matter that loses electrons is.

a. If the amount of matter that gives all Pb = , mass = >36 if the amount of matter that gives all Hg = , mass = >36b, if all the amount of substances that get Fe = , mass = <36 If the amount of substance that gives all Zn = , mass = <36 is obviously impossible.

c. If the total amount of the substance that gets ag = , mass = >36 If the total amount of the substance that gets Cu = , mass = <36 is obviously possible. d. If the total amount of the substance obtained by sn = , mass = <36 will not give magnesium.

Apparently impossible.

In summary, C should be chosen

The ratio of one to three indicates that Ni occupies the entire center of face in a unit cell (cubic unit cells should have symmetry) and c is in the center of body. The unit cell pattern is similar to that of catio3. However, it is Ni that replaces O, and C replaces Ca (hexacoordination).

MG replaces TI (12 coordination).

The main thing is the ability to draw.

The question does not specify the container shape, and the following calculation is based on the columnar container.

For cylindrical containers, the pressure of the liquid on the bottom of the container is equal to the pressure on the bottom surface when the liquid is considered solid. Therefore, the pressure at the bottom of the container increases by 28Pa, and the increased mass of the solution can be found: let the increased mass of the solution be X kg, according to [G take 10] P=G S=mg S=10X X= This mass should be the mass of calcium carbonate added minus the mass of carbon dioxide released, let the mass of calcium carbonate be yg, according to CaCO3+2HCl=CaCl2+H2O+CO2, Y=50;Continuing to find the mass of Qi early HCl that reacts exactly with 50g of calcium carbonate is, therefore, the mass fraction of solute pin in the original hydrochloric acid = .

Write the chemical formula of the following substance: B: Ba(NO3) C: NaOH D: Cu(OH)2

If A is pure and the colorless neutral liquid is also pure, then the colorless neutral liquid is H2O (filler formula).

If A is a pure substance, a colorless neutral liquid is a solution containing only one solute, then a colorless neutral liquid is a Na2SO4 solution or a Nano 3 (filled chemical formula) solution.