Ask for 62 application questions for the first year of junior high school. Urgent .

1.From the title of the hundred is one of 1 2, if it is 1, the number is 114, if it is 2, it is 259; If you are in the opposite direction of the 10th and 100th places, then the number is 259

2.If the mother's age is x and the daughter's is y, then: x+2=6(y+2); x+22=2(y+22) Unskinning: x=28;y=3

3.Due to the different widths of the two cuts, one is a horizontal cut and one is a vertical cut; Let the edge length be x, then:

3*x=4*(x-3), and the solution is x=12

4.I think the meaning of the question seems to be that A used 1080 to buy a fixed number of commemorative coins for penitential socks, and he bought the kind of 120 yuan, but his Bi grip was not enough, but the salesman still gave him the 120 yuan commemorative coins he needed. However, the salesman made as much profit as he gave him the amount of 80 yuan.

Such a living equation should be as follows: Let the quantity he buy be x, then: x*80*30%=1080-(x*120*70%), and solve:

x=10 people in y dormitory: 4y=x-20; 7y6.I don't see a problem.

There are x rooms available.

4x＋21＞7x

Solution: x 7

The number of people is: 4 (7 1) 21 = 45 (people).

Since the first year of junior high school may have talked about setting 2 unknowns, let's set an unknown.

Set the number of rooms x, the number of people obtained is 4x+21, and the principle of using the same number of people is used to obtain 0<4x+21-7(x-1)<7, and you can calculate 7< x<28 3 gives x=8 or 9, and calculates 4x+21=53 or 57 to get 53< p>

There are x people, y rooms.

x=4y+21

055, do not meet, give up.

So, the number of boarders is 53.

There are 4 people living in each room, and 21 people are unhoused.

If you divide each of the 21 people into 3 people, you should be able to divide them into 7 rooms.

And the title says that there is a room that is not empty and dissatisfied, so the number of rooms should be 8 or 9 (because the original 8 people in the two rooms can also be divided into 7+1).

If there are 8, the total number of people is: 4 8 + 21 = 53 people.

If it is 9, the total number of people is: 4 9 + 21 = 57>55, which does not meet the requirements, so there are 8 rooms and 53 people.

There are x dormitories for y people.

Then it is known from the meaning of the title: 4x+21=y *

7>y-7x>0 **

y<55 **

Bring * into ** to get 14 3 then x can take 5 or 6

Just bring these two numbers into the original equation system and test them.

Solution: There are x rooms.

4x+21<7x

3x>21

x>7 because there are fewer than 55 boarders.

If there are 8 rooms, there are 4 * 8 + 21 = 53 people.

If there are 9 rooms, then there are 4 * 9 + 21 = 57 people The number of people is less than 55, so 9 rooms are not possible.

The more rooms, the more people.

There are 8 rooms.

There are 53 people. Think of it this way: if there are less than 55 boarders, then if the maximum number of students is 55, then there will be a maximum of (55-21) 4=rooms.

The inequalities listed give x>7 so 7x=8 for boarders is 8*4+21=53

Do you understand?

It takes x days to complete the armor, which is derived from the title:

18 24+10 x=1 solves: x=40

Therefore, it takes 40 days and 60 days for A and B to complete the project respectively.

If two engineering teams work together for 18 days, engineering team A will work alone for another 10 days, and it will be completed on time.

That is, team A 18 + 10 = 28 days, team B 18 days, can be completed, and if the two engineering teams cooperate, 24 days will be completed at the specified time;

So, Team A does 28-24 = 4 days of work, and Team B needs 24-18 = 6 days to complete, then Team A does 24 days of work, and Team B needs 24 4 * 6 = 36 days to complete, so it takes 24 + 36 = 60 days for Team B to complete alone.

It takes 60 6 * 4 = 40 days for Team A to complete alone.

1.A and B cooperate to complete the project in 18 days: 18 24 = 3 4 So A completes the rest in 10 days:

1-3 4 = 1 4 A completes the project every day: (1 4) 10 = 1 40 A needs to complete the project alone: 1 (1 40) = 40 days.

B alone required: 1 (1 24-1 40) = 60 days.

A and B cooperate in 24 days to complete, A and B work in 18 days, and A does another 10 days to complete, then A works for 4 days and B works for 6 days.

Then 24 days of work of A is equivalent to 36 days of B, then it takes 24 + 36 = 60 days for B to complete, and 60 6 * 4 = 40 days for A to work.

Each term = 4n-1 (n is the first, second, third...) Substituting 2011 into the calculation is n=503, then 2011 is the 503 terms in this column.

Each difference is 4, do the math yourself, it's pretty simple.

No, what grade are you in? Is this a practical question for the first year of junior high school?