Minor questions about analytic geometry, problems with analytic geometry?

Point A about the line x+2y=0 symmetry point is still on the circle then the center of the circle is on the line x+2y=0, and the point a is on the line x-y+1=0, since the chord length of the line x-y+1=0 truncated circle is 2 times the root number 2, then the perpendicular line of this string is over the center of the circle, and the perpendicular line passes through the point (1,2), the perpendicular equation is x+y-3=0, the center of the circle is the intersection of the line x+2y=0 and the straight line x+y-3=0, the intersection point is (6,-3), and the equation of the circle is (x-6) 2+(y+3) 2=(2-6) 2+(3+3) 2=52

As shown in the following bright diagram of the blocking branches, the results can be obtained by calculating and moving the items after the substitution is carried out.

The Coordinate Geometry Book refers to the creation and development of mathematicians such as Descartes and Fermat with the help of the Cartesian coordinate system. It is a branch of geometry that uses analytical methods to study the relationship and properties of geometric objects.

Analyzing how many letters are is one of the key points in high school, and it is also one of the most difficult problems in the college entrance examination. There are many students who find analytic geometry difficult and have no idea where to start, and many teachers think that "analytic geometry is a completely different way of thinking from three-dimensional geometry". In fact, in my personal opinion

1) Analytic geometry is one of the easiest chapters in high school; 2) Solve analytic geometry problems.

yn=-2k square is a trillion wisdom yn+m

yn+2k square finch answers: yn=m

Guess the punch 2k square +1)yn=m

yn=m (2k square + 1).

Thanks for reading.

Fill in the old empty question god cave ascending example question 1Let a tangent of the circle c : x2 y2 4 intersect the x axis and the y axis at the points a and b respectively, then the minimum value of ab is

In high school mathematics, due to the complexity and diversity of analytic geometry itself, it has always been a difficult point in the college entrance examination.

c^2=m^2+n+3m^2-n=4m^2=4

If m 2=1, then the equation is x 2 (n+1)-y 2 (3-n)=1, and (n+1)(3-n) is 0, so -1 is aimed at n 3, and a is chosen

First, introduce a property of the focal triangle car width: for a point on any ellipse, let , then . .As long as the parity is different, there is a corresponding back-to-back diagram closure letter bright, as long as the parity is the same,

Hello, I'm sorry, I'm not very good at math, I can't understand what you sent, and I can't answer it for you.

Solving Circle Staring Geometry Problems 1. Fill in the blanks Example 1Let a tangent line of the circle c : x2 y2 4 intersect with the x-axis and the y-axis at the points a and b, respectively, then the minimum value of ab is Luzheng

The cross-section is equal to the longitudinal cross-section.

Fill-in-the-blank sample question 1Let the circle c: x2 y2 4 intersect a tangent line with the x-axis and y-axis at points a and b, respectively, then the minimum value of ab is

The cross-section is equal to the longitudinal cross-section.

The definition of a parabola and the combination of knowledge of plane geometry.

For reference, please smile.

Now bring x=p 2 into c to calculate the length of pf, and then use the triangle ofp to be similar to the triangle pfq, get the of pf = pf than pq, and solve p to get the alignment equation.

<> "As shown in the figure above, the curve represented by (x-1) 2+y 2=1 is a circle with (1,0) as the center and 1 as the radius, so the diameter of (x-1) 2+y 2=1 is 1.

This is the standard equation for a circle, with a center of (1,0) and a radius of 1

The standard equation (x-1) grinds 2+(y-0) 2=1 2

Contrast (x-a) 2+(y-b) 2=r 2

According to the equation formula of the circle:

x-a) Occlusion 2+(y-b) 2=r 2

Sweet potato center coordinates: (a, b).

The radius number regrets that it is r

This question is achieved in three steps:

Find the point (tangent p,q coordinates).

To find the tangent equation, first find the derivative to obtain the tangent slope, and then write the tangent equation.

Finally, the system of simultaneous equations is found for the coordinates of the intersection point.

For reference, please smile.

Solution: y'=x

The slope of the tangent of the crossing point p is 4, the tangent equation y=4(x-4)+8 (1)The slope of the tangent of the crossing point q is -2, and the tangent equation y=-2(x+2)+2 (2).

Synonymous (1) and (2) find the focus as (1,-4) hope.

Are you going to ask this question? Still have to ask what? The slope of the tangent at each point is exactly equal to the value of the abscissa of that point, which is not surprising!