Looking for all the equations of junior high school chemistry, there are instructions such as writin

Search it: Please write out all the gas chemical equations on the third year of junior high school, as long as the decomposition reaction, add the text equations, thank you.

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CuSO4+2NaOH = Cu(OH)2 +Na2SO4 blue precipitate generated, the upper part is a clear solution.

Experiments on the law of conservation of mass.

ca(oh)2+co2=

caco3↓+

H2O clarified lime water becomes turbid.

Apply CO2 inspection and lime mortar to paint the walls.

ca(hco3)2=δ

caco3↓+h2o+co2↑

White precipitation, the production of clear lime water turbidity gas.

Limescale formation. Formation of stalactites.

hcl+agno3=

agcl↓+hno3

Produces a white precipitate, insoluble in dilute nitric acid.

Check the principle of cl-.

ba(oh)2+

h2so4=baso4↓+2h2o

Produces a white precipitate, insoluble in dilute nitric acid.

Examine the principle of SO42.

bacl2+

h2so4=baso4↓+2hcl

Produces a white precipitate, insoluble in dilute nitric acid.

Examine the principle of SO42.

Ba(NO3)2+H2SO4=BASO4 +2HNO3 generates a white precipitate, insoluble in dilute nitric acid.

Examine the principle of SO42.

FeCl3+3NaOH = Fe(OH)3 +3NaCl solution fades yellow and has reddish-brown precipitate.

AlCl3+3NaOH = Al(OH)3 +3NaCl has a white precipitate.

mgcl2+2naoh

mg(oh)2↓+2nacl

cucl2+2naoh

cu(oh)2↓+2nacl

The blue color of the solution fades, and a blue precipitate is formed.

ca(oh)2+so2=caso3↓+

H2O has a white precipitate generated.

Not in junior high school.

Ca(OH)2+Na2CO3=CaCO3 +2NaOH has a white precipitate to form.

Industrial caustic soda, laboratory caustic soda in small quantities.

Ba(OH)2+Na2CO3=BaCO3 +2NaOH has a white precipitate generated.

ca(oh)2+k2co3=caco3↓

2koh has a white precipitate generated.

agno3+nacl

agcl↓+na

NO3 white is insoluble in the precipitate of dilute nitric acid (similar to other chlorides) and is used to test the chloride ion in the solution: BaCl2

na2so4

baso4↓+2nacl

White insoluble precipitates of dilute nitric acid (similar reactions to other sulfates) should be used to test sulfate ions:

cacl2+na2co3=

caco3↓+2nacl

There is a white precipitate generated.

MgCl2+Ba(OH)2=BaCl2+Mg(OH)2 is formed with a white precipitate.

Let's talk about two precipitates that are insoluble in dilute nitric acid:

agno3+hcl=agcl↓+hno3

White precipitate. BaCl2 + H2SO4 = BaSO4 + 2HCl white precipitate. In addition, there is a representative hydroxide precipitation

CuCl2+2NaOH = Cu(OH)2 +2NaCl blue flocculent precipitate.

FeCl3+3NaOH = Fe(OH)3 +3NaCl reddish-brown flocculent precipitate.

Other insoluble alkalis are generally white in color, but some of them are more special:

FeCl2+2NaOH = Fe(OH)2 +2MaCl white precipitate, immediately turning gray-green, then reddish-brown.

4Fe(OH)2+2H2O+O2=4Fe(OH)32agNO3+2NaOH=AG2O+H2O+2nano3 is observed as an earthy yellow precipitate because silver hydroxide will photocompose.

Carbonate precipitation is common.

Ba(OH)2+CO2=BAC3 +H2OCA(OH)2+CO2=CaCO3 +H2OBACl2+Na2CO3=BaCO3 +2NaClCaCl2+Na2CO3=CaCO3 +2NaCl, both of which are white.

[Chemical experiments] common precipitation formation.

Don't remember them one by one.

I find a pattern and the solubility table is basically released.

The metathesis reaction that generates the precipitate can be pushed by itself.

There is such a precipitation mantra:

potassium, sodium, ammonium, nitrate, both soluble;

hydrochloride, silver insoluble;

sulfate, barium insoluble;

Carbonate, only potassium sodium ammonium, magnesium carbonate slightly soluble, the rest are insoluble.

The above is salt, and the soluble base has potassium, calcium, and barium, of which calcium hydroxide is slightly soluble.

It is worth noting that silver chloride and barium sulfate are often used as test sites because they are insoluble in water and insoluble in acid.