Find the chemical equation in the format of chemistry A B C D E, and the reaction conditions for ill

High school chemistry a+b=c+d+e format chemical equations, and reaction conditions for light only with chlorine and alkyl substitution, e.g. .

ch4+cl2=light=ch3cl+hcl;

CH3Cl + Cl2 = light = CH2Cl + HCl toluene and chlorine under light conditions to generate methyl substitution reaction.

ch3-c6h5+cl2=cl-ch2-c6h5+hcl

cl2+h2o=hcl+hclo+o2 If there are light conditions in high school, this is the only one.。。 No need to go to trimming. It's useless.

The product has these 3 that would have looked like this: Cl2 + H20 = (reversible) HCl + HCl

2HClL = (see light) 2HCl + O2

Although HCO hypochlorous acid decomposes when exposed to light, HCO is still present as long as the amount of chlorine is sufficient.

The reaction of strong acids with SO3 2-, CO3 2- C, Cu, etc. and the oxygen reaction of concentrated sulfuric acid is many, many more It is impossible to say, just remember the type 4HNO3 (concentrated) = light = 4NO2 + O2 + 2H2O

ch4+cl2=light=ch3cl+hcl; ch3Cl + Cl2 = light = ch2Cl + HCL2 + H2 = light = 2HCl

I guess there are certain limitations to your understanding of the problem.

Let me explain this for you:

First of all, the white model ball represents the oxygen atom, the pattern model ball represents the nitrogen atom, and the black model ball represents the hydrogen atom.

The combination of two white model balls can be known to be oxygen (O2), and the combination of one pattern model ball and three black model balls can be seen to be ammonia (NH3), and the survival is water (H2O) and some oxidizing substance formed by the combination of a white model ball and two black model balls.

The ratio of the number of molecules in the reaction of A and B is 5:4, and the stoichiometric number (trim number) of A and B can be obtained according to the Afugadro constant (I have not learned for six or seven years, I forgot the specifics) is 5:4, and it can be concluded that 6 molecules of water are generated, 4 molecules of nitrogen and 4 molecules of oxygen remain, and nitric oxide (NO) can be obtained according to common substances in high schools

As for the hydroxide ion (oh-) that you said can be denied directly according to the diagram, even if it cannot be denied, we can also know that ions cannot exist alone (all substances are positive and negative equal).

Obviously, no, if F is an OH ion, first of all, the atomic equilibrium is difficult to achieve, and N is put to **? Secondly, the concept of oxide should be clarified, OH is not considered an oxide, and besides, if it is an OH ion, how to balance?

a h2o2

b h2oc o2

d h2e fe2o3

f feo1,o2

Electrolysis) H2+O2 decomposition reaction (you should know that I don't remember much about the four major types of Jikehu in the junior high school).

4..h2o===tremor difference) h2+o2 ; 3H2+Fe2O3===High temperature) 3H2O+2Fe

Are you a freshman or junior in high school?

d flame color reaction purple = d contains potassium, e is yellow-green gas at room temperature = e is chlorine.

A is CU and C is NO.

The ionic equation is 3Cu+8H+ +2NO3-=3Cu2+ +2NO+4H2O

a. From the chemical equation, it can be seen that only 1 molecule of the reactant of the reaction is decomposed, which is inconsistent with the figure, so A is incorrect;

b. From the chemical equation, it can be seen that the reaction is a chemical reaction, and the lead is inconsistent with the decomposition reaction shown in the figure, so B is incorrect;

c. From the chemical equation, it can be seen that the number of molecules and molecular composition of the reactants and products in the reaction are consistent with the reaction shown in the figure; Therefore c is correct;

d. From the chemical equation, it can be seen that the number of molecules and molecular composition of the reactants and products in the reaction are not the same as those shown in the diagram; Therefore d is incorrect

Therefore, C

Copper and concentrated liquid dust nitric acid reaction.

Generally encountered purple-red metal is pure copper.

The lead-brown gas of Honghe is generally NO2

Cu + 4 Hno3 (Thick) = Cu (Nao Zen No3) 2 + 2 No2 + 2H20

A is copper, d is NO2, and the equation is: Cu+4Hno3 (concentrated) = Cu(NO3)2+2NO2 +2H2O

Copper reacts with concentrated nitric acid to form nitrogen dioxide with copper nitrate, water.

C is oxygen, which can be prepared by decomposing hydrogen peroxide and generating water at the same time, Sun Meng A is hydrogen peroxide, and B is water

Water and calcium oxide react to form calcium hydroxide, d is calcium hydroxide calcium hydroxide absorbs carbon dioxide to produce water, and e is carbon dioxide

Carbon monoxide combustion can produce carbon dioxide, f is carbon monoxide Therefore, fill in: (1) O2

then hail bridge 2) cao + h2

O=Ca(OH)2

Synthetic reaction 3)CO; 2co+o2

Ignite 2CO2

4) 2H2O energized.

2h2+o2

ca（oh）2

co2caco3+h2o．