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Method 1:
Therefore, each copy represents 1 person.
There were 16 boys.
There are 25 female students. Method 2:
1+1=2 (person).
2 1 20 = 40 (person).
Female: 40 5 (5+3)=25 (person).
Male: 40-25+1=16 (person).
There were 16 boys.
There are 25 female students.
The second is calculated based on the difference between boys and girls. The first time the boy walked out of the team, there were 1 4 more girls than the boys in the team, and the second time there were 1 5 more girls than the boys. But the second time the girls walked out of the team, relatively speaking, there were 2 fewer girls in the team than the previous time, so the corresponding score of 2 girls is 1 4-1 5=1 20, then the total number of people in the team is divided by the corresponding amount, which is 40 people.
So now use the proportional distribution method to find out the number of girls, and then use the number of girls in the team - the number of girls + 1 boy outside the team = the number of boys.
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1. In a certain class of students in physical education class, a boy walked out of the team to count the number of people, and it was found that the ratio of the number of boys in the team to the number of girls was 7 to 5, and it was replaced by a girl who walked out of the team to count the number of people, and it was found that the number of girls in the team was two-thirds of that of boysHow many boys and girls are in this class?
There are 36 males and 25 females.
Process: 1. Set up x boys and y girls. (x-1) (y) = 7 5, (x) (y-1) = 3 2, and the solution is obtained.
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Because: 3:5=15:25
Therefore, each copy represents 1 person.
There were 16 boys.
There are 25 female students.
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Obediently,All the above plagiarism.。。。
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Method 1:
Therefore, each copy represents 1 person.
There were 16 boys.
There are 25 female students. Method 2:
3 2 -1) (3 2 +1) = 1 2 5 2 = 1 51 + 1 = 2 (person).
2 1 20 = 40 (person).
Female: 40 5 (5+3)=25 (person).
Male: 40-25+1=16 (person).
There were 16 boys.
There are 25 female students.
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There are 36 males and 25 females. 600 grams of water.
Process: 1. Set up x boys and y girls. (x-1) (y) = 7 5, (x) (y-1) = 3 2, and the solution is obtained.
2. Set x grams of poured water. (200*8%) (200+x)=(300*6%) (300+x) solution.
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The question of the bunting that was asked, the question is not wrong, your understanding is limited.
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Suppose the class size is a, 1 6a girls and 1 4a boys, 1 4a-1 6a=4 solution a=48
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Except for the 1 student in the statistics, the total number of remaining students remains unchanged.
Expansion ratio is resistant to disturbance, 3:5=15:25
Boys: 16 Females: 25
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Let's say there are x boys and y girls.
The equation is as follows: (x-1) y=3 5
y-1)/x=3/2
Solve the equation to obtain: x=16
y=25
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The total number of people in the team after walking out of one person is considered as "1", and when one boy walks out of the line, there are more girls than boys
1 girl walked out of the group, and the total number of girls outnumbered boys:
The number of female students is:
25 (person);
Number of boys: 40-25 + 1 = 16 (people).
A: There are 16 boys and 25 girls
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Solution: There are x and y male and female students in this class, according to the question.
x-1/y=3/5
y-1/x=3/2
x=16 y=25
A: There are male and female students in this class.
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Brother, you should still study hard.
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Set this class for boys and girls x,y
x-1):y=3;5
x:(y-1)=2;3
x=16y=25
There are 16 boys and 25 girls in this class.
Edutainment and entertainment.
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