Brain teaser , find the law 1 , 2 , i imaginary unit , pi ,e the base of the natural logarithm ,

Updated on amusement 2024-04-06
10 answers
  1. Anonymous users2024-02-07

    The first number should be 0 because 0 is the latest Arabic numeral to be invented, and 0,1 are the two most important numbers in the field of rational numbers and the ring of integers.

    The second number should be c (Euler's constant = because Euler's constant has not yet been proven whether it is a transcendent number, or even a rational or irrational number.

    Since this question is about the development of the history of mathematics, it should be the expansion of the number field and the proposal of a new concept of numbers, which should first move from rational numbers to irrational numbers to complex numbers and then to transcendental numbers.

    1 represents an integer ring.

    1,0 represents a field of rational numbers.

    2 stands for irrational number (it was the first irrational number to be discovered and proved, as proved by the Greek scholar Hippasus).

    i (imaginary unit) represents a complex number field.

    Pi) represents the connection between algebra and geometry.

    e stands for the concept of transcendental numbers (the proof of the transcendence of e precedes ) and also represents the emergence of higher mathematics, so that mathematics has developed to a peak.

    The last null I think should be filled in with a number about mathematical conjecture, then it can be Euler's constant, its transcendence has not yet been proven, and many mathematicians have been working on it.

  2. Anonymous users2024-02-06

    It was born from the interpretation of negative roots when solving equations.

    It was the latest to be born in Arabic numerals, and the Holy See even prevented its use, but it brought convenience to calculations.

  3. Anonymous users2024-02-05

    What is missing from these are the decimal numbers of rational numbers.

    1 represents an integer or a natural number, followed by a decimal, and decimals have infinite non-cyclic decimals, etc.

    The last one fills the empty space endlessly

  4. Anonymous users2024-02-04

    The first one is a score, and the last one I think should be an integral.

  5. Anonymous users2024-02-03

    lg10 =1 is one of my favorite math symbols.

  6. Anonymous users2024-02-02

    1,1,2,6,(明吉好24),(120),(720)

    The rule is that their lead increases by 1

    For example: 1*1=1 1*2=2 2*3=6 6*4=24 24*5=120

  7. Anonymous users2024-02-01

    First of all, 22 82 = 1804, 53 53 = 2809, these two values are not equal, if you have to say the law of equality, it is that the first ten digits are 2 + 8 = 10, and the ten second digits are 5 + 5 = 10. But again, they vary in value.

  8. Anonymous users2024-01-31

    The question went wrong. This should be the topic of the special law multiplication course in the third grade of primary school, the original question is 22 times 82 = ; 53 times 53 = to find the pattern. Because of the problem of the paper, the two questions are glued together, so the question appears.

    This is the law of two-digit multiplication by two-digit number, the last two digits of the product are equal to the mantissa multiplication of the two multipliers (2 times 2 equals 4, and zero is added without carrying, that is, 04), the first two digits of the product are equal to the multiplication of the ten digits of the two multipliers, and then the same mantissa is added (2 times 8 plus the mantissa 2, that is, 18), so the product is 1804

    Again, multiplying 53 by 53 gives you 2809

  9. Anonymous users2024-01-30

    7 9 = 6367 99 = 6633667 999 = 666333 What is the law and what law have you found?

    Rule: n-digit silver beam 6 plus 1 multiplied by n-digit front and round 9 is equal to n-digit 6 and n-digit 3 to form the number of cavities.

  10. Anonymous users2024-01-29

    1) is the second number of the third group, 2 in the tenth place, 1 in the single place, and this number is 21;

    is the first number of the fourth group, 3 in the tenth place, 0 in the single place, and this number is 30;

    is the second number of the fourth group, 3 in the tenth place, 1 in the single place, and this number is 31;

    So =21,=30,=31;

    There are already 3 5s in the original sequence, and 2 5s are missing, so , are all 5, which is 6

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