Please give me the process! Please write it on paper! Thank you!

The point o is the circle of abc outside the rt triangle, so it can be seen that the o point is the midpoint of ac, which connects ob, and since oa=ob so cab = abo

In PAB, PA=PB, so PAB= PBA, and because PA is circled at point A, PAC=90°, i.e., PAB+ BAC = 90°

So abo+ pba = 90°, so pb is the tangent of the circle o.

2) Connecting PO From (1), we can see that ABC is similar to Pao, so if the radius of the circle is X, then there is OA=X, AC=2X

po= There is a triangle under the root number (3+x squared) and the principle of similarity exists.

ao bc = po ac i.e. x 1 = under the root number (3+x squared) 2x collation equation is.

4 (x to the fourth power) -x squared - 3 = 0 Let x square = y has y>0

4*y squared - y -3 = 0

The solution gives y = 1 or y= -3 4 (rounded), so x = 1 or x = -1 (rounded).

So the radius of the circle is 1

1) Prove: Connecting ob, by the known, OAB+ BAP=90°, because oradius OA=ob, so oba= OAB, and known PA=PB, thus PBA= PAB, so, obp= oba+ ABP= OAB+ ABP=90°, so PB is the tangent of O.

2) Solution: Let the radius of o be x, then ao=x, ac=2x, ab=ac -bc =4x -1

Connect op, because pa=pb, oa=ob, op=op, so poa pob, thus aop= bop= aob 2

Because acb= aob 2 (the circumferential angle is equal to half of the central angle of the circle), aop= acb

Again 90°= OAP= CBA, so POA ACB, thus.

pa/ab=ao/bc，pa²/ab²=ao²/bc²，ab²·ao²=pa²·bc²

Substituting the known data and ao=x, ab=4x-1, obtain.

x²（4x²-1）=3

(x -1) (4x +3) = 0, because 4x +3>0, so x -1 = 0, x = 1 (x = -1, which is not in line with the actual meaning).

Ans: The radius of o is 1

: Positive and negative.

3.This is an inverse proportional function.

2-2m=-1∴m=

Because it's an inverse proportional function.

So 2-2m = -1

So m=

The root number can be changed to the square of a-3, the original formula is 2a+3, and the result is -4014+3=-4011

Let's see for yourself if you can see it clearly, no one will do it for how long you leave it like this.