Xiao Ming buys two books and has 3 yuan left, and 4 books are 7 yuan less, how many yuan does Xiao M

Xiao Ming buys 2 books and has 3 yuan left, and buys 4 books for 7 yuan less, you can set the book as x, then 2x 3 4x 7, x 5 yuan, 2 5 3 13 yuan, Xiao Ming has 13 yuan in his hand.

It can be obtained from the title.

Set: Xiao Ming has x yuan, and each book is y yuan.

x－2y＝3

4y－x＝7

Add the two formulas. 2y＝10

y 5 x 13 yuan.

Answer: Xiao Ming has 13 yuan in his hand.

Set $ x per book.

2x+3=4x-7

x=5 Xiao Ming has a total of 2 5 + 3 = 13 yuan.

Column formula (3+7) (4-2)=5, the unit price of each book is 5 yuan.

Xiao Ming brought 5 * 2 + 3 = 13 yuan.

There are x dollars, according to the title.

2（x-3）=x+7

x=13Answer: Xiao Ming has 13 yuan in his hand.

Set $ x per book.

2x＋3=4x-72x=10

2x＋3=4x-7=13

Answer: Xiao Ming has 13 yuan in his hand.

Set a book for x yuan.

2x+3=4x－7

2x=10x=5

2x+3=2 5+3=13 (yuan).

Answer: Xiao Ming has 13 yuan in his hand.

Solution: Set x yuan per book.

2x＋3＝4x－7

Solution: x 5

2x+3=2 5+3=13 (yuan).

Answer: Xiao Ming has 13 yuan in his hand.

Suppose the unit price of these books is the same, they are all x yuan.

2x+3=4x-7

x=52*5+3=4*5-7=13 (yuan).

A book:

5 (yuan) Xiao Ming has a total of money.

5 2 3 13 (yuan).

They add up to $9+. So this book is meta. The money they each bring is the money that the other party is poor, that is, Xiao Ming has yuan, and Xiao Hua has 9 yuan.

Since their money can only buy one book in total, then Xiao Hua can buy this book by giving his money to Xiao Ming, or Xiao Ming giving his money to Xiao Hua. In other words, the money of Xiao Ming is the money of Xiao Ming, and the money of Xiao Hua is Xiao Ming's money. It can be seen from this that Xiao Ming brought yuan and Xiaohua brought 9 yuan.

Set Xiaoming with x yuan, Xiaohua with y yuan. According to the title, the formula can be listed as follows, x+9=y+x+9=x+y

y+solution, x=, y=9

That is, Xiao Ming brought yuan, and Xiaohua brought 9 yuan.

Their combined money is just enough to buy a book, and the ** of this book is 9+;

How much money did they each bring: Xiao Ming,; Xiaohua, answer: Xiao Ming brought yuan; Xiaohua brought 9 yuan;

Answer: Xiao Ming brought Yuan, and Xiaohua brought 9 Yuan.

Suppose Xiao Ming has x yuan and Xiaohua has y yuan, according to your question stem, you can get x+y, which is equal to the price of a book, and x+9 is also equal to the price of a book, so y is equal to nine x = 6 yuan five, so Xiao Ming brought six yuan and five small flowers, and brought nine yuan.

Let the book ** be x-yuan, then you can list the equation:

x－9+x－

Solve x = so this book** is yuan, so Xiao Ming brought yuan, and Xiaohua brought yuan.

Suppose the book costs x-yuan, then according to the title, you can know:

x-9+x=So Xiao Ming brought Yuan, and Xiao Hua brought 9 Yuan.

Set Xiaoming with x yuan, Xiaohua with y yuan.

x+y＝x+9 ……1)

x+y＝y+

1)-(2)：x-y+

y＝x+ …3)

Substitute (3) into (1):

x+x+x substitute (4) into (3), y

y 9 A: Xiao Ming brought 9 yuan, and Xiaohua brought 9 yuan.

Solution: Let a book be x yuan, according to the title, x-9+, solve x=, Xiao Ming with yuan, small flower with 9 yuan.

Xiao Ming plus 9 yuan is equal to small flower Canadian dollars. So Xiao Ming is less than Xiao Hua. Again, Xiao Ming plus small flower is equal to Xiao Ming plus 9 yuan is equal to small flower Canadian dollar. So Xiao Ming Yuan, Xiao Hua 9 yuan. Book element.

According to the title, solution: 9+

This book ** meta.

Yuan) Xiao Ming should bring Yuan.

Yuan) florets should be brought 9 yuan.

9+ yuan.

Yuan. Yuan. Answer: Xiao Ming brought Yuan, and Xiaohua brought 9 Yuan.

Solution, 6 yuan 5 jiao = yuan.

Book 9 + yuan) Xiao Ming Yuan).

Xiaohua Yuan).

According to the inscription column, it is calculated as follows:

The amount of money that Xiao Ming bringed:

9+ yuan. The amount of money that the small flower strip has:

9+ yuan.

Solution, book 9 + yuan).

Xiao Ming Yuan, Xiao Hua Yuan).

Let the price of the book be x

x=x-9+

x = book price) x = yuan.

Xiao Ming's money = yuan.

Small money spent = yuan.

Xiao Ming brought X yuan

x-14 is the ** of a book, 2(x-14)-28=x, x=56 yuan

42 yuan for a book, Xiao MingI brought 56 yuan

14 dec. 28 42 (yuan).

42 dec. 14 56 (yuan).

A book costs 42 yuan, and Xiao Ming brings 56 yuan.

Because there is 14 yuan left to buy a book, and now I use this 14 yuan to buy another book, but there is a difference of 28 yuan. So the ** of a book is 14 + 28 = 42 yuan. So Xiao Ming brought 42 + 14 = 56 yuan. So Xiao Ming brought 56 yuan.

Questions. Thank you

You can rest assured that my answers will have ideas and processes. 

14 + 28 = 42 yuan and the money you need to buy two books, 42 2 = 21 yuan This is the money for one book.

21 + 14 = 35 yuan, Xiao Ming brought 35 yuan.

Suppose Xiao Ming brings x yuan, a book y yuan, and the equation x-y 14 can be listed, and it costs 28 yuan to buy two more books, so y 14, then x 28.

According to the title, it is known that Xiao Ming has ten yuan left to buy a book, and the difference between buying two books is fifteen yuan, and now he needs to ask Xiao Ming how much money he has.

This is a simple logical problem, we can use the method of equations to solve, first let Xiao Ming have x yuan, then the ** of the book is x-10, so you can list equations:

x+15=2 (x-10), solution.

x=35, so Xiao Ming has 35 yuan, and the ** of a book is 25 yuan.

Hope it helps.

From the title, we can find that when Xiao Ming bought the second book, he used up the remaining ten yuan, and there was still a difference of fifteen yuan.

Therefore, the ** of a book is 10 + 15 = 25 yuan.

And Xiao Ming has 25 + 10 = 35 yuan.

10x2 ten 15 = 35 yuan. A, Xiao Ming has 35 yuan. $25 for a book.

Summary. Hello, Xiao Ming is short of 7 yuan to buy books, Xiao Li is short of 10 yuan to buy books, and 1 yuan more to buy together, ask how much is this book? The specific calculation process is as follows:

Xiao Ming is short of 7 yuan to buy a book, Xiao Li is short of 10 yuan to buy a book, and he is 1 yuan more to buy a book, so how much is the book?

Hello, Xiao Ming is short of 7 yuan to buy books, Xiao Li is short of 10 yuan to buy books, and 1 yuan more to buy together, ask how much is this book? The specific calculation process is as follows:

This book** is: 7 + 10 + 1 = 18 yuan.

This problem is easier to understand by solving the problem with equations:

Suppose a book ** is a yuan, and the equation can be listed according to the title:

a-9+ solution equation:

2a-a=a=So the ** of a book is meta.

The book is sold for yuan.

Because, Xiao Ming and I just bought this book before the two of us, and Xiao Ming's difference of 9 yuan is all the money on me, and the money I have is the existing money on Xiao Ming, which together just bought this book!

9 + yuan) 9 yuan of Xiao Ming's difference, which means that Xiao Ming has yuan, and I have 9 yuan, the difference yuan, so it adds up to the money of this book.

10 yuan for a book. 10-9=1, Xiao Ming has 1 yuan. I have yuan.

Summary. The conditions are not enough.

This book is a minimum of 8 yuan and a maximum of yuan.

If both of them have an integer number, the book can only be 8 yuan.

Xiao Ming and Xiao Hua buy books, Xiao Ming is 8 yuan, Xiao Hua is 1 yuan, the two of them are not enough to buy together, how much is this book?

I have received your question and am in the process of answering it.

The conditions are not enough, the minimum for this book is 8 yuan, and the maximum is yuan. If both of them have an integer number, the book can only be 8 yuan.

The problem you are talking about is not enough.