Divide ten oranges into piles, no leftovers, how many divisions are there?

It is to ask you which numbers 10 can be divisible by, 10=1*2*5, so it can be divided into 1 pile of 10; 5 in 2 piles, 2 in 5 piles; 1 for each of the 10 piles, for a total of 4 divisions.

I didn't find a concise calculation method, so I use the enumeration method:

The main idea is to divide according to the number of piles of oranges:

1 pile 10+0=10 1 kind.

2 piles 1+9 2+8 3+7 4+6 5+5 (Note 4+6=6+4, the same below) 5 types.

3 piles 1+1+8 1+2+7 1+3+6 1+4+5 4 types.

2+2+6 2+3+5 2+4+4 3 types.

3+3+4 1 kind.

4 piles 1+1+1+7 1+1+2+6 1+1+3+5 1+1+4+4 1+2+2+5 1+2+3+4

1+3+3+3 2+2+2+4 2+2+3+3 9 types.

5 piles 1+1+1+1+6 1+1+1+2+5 1+1+1+3+4 1+1+2+2+4 1+1+2+3+3

1+2+2+2+3 2+2+2+2+2+2 7 kinds.

6 piles 1+1+1+1+1+5 1+1+1+1+2+4 1+1+1+1+3+3 1+1+1+2+2+3

1+1+2+2+2+2 5 types.

7 piles 1+1+1+1+1+1+4 1+1+1+1+1+1+2+3 1+1+1+1+2+2+2 3 types.

8 piles of 1+1+1+1+1+1+1+3 1+1+1+1+1+1+1+2+2 2 2 types.

9 piles 1+1+1+1+1+1+1+1+1+2 1 kind.

10 piles of 1+1+1+1+1+1+1+1+1+1+1 1 kind.

In total: 1+5+4+3+1+9+7+5+3+2+1+1=42 types.

You can check it, there should be nothing missing, I checked it several times, note that the division does not exist in order. Anyway, when you take the college entrance examination, you are also the champion of the city's mathematics single subject, which is presented to you. Hope it solves your problem.

12 oranges are divided into 4 equal parts, 2 oranges are divided into 4 equal portions, each part is a quarter, and each part is 3 pieces.

2 2 divisions, which can be divided into 6 parts, each part accounts for one-sixth, and each part is 2 parts.

Put one first, then two. (

Because 48 piles and 1 pile are excluded, there are a total of:

48 = 2 24,2 piles, 24 piles or 24 piles, 2 piles each;

48 = 3 16, 3 piles, 16 piles or 16 piles, 3 piles each;

48 = 4 12, 4 piles, 12 per pile or 12 piles, 4 per pile;

48 = 6 8,6 piles, 8 in each pile or 8 in 8 piles, 6 in each pile;

So there are 4 2 = 8 (species) in total

A: There are 8 divisions

Therefore, a

Summary. After adding four, it is 25, 25 5 = 5.

There are 21 oranges, at least a few more oranges need to be added, and the rest can be divided equally among 5 people.

Dear, at least four more are being added.

How to do the equation.

After adding four, it is 25, 25 5 = 5.

Detailed. 5 4 = less than. 25 is greater than 20.

5 4 = less than. 25 is greater than 21.

So each person should be divided into five. That's a total of 25.

Thank you. You're welcome dear.

There are 21 boys and 15 girls in the school.

Is there a requirement? No.

It's just asking how to form a phalanx.

There are 9 children in each row.

Divide the 12 oranges into four equal portions, a few each:

12 4 3 pcs.

The answer is to divide the 12 oranges into four equal portions, with three oranges each.

7 oranges are divided among 4 people, and each person is required to get at least one.

This. Permutations and combinations.

is suitable for the type of question.

Plug-in method. There are 6 spacings for 7 orange albums, and inserting any 3 banzhou gaona into the intervals can divide the oranges into 4 piles, and each pile has at least 1.

The distribution method is as follows: c (3,6) = 6 5 4 (2 3) = 20 (species).