Elementary School Pursuit Problem 5, Elementary School Pursuit Question

Let the distance be x

x-2) 12+(2 3 100+(1 3-2) 8

Multiply both sides of the equation by 120

10(x-2)=12(2x/3)+15(x/3-2)10x-20=8x+5x-30

x=10/3

Xiao Wang Xiao Li went to the base from the school at the same time, Xiao Wang traveled 10 kilometers per hour, Xiao Li set off late, in order to arrive at the same time as Xiao Wang, Xiao Li moved forward at a speed of 12 kilometers per hour, but Xiao Wang slowed down by 2 kilometers per hour when he traveled 2 3 times, and was caught up by Xiao Li at 2 kilometers away from the base.

Even the equal sign can be called an equation??

Let the distance be xx-2) 12=2 3 x 10+(1 3x-2) 8x-2) 12=x 15+x 24-1 413x 120-(x-2) 12=1 4

Forget the rest of yourself.

Examples of primary school pursuit problem application questions are as follows:

A and B are 150 meters apart, A is in front, B is behind, A walks 60 meters per minute, B walks 75 meters per minute, both of them set off south at the same time, and B catches up with A in a few minutes?

The equation is as follows:

Solution: Let B catch up with A after x minutes.

75x-60x=150

15x=150

x=150÷15

x=10A: After 10 minutes, B catches up with A.

I can't see the topic here, so I'm sorry I can't help you.

This problem cannot be solved by applying the relevant formula of the travel problem. It came after learning simple equations in the fourth grade, so this is a problem for solving equations. The pursuit in this problem is the same distance as the Tong Oak Hidden Encounter, and the speed of B must be found first, and the equation can be listed:

Solution: Let B have a velocity of x meters per minute.

30-x）×25=（30+x）×10

750－25x=300+10x

Subtract 300 from both sides at the same time

450－25x=10x

Add 25x to both sides at the same time.

450 = 35x i.e. 35x = 450

Divide by 5 on both sides at the same time

7x=90x=90/7

ab The distance between the two places is.

3000 7 m bureau hall.

A: The distance between the two places is 3000 7 meters.

Analysis: Because both ships started against the current, the ratio of speed against the water was (10-4) :(20-4) = 3:8

Because the speed ratio is equal to the distance traveled by two people, when B reaches port B, A travels 3

8, there are still 58 miles to reach Port B;

In the process of returning, B is driving along the water, so the speed becomes (20+4), and the speed of A remains the same, then the speed ratio is: (10-4):(20+4)=1:4

Then of the 58 journey, A traveled 58

Then A did a total of 38

It took 2 hours, and the answer was based on this

Answer: Solution: When B arrives at port B, A is done.

38), = 12 2,24 (km).

A: The two ports A and B are 24 kilometers apart

1. (50-1) (22-15) + 2. (8-6) x4 = 8 km, 60 people will be promoted to 10 = 6km h, Xiaobi 8 (60 Shouming 10-4) = 4, 6 + 4 = 10, catch up at 10 a.m.

Solution: If the hound can catch a hare after x hours, then:

22x-18x=2

4x=2x=

22-18=4（km）

2 divided by 4 = = 30 points.

Answer: Hound dogs can chase rabbits in 30 minutes.