SOLVE EQUATION X 2 X SQUARED 1 2X SQUARED 1 X 2

Updated on educate 2024-04-15
13 answers
  1. Anonymous users2024-02-07

    Hello: Let x (2x -1)=y

    y+1/y=2

    y²+1=2y

    y²-2y+1=0

    y-1)²=0

    y=1x/(2x²-1)=0

    2x²-1=x

    2x²-x-1=0

    2x+1)(x-1)=0

    x1=-1/2 x2=1

    If you don't understand anything about this question, you can ask it, and if you are satisfied, remember.

    If you have other questions, please send them separately or click to ask me for help, it is not easy to answer the questions, please understand, thank you.

    Good luck with your studies!

  2. Anonymous users2024-02-06

    Solution: Let x (2x -1)=y

    Then the original formula can be reduced to y+1 y=2

    Sorted out y -2y + 1 = 0, solved y = 1 (ps: I won't write the test) x (2x -1) = 1

    2x -x-1=0

    The solution is x = 1, x =

  3. Anonymous users2024-02-05

    <> am glad to answer the questions for you, and I wish you progress in your studies! If you don't understand, you can ask!

    If you need help with other topics, you can turn to me. Hope, thank you!!

  4. Anonymous users2024-02-04

    Solution: x (2x -1)+(2x -1) x=2, let :2x -1=y, then the original formula is:

    x-y) =0, then: x=y. Solution:

    x-(2x -1)] =0, which is reduced to: 2x -x-1=0, and the solution is: x1=1, x2=-1 2.

  5. Anonymous users2024-02-03

    Summary. Hello! Dear, is your question (x-5) =2x-1) squared? <>x-5) = 2x-1) + solve the equation with direct squares.

    Hello! Dear, is your question (x-5) =2x-1) squared? <>x-5)²=2x-1)²

    Hello! Dear, the solution process has been sent to you, directly open the flat method, we want to make the quadratic equation into the form of x = a, and then open the square on both sides of the equal sign at the same time, this problem we take the equal sign after the square (2x -1) as a whole, and then open the square on both sides, the right side of the equal sign is, (2x-1), will you? Pro-<>

  6. Anonymous users2024-02-02

    x-1)²=2

    x-1=±√2

    x=±√2+1

    If you have any questions, please ask, if you have no questions, please click [].

    Good luck with your studies o ).

    x-1)=2(x-1) (x-1)-2(x-1)=0 (x-1)(x-3)=0 x-1=0 or x-3=0 x=1 or x=3 If you are satisfied, please smile in time.

    Oh. x-1) squared - 2 (x-1) - 3 = 0

    x-1-3)(x-1+1)=0

    x-4)x=0

    x1=0x2=4

    x-1)^2-2(x^2-1)=0

    x^2-2x+1-2x^2+2=0

    x^2+2x-3=0

    x+3)(x-1)=0

    x=1 or x=-3

    x 1) 2 squared contains 4

    x 1) 2 squared -4 = 0 (x-1 + 2) (x-1-2) = 0 (x + 1) (x-3) = 0x1 = -1 x2 = 3

    Please rate it. Click [Review] in the upper right corner, and then you can select [Satisfied, the problem has been solved perfectly].

    If you approve of me, please be in time, yours is my motivation to move forward

    If there are new questions, please do not send them in the form of follow-up questions, send me another question and ask for help or send the address of the question link in the follow-up office, it is not easy to answer the question, please understand

    o(o, remember the praise and, help each other.

    Good luck with your studies!

    x-1) squared -2 (x-1) = 15

    x-1)²-2(x-1)-15=0

    x-1-5)(x-1+3)=0

    x-6)(x+2)=0

    x1=6 x2=-2

    x²/(x-1)-2=x

    x²-2(x-1)=x²-x

    x²-2x+2=x²-x

    The square of x = 2x minus two x minus x minus 1 the absolute value minus 1 is equal to zero.

    x²-2x-|x-1|-1=0

    x²-2x+1-|x-1|-2=0

    x-1)²-x-1|-2=0

    x-1|²-x-1|-2=0

    Order|x-1|=t>=0

    t²-t-2=0

    t-2)(t+1)=0

    t=2, t=-1 rounded.

    x-1|=2

    x-1=2 or x-1=-2

    x=3 or x=-1

    If you agree with me, please click "For satisfactory answers" and wish you progress in your studies!

    x-1)²=2x-1)²

    2x-1)²-x-1)²=0

    2x-1)-(x-1)][2x-1)+(x-1)]=0

    x(3x-2)=0

    x1 = 0, x2 = 2/3

    I'm glad to answer your questions and wish you progress in your studies! The Learning Guide team will answer the questions for you.

    If you don't understand, you can ask! If you approve of mine.

    Please click the [Select Satisfied] button below, thank you!

  7. Anonymous users2024-02-01

    Your original question is x -2x-|x-1|-5=0, right?

    It can be written as (x-1) -x-1|-6=0

    x-1|²-x-1|-6=0

    x-1|-3)(|x-1|+2)=0

    Will|x-1|Look at it as a whole.

    The above formula gets, |x-1|=3 or |x-1|=-2 (rounded) so |x-1|=3

    So x-1=3 or x-1=-3

    So x1 = 4 and x2 = -2

  8. Anonymous users2024-01-31

    (1) 3 (2y + 1) square = 27

    2y+1)^2=9

    2y+1=3 or 2y+1=-3

    y=1 or y=-2

    2) 4 (x-2) square = (x + 1) square.

    At the same time, the prescription is prescribed. 2(x-2)=x+1 or 2(x-2)=-(x+1)x=5 or x=1

  9. Anonymous users2024-01-30

    Hello: (1+x) squared + 2(1+x)-4=0(1+x) squared +2(1+x)+1=5

    x+1+1)²=5

    x+2=±√5

    x=-2±√5

    Good luck with your studies!

  10. Anonymous users2024-01-29

    Solution: (1+x) squared + 2(1+x)-4=0(1+x) squared + 2(1+x)+1=5

    1+x+1)²=5

    x+2)²=5

    x+2 = 5 or x+2=- 5

    i.e.: x=-2+5 or x=-2-5

    I wish you progress in your studies and a happy life!

  11. Anonymous users2024-01-28

    2x+1) = (x-1) squared.

    2x+1)²-x-1)²=0

    2x+1+x-1)(2x+1-x+1)=03x(x+2)=0

    x=0 or x=-2

    x squared -2x+1=49

    x²-2x-48=0

    x-8)(x+6)=0

    x=8 or x=-6

  12. Anonymous users2024-01-27

    2x+1) = (x-1) squared.

    2x+1)^2-(x-1)^2=0

    2x+1+x-1)(2x+1-x+1)=03x*(x+2)=0

    3x=0 x+2=0

    x=0 x=-2

    x sells or flattens the wheel square - 2x + 1 = 49

    x-1)^2=49

    x-1=7 x-1=-7

    x=8 x=-6

  13. Anonymous users2024-01-26

    What to solve? Solving equations?

    Solution 1: (2x+1) squared = (x-1) squared (2x+1) 2=(x-1) 2

    4x^2+4x+1=x^2-2x+1

    3x^2+6x=0

    3x(x+2)=0

    Solution: x1=0, x2=-2

    Or: (2x+1) 2=(x-1) 2

    2x+1=±(x-1)

    Yes: 2x+1=x-1.........1)

    Or: 2x+1=1-x.........2)

    From (1): x=-2

    From (2): 3x=0, i.e.: x=0

    That is, the solution of the original equation is: x1=-2, x2=0

    Solution 2: The square of x - 2x + 1 = 49

    x^2-2x+1=49

    x+1)^2=7^2

    x+1=±7

    x=1±7x1=8、x2=-6

Related questions
17 answers2024-04-15

If the question is not copied incorrectly, then:

The equation about x (m-2) x squared -2 (x-1) x + m=0 has only one real root. >>>More

10 answers2024-04-15

Equation 4 x + 1-2 x =11

Can be reduced to 2 2) x + 1-2 x =112 (2x)+ 1-2 x =11 >>>More

10 answers2024-04-15

1) Because x+1 x=3, (x+1 x) 2=3 2=9

And because (x+1 x) 2=x 2+1 (x 2)+2*x*1 x=x 2+1 (x 2)+2=9 >>>More

13 answers2024-04-15

It feels like there is a mistake in your problem, and the equation should be x 2-2xsina + sinb 2 = 0 >>>More

7 answers2024-04-15

x 3+ax 2+1) (x+1)=x 2-bx+1x 3+ax 2+1=x 3-bx 2+x+x 2-bx+1x 3+ax 2+1=x 3+(1-b)x 2+(1-b)x+1x 2 coefficients are equal to Lu Zheng: 1-b=a >>>More