The computer master comes in, the problem of the operating system

It remains on the computer, except that it is defined as the space that new files can freely overwrite the space occupied by those files. So you can't browse these files in the usual way. But with some software, such as finalrecovery, you can easily retrieve them as long as you haven't overwritten them with new ones.

Even some files that have been overwritten or formatted can be recovered. So remind the landlord that if you sell a mobile phone or digital camera, you must check whether the privacy has been stored in it, otherwise the buyer may restore the ** you have deleted and leak your privacy.

You can use a file shredder to shred the files. However, for the powerful finalrecovery, it seems to be basically useless, I tried the file shredder that comes with Rising, and it was completely useless. It's better to cover it yourself a few more times with irrelevant files.

Gone forever.

After emptying the ** station, your hard disk space will be freed up accordingly.

It's not going to go forever.

It's just not visible in the system.

If you empty it later, you can still get it back with recovery software.

In fact, it's gone on the surface.,As long as the disk you deleted the thing on the back doesn't have any files installed.,It's basically possible to get it back! FinalData or EasyRecovery will do!

As long as there is no grid, the file is not shredded, the file is still in the hard disk!

Summary. Answer (1) The logical address is 9016 = 2 * 4kb + 824, the page number is 2, and the block number is 32 physical address = 32 * 4kb + 824 = 131896b. (2) The logical address is 12300 = 3 * 4kb + 12, the page number is 3, the page is found to be missing, and the page is missing.

This one. Answer (1) The logical address is 9016 = 2 * 4kb + 824, the page number is 2, and the block number is 32 physical address = 32 * 4kb + 824 = 131896b. (2) The logical address is 12300 = 3 * 4kb + 12, the page number is 3, the page is found to be missing, and the page is missing.

Example: A user-programmed BAI memory has 32 pages of 1K per page and 16K main memory. Suppose that the system is the user's DAO page 0, 1, 3, and 10 at a certain time, and assign them to physical block numbers 5, 10, 4, and 7 respectively, and try to transform the virtual address 0a5ch into a physical address.

Please write out the analysis process.

000010b, i.e. the second page. Suppose that the corresponding physical block number of the second page of the virtual storage is 3, then the binary of three: 11b is concatenated to the address (ten bits) in front of the page to obtain the physical address:

b Please refer to it, I believe you will. If it can help you, if you are happy, please add a few more points. Thank you.

So choose A. [] is an idle partition.

This may be another problem with the system.

(1) Because the main memory capacity is 1m, because 2 20 = 1m, (2 10 = 1024 = 1k,), the main memory address needs to be represented by 20 bits.

2) There are 256 blocks in total, and the block size is the same as the page size. So there are 256 pages, so the size of each page is 1m 256 = (2 20) (2 8) = 2 12, so the length of each page is 12 bits.

Main storage address = page block number * block size + page address.

So the answer to the original question: (0 pages are assigned to 2 pages, that is, the page block number is 2, and the page block number of pages 1, 2, and 3 is 3, 1, 5).

Page No. Start Address.

0 2 * (2 12) + 0 = 8192 (this number is decimal).

4) Same as the third question.

Original question: Memory address.

I translated it, only provided the first question, and then calculated it myself.

Task 1 (4 points total).

A 32-bit paging storage management system on a virtual computer is used to manage its main memory (RAM), 1G in size. On this computer, all major memory is available for user processes (i.e., ignoring memory requirements for the operating system). A program requires an array of 1024 elements, each of which requires 200 memories.

To run this program in memory space, we need to use this measurement system for the task of array: 200 1024 = (2 2 20) 2 10 =2 2 30 =2 for this task: 1=2 10=1024,1=1 1=2 10 2 10 =2 20,1g=1 1=2 10 2 20 =2 30 to explain how to fit only one gram of physical memory in the memory requirements of a computer system.

Let's say the page size is 2 million, which is equal to the page size (this is a very large size to choose and make the calculation easier in this assigned task). In your explanation, you should address the following questions: The exact order in which you did not address them is as follows; As long as you solve all the problems.

Appropriate written requests. By reading the questions of your answers, there should be a basic understanding without reference to any other **. Simply answering each question with a few keys doesn't cause any markup.

1。Explain what a logical memory address is, what a physical memory address is, and how they relate to each other. [ 1 point].

2。What is a web page, a page, a page fault, and a page table? [ 1 point].

All in English, good bull fork question