1 3 x 3 Q x How much? A1: Don t go back

Actually, this is from the point of view of limits.

Another example: an arc is a straight line when its radius tends to infinity. You may be thinking, how can an arc become a straight line?

That's the limit, and it's not hard to understand. But if you think of it this way: the arc is part of the circle, then when the radius of the circle tends to infinity, the circle also becomes a straight line connected from end to end, which is even more difficult to understand.

First of all, how can straight lines be connected end to end? How can a circle become a straight line? Limits are like that, in the limit state, many things do not take on their original properties.

Let's have a chance to study the limits.

I don't know anything other than that.

Yes, from the point of view of limits, mathematical things are also moving forward in continuous negation, and when you learn more advanced mathematical theories, it will be even more suspenseful, hehe.

They all said, I'm talking about it seems to be levelless, in fact, mathematics is very interesting, and let me tell you one, in the whole real number, every natural number will have a corresponding even number to equivalent, abstract not??

y+z=1x=y+z

The limits of high school are hard to explain, and your own taste puts the problem in sending you by the way.

I understand why you can't answer 1 without adding a sign to the limit, and I don't know what to do with the fifth floor!

1 4 comes through the recipe.

The recipe process for x-x-7 4 0 is as follows:

x²-x-7/4＝0

x -x+1 4 2 (add 1 4 to both sides of the equation to form a perfect square) (x-1 2) =2 (write x -x+1 4 as a perfect square) x-1 2 = 2 (root numbers on both sides of the equation).

Get: x1=1 2-2

x2=1/2+√2

The sum of 2x 2 a 3x a 7 and 4x 2 + 1 is:

2x 2-3x-7)+(4x 2+1).

2x 2-3x-7)+(4x 2+1).

6x 2 a 3x a 6.

4(x-1)²-3

4(x-1)(x-1)-3

4(x²-x-x+1)-3

4x²-8x+4-3

4x²-8x+1

Hello questioner, about the formula of (x-1), there is a math book, the essence of which is the multiplication of (x-1) and (x-1).

You have unknowns, no other conditions, no equations, what do you ask?

The process of solving the problem and eliminating pants is as follows: take and touch Janex-1/5×x=2/3÷17/184/5×x=2/3×18/17x=2/3×18/17÷4/5x=12/17×5/4x=15/17

Solve the field cover: the equation is x -3x=-1, and it is x -3x+1=0, using the formula for finding the root cavity, x=(3 5) 2

1 4 comes through the recipe.

The recipe process for x-x-7 4 0 is as follows:

x²-x-7/4＝0

x -x+1 4 2 (add 1 4 to both sides of the equation to form a perfect square) (x-1 2) =2 (write x -x+1 4 as a perfect square) x-1 2 = 2 (root numbers on both sides of the equation).

Get: x1=1 2-2

x2=1/2+√2

limx→1x^3-1/x^2-1

limx 1[(x-1)(x 2+x+1)] x-1)(x+1)]=limx 1(x 2+x+1) (x+1) The process is supplemented by factoring, then decreasing, and then finding the limit.